Evaluating $int frac {3cos x}{(2sin x-5cos x)},dx$
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$$int dfrac {3cos x}{(2sin x-5cos x)},dx$$ I've been thinking and trying to work this out in quite a few ways: 1)Taking conjugate which actually complicates it further 2)Using half angle formula to convert the expression in terms of tan but I get 2 terms in the integration of which I'm unable to integrate 1 term because I can't seem to be able to make a suitable substitution. 3)Dividing throughout by $cos^2 x$ I find none of these methods to be effective. Please advice.
calculus integration
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edited Nov 22 at 14:58
StubbornAtom
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