Can an undirected graph be disconnected?











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This may be a rather trivial question but I am still trying to get the hang of all the graph theory terms. Nonetheless, I haven't found a source that explicitly says that an undirected graph can only be connected so is it possible to have an undirected graph that is disconnected? And if so, may I have an example one?



Much thanks!










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  • if they are made of separate pieces.
    – hbm
    Dec 4 at 23:30






  • 5




    Here's an example of (the diagram of) a disconnected undirected graph: $$huge ○,,,, ○$$
    – Git Gud
    Dec 4 at 23:30

















up vote
0
down vote

favorite












This may be a rather trivial question but I am still trying to get the hang of all the graph theory terms. Nonetheless, I haven't found a source that explicitly says that an undirected graph can only be connected so is it possible to have an undirected graph that is disconnected? And if so, may I have an example one?



Much thanks!










share|cite|improve this question
























  • if they are made of separate pieces.
    – hbm
    Dec 4 at 23:30






  • 5




    Here's an example of (the diagram of) a disconnected undirected graph: $$huge ○,,,, ○$$
    – Git Gud
    Dec 4 at 23:30















up vote
0
down vote

favorite









up vote
0
down vote

favorite











This may be a rather trivial question but I am still trying to get the hang of all the graph theory terms. Nonetheless, I haven't found a source that explicitly says that an undirected graph can only be connected so is it possible to have an undirected graph that is disconnected? And if so, may I have an example one?



Much thanks!










share|cite|improve this question















This may be a rather trivial question but I am still trying to get the hang of all the graph theory terms. Nonetheless, I haven't found a source that explicitly says that an undirected graph can only be connected so is it possible to have an undirected graph that is disconnected? And if so, may I have an example one?



Much thanks!







graph-theory connectedness directed-graphs






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edited Dec 4 at 23:42









Scientifica

6,33141333




6,33141333










asked Dec 4 at 23:23









DevAllanPer

1296




1296












  • if they are made of separate pieces.
    – hbm
    Dec 4 at 23:30






  • 5




    Here's an example of (the diagram of) a disconnected undirected graph: $$huge ○,,,, ○$$
    – Git Gud
    Dec 4 at 23:30




















  • if they are made of separate pieces.
    – hbm
    Dec 4 at 23:30






  • 5




    Here's an example of (the diagram of) a disconnected undirected graph: $$huge ○,,,, ○$$
    – Git Gud
    Dec 4 at 23:30


















if they are made of separate pieces.
– hbm
Dec 4 at 23:30




if they are made of separate pieces.
– hbm
Dec 4 at 23:30




5




5




Here's an example of (the diagram of) a disconnected undirected graph: $$huge ○,,,, ○$$
– Git Gud
Dec 4 at 23:30






Here's an example of (the diagram of) a disconnected undirected graph: $$huge ○,,,, ○$$
– Git Gud
Dec 4 at 23:30












4 Answers
4






active

oldest

votes

















up vote
7
down vote



accepted










Undirected just mean The edges does not have direction. connected means that there is a path from any vertex of the graph to any other vertex in the graph. so take any disconnected graph whose edges are not directed to give an example. following is one:
enter image description here






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    up vote
    4
    down vote













    Yes. The simplest such graph is just two vertices (no edges).






    share|cite|improve this answer




























      up vote
      2
      down vote













      The definition of graph that I know is the following: A graph consists of two sets $(V,E)$ where $V$ is the set of vertices and $E$ is the set of edges.



      The elements of $E$ are subsets (or multisets in the case of loops) of cardinality $2$ of $V$.



      A graph is undirected if ${x,y}={y,x}$ where ${x,y},{y,x}in E$ and it is directed if ${x,y}neq {y,x}$.



      Therefore, by taking $V={a,b,c}$ and $E={{a,b}}$, you obtain a disconnected undirected graph.






      share|cite|improve this answer




























        up vote
        1
        down vote













        I believe, since you can define a graph $G = (E,V)$ by its edge and vertex sets, it is perfectly ok to have a disconnected graph (i.e. a graph with no path between some vertices). In fact, taking $E$ to be empty still results in a graph.






        share|cite|improve this answer





















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          4 Answers
          4






          active

          oldest

          votes








          4 Answers
          4






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          7
          down vote



          accepted










          Undirected just mean The edges does not have direction. connected means that there is a path from any vertex of the graph to any other vertex in the graph. so take any disconnected graph whose edges are not directed to give an example. following is one:
          enter image description here






          share|cite|improve this answer

























            up vote
            7
            down vote



            accepted










            Undirected just mean The edges does not have direction. connected means that there is a path from any vertex of the graph to any other vertex in the graph. so take any disconnected graph whose edges are not directed to give an example. following is one:
            enter image description here






            share|cite|improve this answer























              up vote
              7
              down vote



              accepted







              up vote
              7
              down vote



              accepted






              Undirected just mean The edges does not have direction. connected means that there is a path from any vertex of the graph to any other vertex in the graph. so take any disconnected graph whose edges are not directed to give an example. following is one:
              enter image description here






              share|cite|improve this answer












              Undirected just mean The edges does not have direction. connected means that there is a path from any vertex of the graph to any other vertex in the graph. so take any disconnected graph whose edges are not directed to give an example. following is one:
              enter image description here







              share|cite|improve this answer












              share|cite|improve this answer



              share|cite|improve this answer










              answered Dec 4 at 23:32









              mathnoob

              1,691322




              1,691322






















                  up vote
                  4
                  down vote













                  Yes. The simplest such graph is just two vertices (no edges).






                  share|cite|improve this answer

























                    up vote
                    4
                    down vote













                    Yes. The simplest such graph is just two vertices (no edges).






                    share|cite|improve this answer























                      up vote
                      4
                      down vote










                      up vote
                      4
                      down vote









                      Yes. The simplest such graph is just two vertices (no edges).






                      share|cite|improve this answer












                      Yes. The simplest such graph is just two vertices (no edges).







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered Dec 4 at 23:30









                      platty

                      3,305320




                      3,305320






















                          up vote
                          2
                          down vote













                          The definition of graph that I know is the following: A graph consists of two sets $(V,E)$ where $V$ is the set of vertices and $E$ is the set of edges.



                          The elements of $E$ are subsets (or multisets in the case of loops) of cardinality $2$ of $V$.



                          A graph is undirected if ${x,y}={y,x}$ where ${x,y},{y,x}in E$ and it is directed if ${x,y}neq {y,x}$.



                          Therefore, by taking $V={a,b,c}$ and $E={{a,b}}$, you obtain a disconnected undirected graph.






                          share|cite|improve this answer

























                            up vote
                            2
                            down vote













                            The definition of graph that I know is the following: A graph consists of two sets $(V,E)$ where $V$ is the set of vertices and $E$ is the set of edges.



                            The elements of $E$ are subsets (or multisets in the case of loops) of cardinality $2$ of $V$.



                            A graph is undirected if ${x,y}={y,x}$ where ${x,y},{y,x}in E$ and it is directed if ${x,y}neq {y,x}$.



                            Therefore, by taking $V={a,b,c}$ and $E={{a,b}}$, you obtain a disconnected undirected graph.






                            share|cite|improve this answer























                              up vote
                              2
                              down vote










                              up vote
                              2
                              down vote









                              The definition of graph that I know is the following: A graph consists of two sets $(V,E)$ where $V$ is the set of vertices and $E$ is the set of edges.



                              The elements of $E$ are subsets (or multisets in the case of loops) of cardinality $2$ of $V$.



                              A graph is undirected if ${x,y}={y,x}$ where ${x,y},{y,x}in E$ and it is directed if ${x,y}neq {y,x}$.



                              Therefore, by taking $V={a,b,c}$ and $E={{a,b}}$, you obtain a disconnected undirected graph.






                              share|cite|improve this answer












                              The definition of graph that I know is the following: A graph consists of two sets $(V,E)$ where $V$ is the set of vertices and $E$ is the set of edges.



                              The elements of $E$ are subsets (or multisets in the case of loops) of cardinality $2$ of $V$.



                              A graph is undirected if ${x,y}={y,x}$ where ${x,y},{y,x}in E$ and it is directed if ${x,y}neq {y,x}$.



                              Therefore, by taking $V={a,b,c}$ and $E={{a,b}}$, you obtain a disconnected undirected graph.







                              share|cite|improve this answer












                              share|cite|improve this answer



                              share|cite|improve this answer










                              answered Dec 4 at 23:31









                              Karen

                              855




                              855






















                                  up vote
                                  1
                                  down vote













                                  I believe, since you can define a graph $G = (E,V)$ by its edge and vertex sets, it is perfectly ok to have a disconnected graph (i.e. a graph with no path between some vertices). In fact, taking $E$ to be empty still results in a graph.






                                  share|cite|improve this answer

























                                    up vote
                                    1
                                    down vote













                                    I believe, since you can define a graph $G = (E,V)$ by its edge and vertex sets, it is perfectly ok to have a disconnected graph (i.e. a graph with no path between some vertices). In fact, taking $E$ to be empty still results in a graph.






                                    share|cite|improve this answer























                                      up vote
                                      1
                                      down vote










                                      up vote
                                      1
                                      down vote









                                      I believe, since you can define a graph $G = (E,V)$ by its edge and vertex sets, it is perfectly ok to have a disconnected graph (i.e. a graph with no path between some vertices). In fact, taking $E$ to be empty still results in a graph.






                                      share|cite|improve this answer












                                      I believe, since you can define a graph $G = (E,V)$ by its edge and vertex sets, it is perfectly ok to have a disconnected graph (i.e. a graph with no path between some vertices). In fact, taking $E$ to be empty still results in a graph.







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered Dec 4 at 23:32









                                      Stuartg98

                                      586




                                      586






























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