Detect Crossed Paths on a Plane Given Coordinates.
$begingroup$
If you have the $X$ and $Y$ coordinates for $2$ lines on a $2D$ plane/graph is it possible to detect via true/false if they cross paths? I'm just trying to detect if lines are not parrallell.
If $(X,Y)$ is $(20, 20)$ to $(X_2,Y_2)$ of $(30,30)$
and a second line is $(X_3,Y_3) (18,22)$ to $(X_4,Y_4)$ of $(30,25)$.
plane-geometry
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
$endgroup$
add a comment |
$begingroup$
If you have the $X$ and $Y$ coordinates for $2$ lines on a $2D$ plane/graph is it possible to detect via true/false if they cross paths? I'm just trying to detect if lines are not parrallell.
If $(X,Y)$ is $(20, 20)$ to $(X_2,Y_2)$ of $(30,30)$
and a second line is $(X_3,Y_3) (18,22)$ to $(X_4,Y_4)$ of $(30,25)$.
plane-geometry
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
$endgroup$
$begingroup$
Do you know how to compute slopes for both lines?
$endgroup$
– David K
Dec 17 '18 at 20:04
$begingroup$
I'll be honest I'm appalling at math as a whole. I have no idea how to but can probably Google that one. What would I do after calculating the slopes?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:05
add a comment |
$begingroup$
If you have the $X$ and $Y$ coordinates for $2$ lines on a $2D$ plane/graph is it possible to detect via true/false if they cross paths? I'm just trying to detect if lines are not parrallell.
If $(X,Y)$ is $(20, 20)$ to $(X_2,Y_2)$ of $(30,30)$
and a second line is $(X_3,Y_3) (18,22)$ to $(X_4,Y_4)$ of $(30,25)$.
plane-geometry
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
$endgroup$
If you have the $X$ and $Y$ coordinates for $2$ lines on a $2D$ plane/graph is it possible to detect via true/false if they cross paths? I'm just trying to detect if lines are not parrallell.
If $(X,Y)$ is $(20, 20)$ to $(X_2,Y_2)$ of $(30,30)$
and a second line is $(X_3,Y_3) (18,22)$ to $(X_4,Y_4)$ of $(30,25)$.
plane-geometry
plane-geometry
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
edited Dec 17 '18 at 20:42
Shubham Johri
5,189718
5,189718
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
asked Dec 17 '18 at 19:55
DaveyBoy85DaveyBoy85
31
31
$begingroup$
Do you know how to compute slopes for both lines?
$endgroup$
– David K
Dec 17 '18 at 20:04
$begingroup$
I'll be honest I'm appalling at math as a whole. I have no idea how to but can probably Google that one. What would I do after calculating the slopes?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:05
add a comment |
$begingroup$
Do you know how to compute slopes for both lines?
$endgroup$
– David K
Dec 17 '18 at 20:04
$begingroup$
I'll be honest I'm appalling at math as a whole. I have no idea how to but can probably Google that one. What would I do after calculating the slopes?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:05
$begingroup$
Do you know how to compute slopes for both lines?
$endgroup$
– David K
Dec 17 '18 at 20:04
$begingroup$
Do you know how to compute slopes for both lines?
$endgroup$
– David K
Dec 17 '18 at 20:04
$begingroup$
I'll be honest I'm appalling at math as a whole. I have no idea how to but can probably Google that one. What would I do after calculating the slopes?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:05
$begingroup$
I'll be honest I'm appalling at math as a whole. I have no idea how to but can probably Google that one. What would I do after calculating the slopes?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:05
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
$2$ non-parallel lines will always intersect. If the lines are parallel, they may or may not be coincident.
For a straight line, its slope $m=frac{y_2-y_1}{x_2-x_1}$, where $(x_1,y_1),(x_2,y_2)$ are two distinct points on the line, describes how the line is inclined with respect to the $x$ axis. The slopes of two parallel lines are equal and unequal for non-parallel lines.
So, you will have to find the slope of the lines. If they are unequal, they intersect at a unique point. Otherwise, the lines are parallel. If, then, they are coincident, the slope of the line joining any point on one line and any point on the second line is equal to the slope of either line. If that's not the case, they don't intersect.
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
$endgroup$
$begingroup$
So in the case in the original post its 10/10 and -12/-3. So since unequal theres a definite intersect between them?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:36
$begingroup$
Yes. Well, the slope of the second line is $3/12$, but that doesn't matter because if the slopes are unequal, so are their reciprocals. You should read more about straight lines and their slopes online.
$endgroup$
– Shubham Johri
Dec 17 '18 at 20:39
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3044364%2fdetect-crossed-paths-on-a-plane-given-coordinates%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
$2$ non-parallel lines will always intersect. If the lines are parallel, they may or may not be coincident.
For a straight line, its slope $m=frac{y_2-y_1}{x_2-x_1}$, where $(x_1,y_1),(x_2,y_2)$ are two distinct points on the line, describes how the line is inclined with respect to the $x$ axis. The slopes of two parallel lines are equal and unequal for non-parallel lines.
So, you will have to find the slope of the lines. If they are unequal, they intersect at a unique point. Otherwise, the lines are parallel. If, then, they are coincident, the slope of the line joining any point on one line and any point on the second line is equal to the slope of either line. If that's not the case, they don't intersect.
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
$endgroup$
$begingroup$
So in the case in the original post its 10/10 and -12/-3. So since unequal theres a definite intersect between them?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:36
$begingroup$
Yes. Well, the slope of the second line is $3/12$, but that doesn't matter because if the slopes are unequal, so are their reciprocals. You should read more about straight lines and their slopes online.
$endgroup$
– Shubham Johri
Dec 17 '18 at 20:39
add a comment |
$begingroup$
$2$ non-parallel lines will always intersect. If the lines are parallel, they may or may not be coincident.
For a straight line, its slope $m=frac{y_2-y_1}{x_2-x_1}$, where $(x_1,y_1),(x_2,y_2)$ are two distinct points on the line, describes how the line is inclined with respect to the $x$ axis. The slopes of two parallel lines are equal and unequal for non-parallel lines.
So, you will have to find the slope of the lines. If they are unequal, they intersect at a unique point. Otherwise, the lines are parallel. If, then, they are coincident, the slope of the line joining any point on one line and any point on the second line is equal to the slope of either line. If that's not the case, they don't intersect.
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
$endgroup$
$begingroup$
So in the case in the original post its 10/10 and -12/-3. So since unequal theres a definite intersect between them?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:36
$begingroup$
Yes. Well, the slope of the second line is $3/12$, but that doesn't matter because if the slopes are unequal, so are their reciprocals. You should read more about straight lines and their slopes online.
$endgroup$
– Shubham Johri
Dec 17 '18 at 20:39
add a comment |
$begingroup$
$2$ non-parallel lines will always intersect. If the lines are parallel, they may or may not be coincident.
For a straight line, its slope $m=frac{y_2-y_1}{x_2-x_1}$, where $(x_1,y_1),(x_2,y_2)$ are two distinct points on the line, describes how the line is inclined with respect to the $x$ axis. The slopes of two parallel lines are equal and unequal for non-parallel lines.
So, you will have to find the slope of the lines. If they are unequal, they intersect at a unique point. Otherwise, the lines are parallel. If, then, they are coincident, the slope of the line joining any point on one line and any point on the second line is equal to the slope of either line. If that's not the case, they don't intersect.
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
$endgroup$
$2$ non-parallel lines will always intersect. If the lines are parallel, they may or may not be coincident.
For a straight line, its slope $m=frac{y_2-y_1}{x_2-x_1}$, where $(x_1,y_1),(x_2,y_2)$ are two distinct points on the line, describes how the line is inclined with respect to the $x$ axis. The slopes of two parallel lines are equal and unequal for non-parallel lines.
So, you will have to find the slope of the lines. If they are unequal, they intersect at a unique point. Otherwise, the lines are parallel. If, then, they are coincident, the slope of the line joining any point on one line and any point on the second line is equal to the slope of either line. If that's not the case, they don't intersect.
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
answered Dec 17 '18 at 20:29
Shubham JohriShubham Johri
5,189718
5,189718
$begingroup$
So in the case in the original post its 10/10 and -12/-3. So since unequal theres a definite intersect between them?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:36
$begingroup$
Yes. Well, the slope of the second line is $3/12$, but that doesn't matter because if the slopes are unequal, so are their reciprocals. You should read more about straight lines and their slopes online.
$endgroup$
– Shubham Johri
Dec 17 '18 at 20:39
add a comment |
$begingroup$
So in the case in the original post its 10/10 and -12/-3. So since unequal theres a definite intersect between them?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:36
$begingroup$
Yes. Well, the slope of the second line is $3/12$, but that doesn't matter because if the slopes are unequal, so are their reciprocals. You should read more about straight lines and their slopes online.
$endgroup$
– Shubham Johri
Dec 17 '18 at 20:39
$begingroup$
So in the case in the original post its 10/10 and -12/-3. So since unequal theres a definite intersect between them?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:36
$begingroup$
So in the case in the original post its 10/10 and -12/-3. So since unequal theres a definite intersect between them?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:36
$begingroup$
Yes. Well, the slope of the second line is $3/12$, but that doesn't matter because if the slopes are unequal, so are their reciprocals. You should read more about straight lines and their slopes online.
$endgroup$
– Shubham Johri
Dec 17 '18 at 20:39
$begingroup$
Yes. Well, the slope of the second line is $3/12$, but that doesn't matter because if the slopes are unequal, so are their reciprocals. You should read more about straight lines and their slopes online.
$endgroup$
– Shubham Johri
Dec 17 '18 at 20:39
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3044364%2fdetect-crossed-paths-on-a-plane-given-coordinates%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Do you know how to compute slopes for both lines?
$endgroup$
– David K
Dec 17 '18 at 20:04
$begingroup$
I'll be honest I'm appalling at math as a whole. I have no idea how to but can probably Google that one. What would I do after calculating the slopes?
$endgroup$
– DaveyBoy85
Dec 17 '18 at 20:05