From direction cosine matrix to Cardan angles - Two different Matlab codes, different results












0












$begingroup$


I have two Matlab codes to get the Cardan angles (ZXY sequence) starting from a given direction cosine matrix (dcm), but the results are different. Why?



The dcm is:



dcm = [0.5972   -0.7833   0.1729;
0.7990 0.5987 -0.0553;
-0.0592 0.1719 0.9832];


First code (alpha=angle around x, beta=angle around y, gamma=angle around z):



[gamma, alpha, beta] = dcm2angle(dcm,'ZXY');
% Result:
% -0.9277 -0.0553 -0.1741


Second code:



if abs(dcm(3,2)) ~= 1
alpha = asin(dcm(3,2));
%
if dcm(3,3) >= 0
beta = asin(-dcm(3,1)/cos(alpha));
else
beta = pi - asin(-dcm(3,1)/cos(alpha));
end
%
if dcm(2,2) >= 0
gamma = asin(-dcm(1,2)/cos(alpha));
else
gamma = pi - asin(-dcm(1,2)/cos(alpha));
end
end
% Result:
% 0.9192 0.1728 0.0601


The dcm for the sequence ZXY in terms of sin and cos is:



enter image description here



Thank you so much for your willingness.










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$endgroup$












  • $begingroup$
    Just to check, apply also both methods on the transpose of the dcm matrix.
    $endgroup$
    – LutzL
    Dec 23 '18 at 8:44










  • $begingroup$
    You can get the beta and gamma values with less lines using beta = atan2(-dcm(3,1), dcm(3,3) and gamma = atan2(-dcm(1,2), dcm(2,2)).
    $endgroup$
    – LutzL
    Dec 23 '18 at 12:19










  • $begingroup$
    Hello @LutzL, I have to use the above code because my professor said that I have to implement the analitic procedure in my book. Anyway thank you for your suggestion and sorry for the delay of my reply.
    $endgroup$
    – Gennaro Arguzzi
    Dec 24 '18 at 23:55
















0












$begingroup$


I have two Matlab codes to get the Cardan angles (ZXY sequence) starting from a given direction cosine matrix (dcm), but the results are different. Why?



The dcm is:



dcm = [0.5972   -0.7833   0.1729;
0.7990 0.5987 -0.0553;
-0.0592 0.1719 0.9832];


First code (alpha=angle around x, beta=angle around y, gamma=angle around z):



[gamma, alpha, beta] = dcm2angle(dcm,'ZXY');
% Result:
% -0.9277 -0.0553 -0.1741


Second code:



if abs(dcm(3,2)) ~= 1
alpha = asin(dcm(3,2));
%
if dcm(3,3) >= 0
beta = asin(-dcm(3,1)/cos(alpha));
else
beta = pi - asin(-dcm(3,1)/cos(alpha));
end
%
if dcm(2,2) >= 0
gamma = asin(-dcm(1,2)/cos(alpha));
else
gamma = pi - asin(-dcm(1,2)/cos(alpha));
end
end
% Result:
% 0.9192 0.1728 0.0601


The dcm for the sequence ZXY in terms of sin and cos is:



enter image description here



Thank you so much for your willingness.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Just to check, apply also both methods on the transpose of the dcm matrix.
    $endgroup$
    – LutzL
    Dec 23 '18 at 8:44










  • $begingroup$
    You can get the beta and gamma values with less lines using beta = atan2(-dcm(3,1), dcm(3,3) and gamma = atan2(-dcm(1,2), dcm(2,2)).
    $endgroup$
    – LutzL
    Dec 23 '18 at 12:19










  • $begingroup$
    Hello @LutzL, I have to use the above code because my professor said that I have to implement the analitic procedure in my book. Anyway thank you for your suggestion and sorry for the delay of my reply.
    $endgroup$
    – Gennaro Arguzzi
    Dec 24 '18 at 23:55














0












0








0





$begingroup$


I have two Matlab codes to get the Cardan angles (ZXY sequence) starting from a given direction cosine matrix (dcm), but the results are different. Why?



The dcm is:



dcm = [0.5972   -0.7833   0.1729;
0.7990 0.5987 -0.0553;
-0.0592 0.1719 0.9832];


First code (alpha=angle around x, beta=angle around y, gamma=angle around z):



[gamma, alpha, beta] = dcm2angle(dcm,'ZXY');
% Result:
% -0.9277 -0.0553 -0.1741


Second code:



if abs(dcm(3,2)) ~= 1
alpha = asin(dcm(3,2));
%
if dcm(3,3) >= 0
beta = asin(-dcm(3,1)/cos(alpha));
else
beta = pi - asin(-dcm(3,1)/cos(alpha));
end
%
if dcm(2,2) >= 0
gamma = asin(-dcm(1,2)/cos(alpha));
else
gamma = pi - asin(-dcm(1,2)/cos(alpha));
end
end
% Result:
% 0.9192 0.1728 0.0601


The dcm for the sequence ZXY in terms of sin and cos is:



enter image description here



Thank you so much for your willingness.










share|cite|improve this question











$endgroup$




I have two Matlab codes to get the Cardan angles (ZXY sequence) starting from a given direction cosine matrix (dcm), but the results are different. Why?



The dcm is:



dcm = [0.5972   -0.7833   0.1729;
0.7990 0.5987 -0.0553;
-0.0592 0.1719 0.9832];


First code (alpha=angle around x, beta=angle around y, gamma=angle around z):



[gamma, alpha, beta] = dcm2angle(dcm,'ZXY');
% Result:
% -0.9277 -0.0553 -0.1741


Second code:



if abs(dcm(3,2)) ~= 1
alpha = asin(dcm(3,2));
%
if dcm(3,3) >= 0
beta = asin(-dcm(3,1)/cos(alpha));
else
beta = pi - asin(-dcm(3,1)/cos(alpha));
end
%
if dcm(2,2) >= 0
gamma = asin(-dcm(1,2)/cos(alpha));
else
gamma = pi - asin(-dcm(1,2)/cos(alpha));
end
end
% Result:
% 0.9192 0.1728 0.0601


The dcm for the sequence ZXY in terms of sin and cos is:



enter image description here



Thank you so much for your willingness.







matrices matlab education rotations classical-mechanics






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edited Dec 23 '18 at 8:05







Gennaro Arguzzi

















asked Dec 22 '18 at 17:20









Gennaro ArguzziGennaro Arguzzi

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  • $begingroup$
    Just to check, apply also both methods on the transpose of the dcm matrix.
    $endgroup$
    – LutzL
    Dec 23 '18 at 8:44










  • $begingroup$
    You can get the beta and gamma values with less lines using beta = atan2(-dcm(3,1), dcm(3,3) and gamma = atan2(-dcm(1,2), dcm(2,2)).
    $endgroup$
    – LutzL
    Dec 23 '18 at 12:19










  • $begingroup$
    Hello @LutzL, I have to use the above code because my professor said that I have to implement the analitic procedure in my book. Anyway thank you for your suggestion and sorry for the delay of my reply.
    $endgroup$
    – Gennaro Arguzzi
    Dec 24 '18 at 23:55


















  • $begingroup$
    Just to check, apply also both methods on the transpose of the dcm matrix.
    $endgroup$
    – LutzL
    Dec 23 '18 at 8:44










  • $begingroup$
    You can get the beta and gamma values with less lines using beta = atan2(-dcm(3,1), dcm(3,3) and gamma = atan2(-dcm(1,2), dcm(2,2)).
    $endgroup$
    – LutzL
    Dec 23 '18 at 12:19










  • $begingroup$
    Hello @LutzL, I have to use the above code because my professor said that I have to implement the analitic procedure in my book. Anyway thank you for your suggestion and sorry for the delay of my reply.
    $endgroup$
    – Gennaro Arguzzi
    Dec 24 '18 at 23:55
















$begingroup$
Just to check, apply also both methods on the transpose of the dcm matrix.
$endgroup$
– LutzL
Dec 23 '18 at 8:44




$begingroup$
Just to check, apply also both methods on the transpose of the dcm matrix.
$endgroup$
– LutzL
Dec 23 '18 at 8:44












$begingroup$
You can get the beta and gamma values with less lines using beta = atan2(-dcm(3,1), dcm(3,3) and gamma = atan2(-dcm(1,2), dcm(2,2)).
$endgroup$
– LutzL
Dec 23 '18 at 12:19




$begingroup$
You can get the beta and gamma values with less lines using beta = atan2(-dcm(3,1), dcm(3,3) and gamma = atan2(-dcm(1,2), dcm(2,2)).
$endgroup$
– LutzL
Dec 23 '18 at 12:19












$begingroup$
Hello @LutzL, I have to use the above code because my professor said that I have to implement the analitic procedure in my book. Anyway thank you for your suggestion and sorry for the delay of my reply.
$endgroup$
– Gennaro Arguzzi
Dec 24 '18 at 23:55




$begingroup$
Hello @LutzL, I have to use the above code because my professor said that I have to implement the analitic procedure in my book. Anyway thank you for your suggestion and sorry for the delay of my reply.
$endgroup$
– Gennaro Arguzzi
Dec 24 '18 at 23:55










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