Speed, Distance and Time [closed]
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Josh cycles 2 km at y km/h and then runs 4 km at (y-4) km/h. The whole journey takes 40 min.
Write an equation in y and show that it simplifies to $y^2$ – 13y + 12 = 0
problem-solving
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closed as off-topic by Saad, Toby Mak, verret, Alexander Gruber♦ Jan 8 at 22:08
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Josh cycles 2 km at y km/h and then runs 4 km at (y-4) km/h. The whole journey takes 40 min.
Write an equation in y and show that it simplifies to $y^2$ – 13y + 12 = 0
problem-solving
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closed as off-topic by Saad, Toby Mak, verret, Alexander Gruber♦ Jan 8 at 22:08
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Toby Mak, verret, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
2
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so what have you tried? where are you stuck?
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– Siong Thye Goh
Jan 8 at 12:19
add a comment |
$begingroup$
Josh cycles 2 km at y km/h and then runs 4 km at (y-4) km/h. The whole journey takes 40 min.
Write an equation in y and show that it simplifies to $y^2$ – 13y + 12 = 0
problem-solving
$endgroup$
Josh cycles 2 km at y km/h and then runs 4 km at (y-4) km/h. The whole journey takes 40 min.
Write an equation in y and show that it simplifies to $y^2$ – 13y + 12 = 0
problem-solving
problem-solving
asked Jan 8 at 12:17
Good aeksiGood aeksi
11
11
closed as off-topic by Saad, Toby Mak, verret, Alexander Gruber♦ Jan 8 at 22:08
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Toby Mak, verret, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Saad, Toby Mak, verret, Alexander Gruber♦ Jan 8 at 22:08
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Toby Mak, verret, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
2
$begingroup$
so what have you tried? where are you stuck?
$endgroup$
– Siong Thye Goh
Jan 8 at 12:19
add a comment |
2
$begingroup$
so what have you tried? where are you stuck?
$endgroup$
– Siong Thye Goh
Jan 8 at 12:19
2
2
$begingroup$
so what have you tried? where are you stuck?
$endgroup$
– Siong Thye Goh
Jan 8 at 12:19
$begingroup$
so what have you tried? where are you stuck?
$endgroup$
– Siong Thye Goh
Jan 8 at 12:19
add a comment |
1 Answer
1
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Some hints:
- The velocities are given in $frac{km}{h}$. So, you may convert the total time to hours: $T = 40,min = frac{2}{3}h$.
- Split the overall time $T = t_1 + t_2$ into two parts and use $t = frac{mbox{distance}}{mbox{velocity}}$.
- For example, for the second part of the journey you get $t_2 = frac{4}{y-4}$.
Can you take it from here?
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Some hints:
- The velocities are given in $frac{km}{h}$. So, you may convert the total time to hours: $T = 40,min = frac{2}{3}h$.
- Split the overall time $T = t_1 + t_2$ into two parts and use $t = frac{mbox{distance}}{mbox{velocity}}$.
- For example, for the second part of the journey you get $t_2 = frac{4}{y-4}$.
Can you take it from here?
$endgroup$
add a comment |
$begingroup$
Some hints:
- The velocities are given in $frac{km}{h}$. So, you may convert the total time to hours: $T = 40,min = frac{2}{3}h$.
- Split the overall time $T = t_1 + t_2$ into two parts and use $t = frac{mbox{distance}}{mbox{velocity}}$.
- For example, for the second part of the journey you get $t_2 = frac{4}{y-4}$.
Can you take it from here?
$endgroup$
add a comment |
$begingroup$
Some hints:
- The velocities are given in $frac{km}{h}$. So, you may convert the total time to hours: $T = 40,min = frac{2}{3}h$.
- Split the overall time $T = t_1 + t_2$ into two parts and use $t = frac{mbox{distance}}{mbox{velocity}}$.
- For example, for the second part of the journey you get $t_2 = frac{4}{y-4}$.
Can you take it from here?
$endgroup$
Some hints:
- The velocities are given in $frac{km}{h}$. So, you may convert the total time to hours: $T = 40,min = frac{2}{3}h$.
- Split the overall time $T = t_1 + t_2$ into two parts and use $t = frac{mbox{distance}}{mbox{velocity}}$.
- For example, for the second part of the journey you get $t_2 = frac{4}{y-4}$.
Can you take it from here?
answered Jan 8 at 12:44
trancelocationtrancelocation
14.1k1829
14.1k1829
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add a comment |
2
$begingroup$
so what have you tried? where are you stuck?
$endgroup$
– Siong Thye Goh
Jan 8 at 12:19