Prove $L$ is in $mathbb {Z} $ - Limits by definition [closed]
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Let $a, b in R$ with $a<b$ and $f : (a, b) to mathbb {Z}, x_0 in (a, b) $. Suppose that there exists an $Linmathbb{R}$ such that $lim_{xto x_0} f(x) = L $.
Prove that $L in mathbb{Z} $.
limits
closed as off-topic by Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus Nov 14 at 0:33
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- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
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Let $a, b in R$ with $a<b$ and $f : (a, b) to mathbb {Z}, x_0 in (a, b) $. Suppose that there exists an $Linmathbb{R}$ such that $lim_{xto x_0} f(x) = L $.
Prove that $L in mathbb{Z} $.
limits
closed as off-topic by Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus Nov 14 at 0:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
Assume $Lnotin mathbb {Z} $ and then use definition of limit with a suitable value of $epsilon$ to derive a contradiction. Post your efforts based on this in your question so that if there is anything wrong help can be obtained.
– Paramanand Singh
Nov 13 at 18:13
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Let $a, b in R$ with $a<b$ and $f : (a, b) to mathbb {Z}, x_0 in (a, b) $. Suppose that there exists an $Linmathbb{R}$ such that $lim_{xto x_0} f(x) = L $.
Prove that $L in mathbb{Z} $.
limits
Let $a, b in R$ with $a<b$ and $f : (a, b) to mathbb {Z}, x_0 in (a, b) $. Suppose that there exists an $Linmathbb{R}$ such that $lim_{xto x_0} f(x) = L $.
Prove that $L in mathbb{Z} $.
limits
limits
edited Nov 13 at 18:17
Paramanand Singh
48.1k555154
48.1k555154
asked Nov 13 at 16:35
Yuki1112
32
32
closed as off-topic by Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus Nov 14 at 0:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus Nov 14 at 0:33
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Paramanand Singh, amWhy, Erick Wong, Scientifica, Leucippus
If this question can be reworded to fit the rules in the help center, please edit the question.
Assume $Lnotin mathbb {Z} $ and then use definition of limit with a suitable value of $epsilon$ to derive a contradiction. Post your efforts based on this in your question so that if there is anything wrong help can be obtained.
– Paramanand Singh
Nov 13 at 18:13
add a comment |
Assume $Lnotin mathbb {Z} $ and then use definition of limit with a suitable value of $epsilon$ to derive a contradiction. Post your efforts based on this in your question so that if there is anything wrong help can be obtained.
– Paramanand Singh
Nov 13 at 18:13
Assume $Lnotin mathbb {Z} $ and then use definition of limit with a suitable value of $epsilon$ to derive a contradiction. Post your efforts based on this in your question so that if there is anything wrong help can be obtained.
– Paramanand Singh
Nov 13 at 18:13
Assume $Lnotin mathbb {Z} $ and then use definition of limit with a suitable value of $epsilon$ to derive a contradiction. Post your efforts based on this in your question so that if there is anything wrong help can be obtained.
– Paramanand Singh
Nov 13 at 18:13
add a comment |
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Assume $Lnotin mathbb {Z} $ and then use definition of limit with a suitable value of $epsilon$ to derive a contradiction. Post your efforts based on this in your question so that if there is anything wrong help can be obtained.
– Paramanand Singh
Nov 13 at 18:13