Steps used to solve this riccati differential equation?
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I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:
$$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$
to solve it, they first rearrange it as
$$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$
and then state (without working or explanation) that this gives
$$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$
And I'm unsure how to get from one to the other.
Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?
ordinary-differential-equations self-learning
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I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:
$$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$
to solve it, they first rearrange it as
$$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$
and then state (without working or explanation) that this gives
$$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$
And I'm unsure how to get from one to the other.
Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?
ordinary-differential-equations self-learning
$endgroup$
add a comment |
$begingroup$
I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:
$$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$
to solve it, they first rearrange it as
$$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$
and then state (without working or explanation) that this gives
$$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$
And I'm unsure how to get from one to the other.
Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?
ordinary-differential-equations self-learning
$endgroup$
I am reading through examples of linear filtering problems for SDE's, and the process first requires solving a (deterministic) riccati differential equation. In one of the examples, this is given by:
$$frac{dS_t}{dt} = frac{-1}{m^2}S^2_t + c^2$$
to solve it, they first rearrange it as
$$frac{m^2 dS_t}{m^2 c^2 -S^2_t} = dt$$
and then state (without working or explanation) that this gives
$$left| frac{mc+S_t}{mc-S_t} right|= left| frac{mc+a^2}{mc-a^2} right| exp left( frac{2ct}{m} right)$$
And I'm unsure how to get from one to the other.
Clearly, since $t$ has emerged, it involves integrating both sides. But besides that I'm lost. Could someone explain this or give some steps/outline for me to do myself?
ordinary-differential-equations self-learning
ordinary-differential-equations self-learning
asked Dec 22 '18 at 6:15
XiaomiXiaomi
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1,066115
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Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
$$
frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
$$
which after integration and determination of the integration constant should give your solution form.
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1 Answer
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1 Answer
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active
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$begingroup$
Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
$$
frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
$$
which after integration and determination of the integration constant should give your solution form.
$endgroup$
add a comment |
$begingroup$
Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
$$
frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
$$
which after integration and determination of the integration constant should give your solution form.
$endgroup$
add a comment |
$begingroup$
Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
$$
frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
$$
which after integration and determination of the integration constant should give your solution form.
$endgroup$
Don't see this as Riccati equation, see it as separable ODE with constant solutions at $pm mc$. Then the last form has a partial fraction decomposition
$$
frac{mdS}{S+mc}-frac{mdS}{S-mc} = 2cdt
$$
which after integration and determination of the integration constant should give your solution form.
answered Dec 22 '18 at 7:06
LutzLLutzL
59.3k42057
59.3k42057
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