how do you transpose more than 2 matrices [closed]
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Sorry for the stupid question. How do you transpose more than 2 matrices.
i.e. $(ABCDE)'=$
linear-algebra
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closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37
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Sorry for the stupid question. How do you transpose more than 2 matrices.
i.e. $(ABCDE)'=$
linear-algebra
New contributor
closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R
If this question can be reworded to fit the rules in the help center, please edit the question.
1
This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25
so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27
@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31
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up vote
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down vote
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Sorry for the stupid question. How do you transpose more than 2 matrices.
i.e. $(ABCDE)'=$
linear-algebra
New contributor
Sorry for the stupid question. How do you transpose more than 2 matrices.
i.e. $(ABCDE)'=$
linear-algebra
linear-algebra
New contributor
New contributor
edited Nov 13 at 17:33
Bernard
115k637108
115k637108
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asked Nov 13 at 17:23
user9903833
6
6
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New contributor
closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R Nov 14 at 4:37
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Lee David Chung Lin, user10354138, Shailesh, Chinnapparaj R
If this question can be reworded to fit the rules in the help center, please edit the question.
1
This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25
so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27
@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31
add a comment |
1
This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25
so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27
@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31
1
1
This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25
This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25
so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27
so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27
@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31
@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31
add a comment |
1 Answer
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if $(AB)^T = B^TA^T$ and matrix multipication is associative.
$(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.
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1 Answer
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active
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
up vote
2
down vote
if $(AB)^T = B^TA^T$ and matrix multipication is associative.
$(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.
add a comment |
up vote
2
down vote
if $(AB)^T = B^TA^T$ and matrix multipication is associative.
$(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.
add a comment |
up vote
2
down vote
up vote
2
down vote
if $(AB)^T = B^TA^T$ and matrix multipication is associative.
$(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.
if $(AB)^T = B^TA^T$ and matrix multipication is associative.
$(ABCDE)^T = (A(BCDE))^T = (BCDE)^TA^T$ and keep repeating down the chain.
answered Nov 13 at 17:26
Doug M
42.5k31752
42.5k31752
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1
This is akin to the socks-shoes property. Write the product in reverse order with transposes.
– Sean Roberson
Nov 13 at 17:25
so it will be E'D'C'B'A'
– user9903833
Nov 13 at 17:27
@user9903833 Yes, that's right
– Rushabh Mehta
Nov 13 at 17:31