Powershell: compare and match specific part of filename











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I have something want to use Powershell to write. Could anyone know it? Thanks.
I use powershell to create a list.
e.g.



$SUID = @("0011", "0012", "0013", "0014", "0015")



I have a folder containing log files:



0010Log201811151440.log
0012Log201811151440.log
0013Log201811151440.log
0017Log201811151440.log
0015Log201811151440.log


I want to use Powershell to determine SUID and files matching. Such as:



0011 = file is missing
0012 = 0012Log201811151440.log
0013 = 0013Log201811151440.log
0014 = file is missing
0015 = 0015Log201811151440.log









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    up vote
    0
    down vote

    favorite












    I have something want to use Powershell to write. Could anyone know it? Thanks.
    I use powershell to create a list.
    e.g.



    $SUID = @("0011", "0012", "0013", "0014", "0015")



    I have a folder containing log files:



    0010Log201811151440.log
    0012Log201811151440.log
    0013Log201811151440.log
    0017Log201811151440.log
    0015Log201811151440.log


    I want to use Powershell to determine SUID and files matching. Such as:



    0011 = file is missing
    0012 = 0012Log201811151440.log
    0013 = 0013Log201811151440.log
    0014 = file is missing
    0015 = 0015Log201811151440.log









    share|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have something want to use Powershell to write. Could anyone know it? Thanks.
      I use powershell to create a list.
      e.g.



      $SUID = @("0011", "0012", "0013", "0014", "0015")



      I have a folder containing log files:



      0010Log201811151440.log
      0012Log201811151440.log
      0013Log201811151440.log
      0017Log201811151440.log
      0015Log201811151440.log


      I want to use Powershell to determine SUID and files matching. Such as:



      0011 = file is missing
      0012 = 0012Log201811151440.log
      0013 = 0013Log201811151440.log
      0014 = file is missing
      0015 = 0015Log201811151440.log









      share|improve this question















      I have something want to use Powershell to write. Could anyone know it? Thanks.
      I use powershell to create a list.
      e.g.



      $SUID = @("0011", "0012", "0013", "0014", "0015")



      I have a folder containing log files:



      0010Log201811151440.log
      0012Log201811151440.log
      0013Log201811151440.log
      0017Log201811151440.log
      0015Log201811151440.log


      I want to use Powershell to determine SUID and files matching. Such as:



      0011 = file is missing
      0012 = 0012Log201811151440.log
      0013 = 0013Log201811151440.log
      0014 = file is missing
      0015 = 0015Log201811151440.log






      powershell script






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 22 at 7:06









      Aulis Ronkainen

      6151514




      6151514










      asked Nov 22 at 6:35









      user966127

      31




      31






















          1 Answer
          1






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          0
          down vote



          accepted










          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          $separator = "Log"
          $first = ($filename -split $separator)[0]
          $first





          share|improve this answer








          New contributor




          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.


















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30













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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote



          accepted










          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          $separator = "Log"
          $first = ($filename -split $separator)[0]
          $first





          share|improve this answer








          New contributor




          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.


















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30

















          up vote
          0
          down vote



          accepted










          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          $separator = "Log"
          $first = ($filename -split $separator)[0]
          $first





          share|improve this answer








          New contributor




          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.


















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30















          up vote
          0
          down vote



          accepted







          up vote
          0
          down vote



          accepted






          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          $separator = "Log"
          $first = ($filename -split $separator)[0]
          $first





          share|improve this answer








          New contributor




          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          You can use a split method to get the first part of the name:



          $filename = "0010Log201811151440.log"
          $separator = "Log"
          $first = ($filename -split $separator)[0]
          $first






          share|improve this answer








          New contributor




          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          share|improve this answer



          share|improve this answer






          New contributor




          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.









          answered Nov 22 at 10:03









          Xaero Walk

          16




          16




          New contributor




          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          New contributor





          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          Xaero Walk is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.












          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30




















          • Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
            – user966127
            Nov 23 at 3:30


















          Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
          – user966127
          Nov 23 at 3:30






          Dear Xaero Walk. Thanks, this is very useful to split first 4 number. I'm thinking how to split ~70 logs of filename and get first 4 number of each filename. Thanks. Best regards, Ken
          – user966127
          Nov 23 at 3:30




















           

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