Excel Formula to figure out number of bits required to finish the last octet of a subnet mask












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my Business Applications professor gave us a question where we have an IP Address (160.35.128.93) and we have to use a formula to figure out what the required number of bits is required for the last octet of the IP Address and we have to make sure the number is rounded up. For example, his answer is that there are 6 required bits. The formula I'm using right now is IMLOG2(number_of_subnets+2) but after an hour of trying, I can't seem to get the right answer. Help would greatly appreciated.










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  • The question you were given makes no sense. The subnet mask does not depend on the address to such precision; it could go all the way from e.g. /2 or /4 up to /30 or /31.

    – grawity
    Feb 8 at 20:02













  • To make sure that I didn't mess it up, here's the question word for word:

    – SmartphoneUser
    Feb 8 at 20:07











  • 2. The formula to calculate the number of bits we require in the last octet for the subnet is Log2(number_of_subnets+2). Determine the function you need to use to find the number of bits we use to finish the subnet mask.

    – SmartphoneUser
    Feb 8 at 20:08











  • It is better to edit your question instead of adding information in comments. You have the formula, where is the problem exactly?

    – cybernetic.nomad
    Feb 8 at 21:11











  • Just use =LOG((num of subnets + 2),2). I don't think you have a complex number your dealing with.

    – Brian
    Feb 8 at 22:45


















0















my Business Applications professor gave us a question where we have an IP Address (160.35.128.93) and we have to use a formula to figure out what the required number of bits is required for the last octet of the IP Address and we have to make sure the number is rounded up. For example, his answer is that there are 6 required bits. The formula I'm using right now is IMLOG2(number_of_subnets+2) but after an hour of trying, I can't seem to get the right answer. Help would greatly appreciated.










share|improve this question























  • The question you were given makes no sense. The subnet mask does not depend on the address to such precision; it could go all the way from e.g. /2 or /4 up to /30 or /31.

    – grawity
    Feb 8 at 20:02













  • To make sure that I didn't mess it up, here's the question word for word:

    – SmartphoneUser
    Feb 8 at 20:07











  • 2. The formula to calculate the number of bits we require in the last octet for the subnet is Log2(number_of_subnets+2). Determine the function you need to use to find the number of bits we use to finish the subnet mask.

    – SmartphoneUser
    Feb 8 at 20:08











  • It is better to edit your question instead of adding information in comments. You have the formula, where is the problem exactly?

    – cybernetic.nomad
    Feb 8 at 21:11











  • Just use =LOG((num of subnets + 2),2). I don't think you have a complex number your dealing with.

    – Brian
    Feb 8 at 22:45
















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0








0








my Business Applications professor gave us a question where we have an IP Address (160.35.128.93) and we have to use a formula to figure out what the required number of bits is required for the last octet of the IP Address and we have to make sure the number is rounded up. For example, his answer is that there are 6 required bits. The formula I'm using right now is IMLOG2(number_of_subnets+2) but after an hour of trying, I can't seem to get the right answer. Help would greatly appreciated.










share|improve this question














my Business Applications professor gave us a question where we have an IP Address (160.35.128.93) and we have to use a formula to figure out what the required number of bits is required for the last octet of the IP Address and we have to make sure the number is rounded up. For example, his answer is that there are 6 required bits. The formula I'm using right now is IMLOG2(number_of_subnets+2) but after an hour of trying, I can't seem to get the right answer. Help would greatly appreciated.







microsoft-excel






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share|improve this question











share|improve this question




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asked Feb 8 at 19:53









SmartphoneUser SmartphoneUser

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163













  • The question you were given makes no sense. The subnet mask does not depend on the address to such precision; it could go all the way from e.g. /2 or /4 up to /30 or /31.

    – grawity
    Feb 8 at 20:02













  • To make sure that I didn't mess it up, here's the question word for word:

    – SmartphoneUser
    Feb 8 at 20:07











  • 2. The formula to calculate the number of bits we require in the last octet for the subnet is Log2(number_of_subnets+2). Determine the function you need to use to find the number of bits we use to finish the subnet mask.

    – SmartphoneUser
    Feb 8 at 20:08











  • It is better to edit your question instead of adding information in comments. You have the formula, where is the problem exactly?

    – cybernetic.nomad
    Feb 8 at 21:11











  • Just use =LOG((num of subnets + 2),2). I don't think you have a complex number your dealing with.

    – Brian
    Feb 8 at 22:45





















  • The question you were given makes no sense. The subnet mask does not depend on the address to such precision; it could go all the way from e.g. /2 or /4 up to /30 or /31.

    – grawity
    Feb 8 at 20:02













  • To make sure that I didn't mess it up, here's the question word for word:

    – SmartphoneUser
    Feb 8 at 20:07











  • 2. The formula to calculate the number of bits we require in the last octet for the subnet is Log2(number_of_subnets+2). Determine the function you need to use to find the number of bits we use to finish the subnet mask.

    – SmartphoneUser
    Feb 8 at 20:08











  • It is better to edit your question instead of adding information in comments. You have the formula, where is the problem exactly?

    – cybernetic.nomad
    Feb 8 at 21:11











  • Just use =LOG((num of subnets + 2),2). I don't think you have a complex number your dealing with.

    – Brian
    Feb 8 at 22:45



















The question you were given makes no sense. The subnet mask does not depend on the address to such precision; it could go all the way from e.g. /2 or /4 up to /30 or /31.

– grawity
Feb 8 at 20:02







The question you were given makes no sense. The subnet mask does not depend on the address to such precision; it could go all the way from e.g. /2 or /4 up to /30 or /31.

– grawity
Feb 8 at 20:02















To make sure that I didn't mess it up, here's the question word for word:

– SmartphoneUser
Feb 8 at 20:07





To make sure that I didn't mess it up, here's the question word for word:

– SmartphoneUser
Feb 8 at 20:07













2. The formula to calculate the number of bits we require in the last octet for the subnet is Log2(number_of_subnets+2). Determine the function you need to use to find the number of bits we use to finish the subnet mask.

– SmartphoneUser
Feb 8 at 20:08





2. The formula to calculate the number of bits we require in the last octet for the subnet is Log2(number_of_subnets+2). Determine the function you need to use to find the number of bits we use to finish the subnet mask.

– SmartphoneUser
Feb 8 at 20:08













It is better to edit your question instead of adding information in comments. You have the formula, where is the problem exactly?

– cybernetic.nomad
Feb 8 at 21:11





It is better to edit your question instead of adding information in comments. You have the formula, where is the problem exactly?

– cybernetic.nomad
Feb 8 at 21:11













Just use =LOG((num of subnets + 2),2). I don't think you have a complex number your dealing with.

– Brian
Feb 8 at 22:45







Just use =LOG((num of subnets + 2),2). I don't think you have a complex number your dealing with.

– Brian
Feb 8 at 22:45












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