Integral of a function of phi and sin(phi) in denominator











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I need to solve an integral for my master thesis in physics, but I do not know how to even start. The integral is



$int_{-pi/2}^{pi/2} frac{1}{b+sin^2(phi)} cdot frac{1}{a^2+phi^2} dphi$



Both a and b are positive and bigger than 0, so the integral should converge.



I tried to think of a Weierstrass Substitution, but could not find a suitable one.



Also, I could not apply the Residue theorem, since I do not know which contours to use.



I need the result dependent on a and b.



Can you give me any tipps?










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  • 2




    Looks nasty! I don't see any way other than doing it numerically unfortunately.
    – Richard Martin
    Nov 13 at 16:37















up vote
1
down vote

favorite












I need to solve an integral for my master thesis in physics, but I do not know how to even start. The integral is



$int_{-pi/2}^{pi/2} frac{1}{b+sin^2(phi)} cdot frac{1}{a^2+phi^2} dphi$



Both a and b are positive and bigger than 0, so the integral should converge.



I tried to think of a Weierstrass Substitution, but could not find a suitable one.



Also, I could not apply the Residue theorem, since I do not know which contours to use.



I need the result dependent on a and b.



Can you give me any tipps?










share|cite|improve this question







New contributor




Daniel R is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 2




    Looks nasty! I don't see any way other than doing it numerically unfortunately.
    – Richard Martin
    Nov 13 at 16:37













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I need to solve an integral for my master thesis in physics, but I do not know how to even start. The integral is



$int_{-pi/2}^{pi/2} frac{1}{b+sin^2(phi)} cdot frac{1}{a^2+phi^2} dphi$



Both a and b are positive and bigger than 0, so the integral should converge.



I tried to think of a Weierstrass Substitution, but could not find a suitable one.



Also, I could not apply the Residue theorem, since I do not know which contours to use.



I need the result dependent on a and b.



Can you give me any tipps?










share|cite|improve this question







New contributor




Daniel R is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I need to solve an integral for my master thesis in physics, but I do not know how to even start. The integral is



$int_{-pi/2}^{pi/2} frac{1}{b+sin^2(phi)} cdot frac{1}{a^2+phi^2} dphi$



Both a and b are positive and bigger than 0, so the integral should converge.



I tried to think of a Weierstrass Substitution, but could not find a suitable one.



Also, I could not apply the Residue theorem, since I do not know which contours to use.



I need the result dependent on a and b.



Can you give me any tipps?







integration






share|cite|improve this question







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Daniel R is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|cite|improve this question







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Daniel R is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|cite|improve this question




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asked Nov 13 at 16:17









Daniel R

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Daniel R is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Daniel R is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 2




    Looks nasty! I don't see any way other than doing it numerically unfortunately.
    – Richard Martin
    Nov 13 at 16:37














  • 2




    Looks nasty! I don't see any way other than doing it numerically unfortunately.
    – Richard Martin
    Nov 13 at 16:37








2




2




Looks nasty! I don't see any way other than doing it numerically unfortunately.
– Richard Martin
Nov 13 at 16:37




Looks nasty! I don't see any way other than doing it numerically unfortunately.
– Richard Martin
Nov 13 at 16:37















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