Steps used to solve this riccati differential equation?












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I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:



$$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$



to solve it, they first rearrange it as



$$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$



and then state (without working or explanation) that this gives



$$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$



And I'm unsure how to get from one to the other.



Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?










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    0












    $begingroup$


    I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:



    $$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$



    to solve it, they first rearrange it as



    $$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$



    and then state (without working or explanation) that this gives



    $$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$



    And I'm unsure how to get from one to the other.



    Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:



      $$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$



      to solve it, they first rearrange it as



      $$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$



      and then state (without working or explanation) that this gives



      $$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$



      And I'm unsure how to get from one to the other.



      Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?










      share|cite|improve this question









      $endgroup$




      I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:



      $$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$



      to solve it, they first rearrange it as



      $$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$



      and then state (without working or explanation) that this gives



      $$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$



      And I'm unsure how to get from one to the other.



      Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?







      ordinary-differential-equations self-learning






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      asked Dec 22 '18 at 6:15









      XiaomiXiaomi

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          $begingroup$

          Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
          $$
          frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
          $$

          which after integration and determination of the integration constant should give your solution form.






          share|cite|improve this answer









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            1 Answer
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            1 Answer
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            active

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            1












            $begingroup$

            Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
            $$
            frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
            $$

            which after integration and determination of the integration constant should give your solution form.






            share|cite|improve this answer









            $endgroup$


















              1












              $begingroup$

              Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
              $$
              frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
              $$

              which after integration and determination of the integration constant should give your solution form.






              share|cite|improve this answer









              $endgroup$
















                1












                1








                1





                $begingroup$

                Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
                $$
                frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
                $$

                which after integration and determination of the integration constant should give your solution form.






                share|cite|improve this answer









                $endgroup$



                Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
                $$
                frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
                $$

                which after integration and determination of the integration constant should give your solution form.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 22 '18 at 7:06









                LutzLLutzL

                59.3k42057




                59.3k42057






























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