Quotient of finite, nilpotent group by Frattini subgroup is isomorphic to product of quotients of Sylow...












0












$begingroup$


Let $G$ be a finite nilpotent group.



We know that $G=G_{p_1}times G_{p_2}times cdots times G_{p_r}$ where $G_{p_i}in Syl_{p_i}(G)$, $i=1,dots,r$.



Is the following equation right? And why?



$G/Phi(G)=G_{p_1}/Phi(G_{p_1})timescdotstimes G_{p_r}/Phi(G_{p_r})$,



where $Phi(G)$ is the Frattini subgroup of $G$.










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$endgroup$








  • 1




    $begingroup$
    What's $Phi(G)$? Frattini subgroup?
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:42










  • $begingroup$
    @Lord Shark the Unknown Yes!
    $endgroup$
    – Qin
    Jul 26 '18 at 9:43






  • 1




    $begingroup$
    The Frattini subgroup satisfies $Phi(H_1times H_2)=Phi(H_1)timesPhi(H_2)$ so then $(H_1times H_2)/Phi(H_1times H_2)=H_1/Phi(H_1)times H_2/Phi(H_2)$ etc.
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:49








  • 2




    $begingroup$
    Yes: An "n" is missing.
    $endgroup$
    – Christian Blatter
    Jul 26 '18 at 10:08
















0












$begingroup$


Let $G$ be a finite nilpotent group.



We know that $G=G_{p_1}times G_{p_2}times cdots times G_{p_r}$ where $G_{p_i}in Syl_{p_i}(G)$, $i=1,dots,r$.



Is the following equation right? And why?



$G/Phi(G)=G_{p_1}/Phi(G_{p_1})timescdotstimes G_{p_r}/Phi(G_{p_r})$,



where $Phi(G)$ is the Frattini subgroup of $G$.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    What's $Phi(G)$? Frattini subgroup?
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:42










  • $begingroup$
    @Lord Shark the Unknown Yes!
    $endgroup$
    – Qin
    Jul 26 '18 at 9:43






  • 1




    $begingroup$
    The Frattini subgroup satisfies $Phi(H_1times H_2)=Phi(H_1)timesPhi(H_2)$ so then $(H_1times H_2)/Phi(H_1times H_2)=H_1/Phi(H_1)times H_2/Phi(H_2)$ etc.
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:49








  • 2




    $begingroup$
    Yes: An "n" is missing.
    $endgroup$
    – Christian Blatter
    Jul 26 '18 at 10:08














0












0








0





$begingroup$


Let $G$ be a finite nilpotent group.



We know that $G=G_{p_1}times G_{p_2}times cdots times G_{p_r}$ where $G_{p_i}in Syl_{p_i}(G)$, $i=1,dots,r$.



Is the following equation right? And why?



$G/Phi(G)=G_{p_1}/Phi(G_{p_1})timescdotstimes G_{p_r}/Phi(G_{p_r})$,



where $Phi(G)$ is the Frattini subgroup of $G$.










share|cite|improve this question











$endgroup$




Let $G$ be a finite nilpotent group.



We know that $G=G_{p_1}times G_{p_2}times cdots times G_{p_r}$ where $G_{p_i}in Syl_{p_i}(G)$, $i=1,dots,r$.



Is the following equation right? And why?



$G/Phi(G)=G_{p_1}/Phi(G_{p_1})timescdotstimes G_{p_r}/Phi(G_{p_r})$,



where $Phi(G)$ is the Frattini subgroup of $G$.







finite-groups group-isomorphism sylow-theory direct-product nilpotent-groups






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 22 '18 at 4:43









Shaun

9,380113684




9,380113684










asked Jul 26 '18 at 9:38









QinQin

200117




200117








  • 1




    $begingroup$
    What's $Phi(G)$? Frattini subgroup?
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:42










  • $begingroup$
    @Lord Shark the Unknown Yes!
    $endgroup$
    – Qin
    Jul 26 '18 at 9:43






  • 1




    $begingroup$
    The Frattini subgroup satisfies $Phi(H_1times H_2)=Phi(H_1)timesPhi(H_2)$ so then $(H_1times H_2)/Phi(H_1times H_2)=H_1/Phi(H_1)times H_2/Phi(H_2)$ etc.
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:49








  • 2




    $begingroup$
    Yes: An "n" is missing.
    $endgroup$
    – Christian Blatter
    Jul 26 '18 at 10:08














  • 1




    $begingroup$
    What's $Phi(G)$? Frattini subgroup?
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:42










  • $begingroup$
    @Lord Shark the Unknown Yes!
    $endgroup$
    – Qin
    Jul 26 '18 at 9:43






  • 1




    $begingroup$
    The Frattini subgroup satisfies $Phi(H_1times H_2)=Phi(H_1)timesPhi(H_2)$ so then $(H_1times H_2)/Phi(H_1times H_2)=H_1/Phi(H_1)times H_2/Phi(H_2)$ etc.
    $endgroup$
    – Lord Shark the Unknown
    Jul 26 '18 at 9:49








  • 2




    $begingroup$
    Yes: An "n" is missing.
    $endgroup$
    – Christian Blatter
    Jul 26 '18 at 10:08








1




1




$begingroup$
What's $Phi(G)$? Frattini subgroup?
$endgroup$
– Lord Shark the Unknown
Jul 26 '18 at 9:42




$begingroup$
What's $Phi(G)$? Frattini subgroup?
$endgroup$
– Lord Shark the Unknown
Jul 26 '18 at 9:42












$begingroup$
@Lord Shark the Unknown Yes!
$endgroup$
– Qin
Jul 26 '18 at 9:43




$begingroup$
@Lord Shark the Unknown Yes!
$endgroup$
– Qin
Jul 26 '18 at 9:43




1




1




$begingroup$
The Frattini subgroup satisfies $Phi(H_1times H_2)=Phi(H_1)timesPhi(H_2)$ so then $(H_1times H_2)/Phi(H_1times H_2)=H_1/Phi(H_1)times H_2/Phi(H_2)$ etc.
$endgroup$
– Lord Shark the Unknown
Jul 26 '18 at 9:49






$begingroup$
The Frattini subgroup satisfies $Phi(H_1times H_2)=Phi(H_1)timesPhi(H_2)$ so then $(H_1times H_2)/Phi(H_1times H_2)=H_1/Phi(H_1)times H_2/Phi(H_2)$ etc.
$endgroup$
– Lord Shark the Unknown
Jul 26 '18 at 9:49






2




2




$begingroup$
Yes: An "n" is missing.
$endgroup$
– Christian Blatter
Jul 26 '18 at 10:08




$begingroup$
Yes: An "n" is missing.
$endgroup$
– Christian Blatter
Jul 26 '18 at 10:08










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