Is sigmoid function distributive
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Sigmoid function is defined as $frac{1}{1+e^{-(x+y)}}$.
Is there a property for sigmoid such that
$frac{1}{1+e^{-(x+y)}}=$ sigmoid$(x)$ {some operation} sigmoid$(y)$ ?
functions
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Sigmoid function is defined as $frac{1}{1+e^{-(x+y)}}$.
Is there a property for sigmoid such that
$frac{1}{1+e^{-(x+y)}}=$ sigmoid$(x)$ {some operation} sigmoid$(y)$ ?
functions
add a comment |
up vote
1
down vote
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up vote
1
down vote
favorite
Sigmoid function is defined as $frac{1}{1+e^{-(x+y)}}$.
Is there a property for sigmoid such that
$frac{1}{1+e^{-(x+y)}}=$ sigmoid$(x)$ {some operation} sigmoid$(y)$ ?
functions
Sigmoid function is defined as $frac{1}{1+e^{-(x+y)}}$.
Is there a property for sigmoid such that
$frac{1}{1+e^{-(x+y)}}=$ sigmoid$(x)$ {some operation} sigmoid$(y)$ ?
functions
functions
edited Nov 13 at 16:39
dmtri
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asked Nov 13 at 16:32
puffles
579
579
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