Overhead brace in tikz












7














I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.



enter image description here



Here is a template:



    documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 

usepackage{sseq}
usepackage[all,cmtip]{xy}
usepackage{tikz-cd}
usepackage{tikz}
usetikzlibrary{matrix}
usetikzlibrary{decorations.markings}


begin{document}


begin{figure}[!h]
begin{center}
begin{tikzpicture}[scale=0.8]
node at (0,5) {1};
node at (0,4.5) {2};
node at (0,4) {3};
draw[->] (0,3.5) -- (0,2.5);
node[right] at (0,3) {};
node at (0,2) {4};
node at (0,1.5) {};
node at (0,1) {5};
node at (0,0.5) {6};

draw[->] (-0.5,3.5) -- (-3.5,2.5);
node at (-2,3) {};
node at (-3.5,2) {7};

node at (-4,4) {8};
draw[->] (-4,3.5) -- (-4,2.5);
node[left] at (-4,3) {};
node at (-4.5,2) {9};
node at (-4,1.5) {};
node at (-4,1) {10};


node at (4,4) {11};
draw[->] (4,3.5) -- (4,2.5);
node[right] at (4,3) {};
node at (4,2) {12};
node at (4,1.5) {};
node at (4,1) {13};



end{tikzpicture}
end{center}
end{figure}

end{document}









share|improve this question



























    7














    I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.



    enter image description here



    Here is a template:



        documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 

    usepackage{sseq}
    usepackage[all,cmtip]{xy}
    usepackage{tikz-cd}
    usepackage{tikz}
    usetikzlibrary{matrix}
    usetikzlibrary{decorations.markings}


    begin{document}


    begin{figure}[!h]
    begin{center}
    begin{tikzpicture}[scale=0.8]
    node at (0,5) {1};
    node at (0,4.5) {2};
    node at (0,4) {3};
    draw[->] (0,3.5) -- (0,2.5);
    node[right] at (0,3) {};
    node at (0,2) {4};
    node at (0,1.5) {};
    node at (0,1) {5};
    node at (0,0.5) {6};

    draw[->] (-0.5,3.5) -- (-3.5,2.5);
    node at (-2,3) {};
    node at (-3.5,2) {7};

    node at (-4,4) {8};
    draw[->] (-4,3.5) -- (-4,2.5);
    node[left] at (-4,3) {};
    node at (-4.5,2) {9};
    node at (-4,1.5) {};
    node at (-4,1) {10};


    node at (4,4) {11};
    draw[->] (4,3.5) -- (4,2.5);
    node[right] at (4,3) {};
    node at (4,2) {12};
    node at (4,1.5) {};
    node at (4,1) {13};



    end{tikzpicture}
    end{center}
    end{figure}

    end{document}









    share|improve this question

























      7












      7








      7


      1





      I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.



      enter image description here



      Here is a template:



          documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 

      usepackage{sseq}
      usepackage[all,cmtip]{xy}
      usepackage{tikz-cd}
      usepackage{tikz}
      usetikzlibrary{matrix}
      usetikzlibrary{decorations.markings}


      begin{document}


      begin{figure}[!h]
      begin{center}
      begin{tikzpicture}[scale=0.8]
      node at (0,5) {1};
      node at (0,4.5) {2};
      node at (0,4) {3};
      draw[->] (0,3.5) -- (0,2.5);
      node[right] at (0,3) {};
      node at (0,2) {4};
      node at (0,1.5) {};
      node at (0,1) {5};
      node at (0,0.5) {6};

      draw[->] (-0.5,3.5) -- (-3.5,2.5);
      node at (-2,3) {};
      node at (-3.5,2) {7};

      node at (-4,4) {8};
      draw[->] (-4,3.5) -- (-4,2.5);
      node[left] at (-4,3) {};
      node at (-4.5,2) {9};
      node at (-4,1.5) {};
      node at (-4,1) {10};


      node at (4,4) {11};
      draw[->] (4,3.5) -- (4,2.5);
      node[right] at (4,3) {};
      node at (4,2) {12};
      node at (4,1.5) {};
      node at (4,1) {13};



      end{tikzpicture}
      end{center}
      end{figure}

      end{document}









      share|improve this question













      I wish to use the overhead brace, bracing over the three items 8, 3, 11 from the bottom of 2.



      enter image description here



      Here is a template:



          documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 

      usepackage{sseq}
      usepackage[all,cmtip]{xy}
      usepackage{tikz-cd}
      usepackage{tikz}
      usetikzlibrary{matrix}
      usetikzlibrary{decorations.markings}


      begin{document}


      begin{figure}[!h]
      begin{center}
      begin{tikzpicture}[scale=0.8]
      node at (0,5) {1};
      node at (0,4.5) {2};
      node at (0,4) {3};
      draw[->] (0,3.5) -- (0,2.5);
      node[right] at (0,3) {};
      node at (0,2) {4};
      node at (0,1.5) {};
      node at (0,1) {5};
      node at (0,0.5) {6};

      draw[->] (-0.5,3.5) -- (-3.5,2.5);
      node at (-2,3) {};
      node at (-3.5,2) {7};

      node at (-4,4) {8};
      draw[->] (-4,3.5) -- (-4,2.5);
      node[left] at (-4,3) {};
      node at (-4.5,2) {9};
      node at (-4,1.5) {};
      node at (-4,1) {10};


      node at (4,4) {11};
      draw[->] (4,3.5) -- (4,2.5);
      node[right] at (4,3) {};
      node at (4,2) {12};
      node at (4,1.5) {};
      node at (4,1) {13};



      end{tikzpicture}
      end{center}
      end{figure}

      end{document}






      tikz-pgf horizontal-alignment vertical-alignment braces overbrace






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Dec 17 at 4:50









      wonderich

      713618




      713618






















          1 Answer
          1






          active

          oldest

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          7














          I have not simplified your code which can be simplified in several different ways. I used the positioning library (page 229 of the manual 3.0.1a) to position nodes 2 and 1 relative to node 3.
          I named a few nodes by their value.
          To use the braces, I used the decorations.pathreplacing library. (page 581 of manual 3.0.1a)



          capture



            documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 
          % usepackage{sseq}
          % usepackage[all,cmtip]{xy}
          % usepackage{tikz-cd}
          usepackage{tikz}
          % usetikzlibrary{matrix}
          % usetikzlibrary{decorations.markings}
          usetikzlibrary{positioning,decorations.pathreplacing}

          begin{document}
          begin{figure}[!h]
          begin{center}
          begin{tikzpicture}[scale=0.8]

          node at (0,4)(3) {3};

          node[above =of 3] {1};
          node[above=5mm of 3]{2};
          node at (-4,4)(8) {8};
          node at (4,4)(11) {11};
          draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
          draw[->] (0,3.5) -- (0,2.5);
          node[right] at (0,3) {};
          node at (0,2) {4};
          node at (0,1.5) {};
          node at (0,1) {5};
          node at (0,0.5) {6};

          draw[->] (-0.5,3.5) -- (-3.5,2.5);
          node at (-2,3) {};
          node at (-3.5,2) {7};
          draw[->] (-4,3.5) -- (-4,2.5);
          node[left] at (-4,3) {};
          node at (-4.5,2) {9};
          node at (-4,1.5) {};
          node at (-4,1) {10};
          draw[->] (4,3.5) -- (4,2.5);
          node[right] at (4,3) {};
          node at (4,2) {12};
          node at (4,1.5) {};
          node at (4,1) {13};
          end{tikzpicture}
          end{center}
          end{figure}

          end{document}





          share|improve this answer























          • that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
            – wonderich
            Dec 17 at 5:12










          • You can use the graphs library in several different ways to make this graph (see page 257)
            – AndréC
            Dec 17 at 5:14








          • 2




            @wonderich I suggest marking AndréC's answer as "Accepted" by clicking the tick below the up/down vote buttons, if the answer solves your problem.
            – JouleV
            Dec 17 at 6:45










          • Yes, I just did! Thanks!
            – wonderich
            Dec 17 at 14:15











          Your Answer








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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          7














          I have not simplified your code which can be simplified in several different ways. I used the positioning library (page 229 of the manual 3.0.1a) to position nodes 2 and 1 relative to node 3.
          I named a few nodes by their value.
          To use the braces, I used the decorations.pathreplacing library. (page 581 of manual 3.0.1a)



          capture



            documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 
          % usepackage{sseq}
          % usepackage[all,cmtip]{xy}
          % usepackage{tikz-cd}
          usepackage{tikz}
          % usetikzlibrary{matrix}
          % usetikzlibrary{decorations.markings}
          usetikzlibrary{positioning,decorations.pathreplacing}

          begin{document}
          begin{figure}[!h]
          begin{center}
          begin{tikzpicture}[scale=0.8]

          node at (0,4)(3) {3};

          node[above =of 3] {1};
          node[above=5mm of 3]{2};
          node at (-4,4)(8) {8};
          node at (4,4)(11) {11};
          draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
          draw[->] (0,3.5) -- (0,2.5);
          node[right] at (0,3) {};
          node at (0,2) {4};
          node at (0,1.5) {};
          node at (0,1) {5};
          node at (0,0.5) {6};

          draw[->] (-0.5,3.5) -- (-3.5,2.5);
          node at (-2,3) {};
          node at (-3.5,2) {7};
          draw[->] (-4,3.5) -- (-4,2.5);
          node[left] at (-4,3) {};
          node at (-4.5,2) {9};
          node at (-4,1.5) {};
          node at (-4,1) {10};
          draw[->] (4,3.5) -- (4,2.5);
          node[right] at (4,3) {};
          node at (4,2) {12};
          node at (4,1.5) {};
          node at (4,1) {13};
          end{tikzpicture}
          end{center}
          end{figure}

          end{document}





          share|improve this answer























          • that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
            – wonderich
            Dec 17 at 5:12










          • You can use the graphs library in several different ways to make this graph (see page 257)
            – AndréC
            Dec 17 at 5:14








          • 2




            @wonderich I suggest marking AndréC's answer as "Accepted" by clicking the tick below the up/down vote buttons, if the answer solves your problem.
            – JouleV
            Dec 17 at 6:45










          • Yes, I just did! Thanks!
            – wonderich
            Dec 17 at 14:15
















          7














          I have not simplified your code which can be simplified in several different ways. I used the positioning library (page 229 of the manual 3.0.1a) to position nodes 2 and 1 relative to node 3.
          I named a few nodes by their value.
          To use the braces, I used the decorations.pathreplacing library. (page 581 of manual 3.0.1a)



          capture



            documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 
          % usepackage{sseq}
          % usepackage[all,cmtip]{xy}
          % usepackage{tikz-cd}
          usepackage{tikz}
          % usetikzlibrary{matrix}
          % usetikzlibrary{decorations.markings}
          usetikzlibrary{positioning,decorations.pathreplacing}

          begin{document}
          begin{figure}[!h]
          begin{center}
          begin{tikzpicture}[scale=0.8]

          node at (0,4)(3) {3};

          node[above =of 3] {1};
          node[above=5mm of 3]{2};
          node at (-4,4)(8) {8};
          node at (4,4)(11) {11};
          draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
          draw[->] (0,3.5) -- (0,2.5);
          node[right] at (0,3) {};
          node at (0,2) {4};
          node at (0,1.5) {};
          node at (0,1) {5};
          node at (0,0.5) {6};

          draw[->] (-0.5,3.5) -- (-3.5,2.5);
          node at (-2,3) {};
          node at (-3.5,2) {7};
          draw[->] (-4,3.5) -- (-4,2.5);
          node[left] at (-4,3) {};
          node at (-4.5,2) {9};
          node at (-4,1.5) {};
          node at (-4,1) {10};
          draw[->] (4,3.5) -- (4,2.5);
          node[right] at (4,3) {};
          node at (4,2) {12};
          node at (4,1.5) {};
          node at (4,1) {13};
          end{tikzpicture}
          end{center}
          end{figure}

          end{document}





          share|improve this answer























          • that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
            – wonderich
            Dec 17 at 5:12










          • You can use the graphs library in several different ways to make this graph (see page 257)
            – AndréC
            Dec 17 at 5:14








          • 2




            @wonderich I suggest marking AndréC's answer as "Accepted" by clicking the tick below the up/down vote buttons, if the answer solves your problem.
            – JouleV
            Dec 17 at 6:45










          • Yes, I just did! Thanks!
            – wonderich
            Dec 17 at 14:15














          7












          7








          7






          I have not simplified your code which can be simplified in several different ways. I used the positioning library (page 229 of the manual 3.0.1a) to position nodes 2 and 1 relative to node 3.
          I named a few nodes by their value.
          To use the braces, I used the decorations.pathreplacing library. (page 581 of manual 3.0.1a)



          capture



            documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 
          % usepackage{sseq}
          % usepackage[all,cmtip]{xy}
          % usepackage{tikz-cd}
          usepackage{tikz}
          % usetikzlibrary{matrix}
          % usetikzlibrary{decorations.markings}
          usetikzlibrary{positioning,decorations.pathreplacing}

          begin{document}
          begin{figure}[!h]
          begin{center}
          begin{tikzpicture}[scale=0.8]

          node at (0,4)(3) {3};

          node[above =of 3] {1};
          node[above=5mm of 3]{2};
          node at (-4,4)(8) {8};
          node at (4,4)(11) {11};
          draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
          draw[->] (0,3.5) -- (0,2.5);
          node[right] at (0,3) {};
          node at (0,2) {4};
          node at (0,1.5) {};
          node at (0,1) {5};
          node at (0,0.5) {6};

          draw[->] (-0.5,3.5) -- (-3.5,2.5);
          node at (-2,3) {};
          node at (-3.5,2) {7};
          draw[->] (-4,3.5) -- (-4,2.5);
          node[left] at (-4,3) {};
          node at (-4.5,2) {9};
          node at (-4,1.5) {};
          node at (-4,1) {10};
          draw[->] (4,3.5) -- (4,2.5);
          node[right] at (4,3) {};
          node at (4,2) {12};
          node at (4,1.5) {};
          node at (4,1) {13};
          end{tikzpicture}
          end{center}
          end{figure}

          end{document}





          share|improve this answer














          I have not simplified your code which can be simplified in several different ways. I used the positioning library (page 229 of the manual 3.0.1a) to position nodes 2 and 1 relative to node 3.
          I named a few nodes by their value.
          To use the braces, I used the decorations.pathreplacing library. (page 581 of manual 3.0.1a)



          capture



            documentclass[11pt,urlcolor=blue, linkcolor=blue]{article} 
          % usepackage{sseq}
          % usepackage[all,cmtip]{xy}
          % usepackage{tikz-cd}
          usepackage{tikz}
          % usetikzlibrary{matrix}
          % usetikzlibrary{decorations.markings}
          usetikzlibrary{positioning,decorations.pathreplacing}

          begin{document}
          begin{figure}[!h]
          begin{center}
          begin{tikzpicture}[scale=0.8]

          node at (0,4)(3) {3};

          node[above =of 3] {1};
          node[above=5mm of 3]{2};
          node at (-4,4)(8) {8};
          node at (4,4)(11) {11};
          draw[decorate, decoration={brace,raise=2pt,amplitude=10pt}](8.north west)--(11.north east);
          draw[->] (0,3.5) -- (0,2.5);
          node[right] at (0,3) {};
          node at (0,2) {4};
          node at (0,1.5) {};
          node at (0,1) {5};
          node at (0,0.5) {6};

          draw[->] (-0.5,3.5) -- (-3.5,2.5);
          node at (-2,3) {};
          node at (-3.5,2) {7};
          draw[->] (-4,3.5) -- (-4,2.5);
          node[left] at (-4,3) {};
          node at (-4.5,2) {9};
          node at (-4,1.5) {};
          node at (-4,1) {10};
          draw[->] (4,3.5) -- (4,2.5);
          node[right] at (4,3) {};
          node at (4,2) {12};
          node at (4,1.5) {};
          node at (4,1) {13};
          end{tikzpicture}
          end{center}
          end{figure}

          end{document}






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Dec 17 at 5:12

























          answered Dec 17 at 5:09









          AndréC

          7,63011440




          7,63011440












          • that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
            – wonderich
            Dec 17 at 5:12










          • You can use the graphs library in several different ways to make this graph (see page 257)
            – AndréC
            Dec 17 at 5:14








          • 2




            @wonderich I suggest marking AndréC's answer as "Accepted" by clicking the tick below the up/down vote buttons, if the answer solves your problem.
            – JouleV
            Dec 17 at 6:45










          • Yes, I just did! Thanks!
            – wonderich
            Dec 17 at 14:15


















          • that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
            – wonderich
            Dec 17 at 5:12










          • You can use the graphs library in several different ways to make this graph (see page 257)
            – AndréC
            Dec 17 at 5:14








          • 2




            @wonderich I suggest marking AndréC's answer as "Accepted" by clicking the tick below the up/down vote buttons, if the answer solves your problem.
            – JouleV
            Dec 17 at 6:45










          • Yes, I just did! Thanks!
            – wonderich
            Dec 17 at 14:15
















          that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
          – wonderich
          Dec 17 at 5:12




          that is basically what I wanted! thanks! (other ways you suggest to simplify can be posted as a separate answer. Please dont overwrite what you had!)
          – wonderich
          Dec 17 at 5:12












          You can use the graphs library in several different ways to make this graph (see page 257)
          – AndréC
          Dec 17 at 5:14






          You can use the graphs library in several different ways to make this graph (see page 257)
          – AndréC
          Dec 17 at 5:14






          2




          2




          @wonderich I suggest marking AndréC's answer as "Accepted" by clicking the tick below the up/down vote buttons, if the answer solves your problem.
          – JouleV
          Dec 17 at 6:45




          @wonderich I suggest marking AndréC's answer as "Accepted" by clicking the tick below the up/down vote buttons, if the answer solves your problem.
          – JouleV
          Dec 17 at 6:45












          Yes, I just did! Thanks!
          – wonderich
          Dec 17 at 14:15




          Yes, I just did! Thanks!
          – wonderich
          Dec 17 at 14:15


















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