How to interpret a limit in a graph theory result











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The following is a theorem in the linked paper here.




enter image description here




To add some context, the authors also state:




Throughout this paper...$t^k$, the average degree, will always be an increasing function of $n$, the number of vertices of the hypergraph, i.e., $t = t(n) to infty$ with $n to infty$




How does one interpret the limit in the above sentence? Currently I am interpreting it as: if you add more and more vertices to your hypergraph, the $k$-th root of the average degree should also increase, but that doesn't seem to make much sense. I suppose my main trouble here is: are there particular $(k+1)$-uniform hypergraphs to which Theorem 2.4 cannot be applied, owing to the aforementioned limit?










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  • I wasn't sure if I provided enough context. I will post the entire theorem in question.
    – David Smith
    2 days ago















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down vote

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The following is a theorem in the linked paper here.




enter image description here




To add some context, the authors also state:




Throughout this paper...$t^k$, the average degree, will always be an increasing function of $n$, the number of vertices of the hypergraph, i.e., $t = t(n) to infty$ with $n to infty$




How does one interpret the limit in the above sentence? Currently I am interpreting it as: if you add more and more vertices to your hypergraph, the $k$-th root of the average degree should also increase, but that doesn't seem to make much sense. I suppose my main trouble here is: are there particular $(k+1)$-uniform hypergraphs to which Theorem 2.4 cannot be applied, owing to the aforementioned limit?










share|cite|improve this question
























  • I wasn't sure if I provided enough context. I will post the entire theorem in question.
    – David Smith
    2 days ago













up vote
1
down vote

favorite









up vote
1
down vote

favorite











The following is a theorem in the linked paper here.




enter image description here




To add some context, the authors also state:




Throughout this paper...$t^k$, the average degree, will always be an increasing function of $n$, the number of vertices of the hypergraph, i.e., $t = t(n) to infty$ with $n to infty$




How does one interpret the limit in the above sentence? Currently I am interpreting it as: if you add more and more vertices to your hypergraph, the $k$-th root of the average degree should also increase, but that doesn't seem to make much sense. I suppose my main trouble here is: are there particular $(k+1)$-uniform hypergraphs to which Theorem 2.4 cannot be applied, owing to the aforementioned limit?










share|cite|improve this question















The following is a theorem in the linked paper here.




enter image description here




To add some context, the authors also state:




Throughout this paper...$t^k$, the average degree, will always be an increasing function of $n$, the number of vertices of the hypergraph, i.e., $t = t(n) to infty$ with $n to infty$




How does one interpret the limit in the above sentence? Currently I am interpreting it as: if you add more and more vertices to your hypergraph, the $k$-th root of the average degree should also increase, but that doesn't seem to make much sense. I suppose my main trouble here is: are there particular $(k+1)$-uniform hypergraphs to which Theorem 2.4 cannot be applied, owing to the aforementioned limit?







graph-theory extremal-graph-theory






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edited 2 days ago

























asked 2 days ago









David Smith

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  • I wasn't sure if I provided enough context. I will post the entire theorem in question.
    – David Smith
    2 days ago


















  • I wasn't sure if I provided enough context. I will post the entire theorem in question.
    – David Smith
    2 days ago
















I wasn't sure if I provided enough context. I will post the entire theorem in question.
– David Smith
2 days ago




I wasn't sure if I provided enough context. I will post the entire theorem in question.
– David Smith
2 days ago















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