Proving the Reduction Formula of $tan^n(theta)$












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The following is what I have tried to prove the reduction formula of $tan^n(theta)$.



enter image description here



For the last step, how to convert the $int sec^2(theta) tan^{n-1}(theta)dtheta $ to $frac {tan^{n-1}theta}{n-1}$?



Thank you for your help.










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  • $begingroup$
    sosmath.com/CBB/viewtopic.php?p=47786
    $endgroup$
    – lab bhattacharjee
    May 13 '14 at 13:03
















0












$begingroup$


The following is what I have tried to prove the reduction formula of $tan^n(theta)$.



enter image description here



For the last step, how to convert the $int sec^2(theta) tan^{n-1}(theta)dtheta $ to $frac {tan^{n-1}theta}{n-1}$?



Thank you for your help.










share|cite|improve this question











$endgroup$












  • $begingroup$
    sosmath.com/CBB/viewtopic.php?p=47786
    $endgroup$
    – lab bhattacharjee
    May 13 '14 at 13:03














0












0








0





$begingroup$


The following is what I have tried to prove the reduction formula of $tan^n(theta)$.



enter image description here



For the last step, how to convert the $int sec^2(theta) tan^{n-1}(theta)dtheta $ to $frac {tan^{n-1}theta}{n-1}$?



Thank you for your help.










share|cite|improve this question











$endgroup$




The following is what I have tried to prove the reduction formula of $tan^n(theta)$.



enter image description here



For the last step, how to convert the $int sec^2(theta) tan^{n-1}(theta)dtheta $ to $frac {tan^{n-1}theta}{n-1}$?



Thank you for your help.







calculus reduction-formula






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edited Jan 6 at 23:08









clathratus

5,1141439




5,1141439










asked May 13 '14 at 13:01









KinKin

55431431




55431431












  • $begingroup$
    sosmath.com/CBB/viewtopic.php?p=47786
    $endgroup$
    – lab bhattacharjee
    May 13 '14 at 13:03


















  • $begingroup$
    sosmath.com/CBB/viewtopic.php?p=47786
    $endgroup$
    – lab bhattacharjee
    May 13 '14 at 13:03
















$begingroup$
sosmath.com/CBB/viewtopic.php?p=47786
$endgroup$
– lab bhattacharjee
May 13 '14 at 13:03




$begingroup$
sosmath.com/CBB/viewtopic.php?p=47786
$endgroup$
– lab bhattacharjee
May 13 '14 at 13:03










1 Answer
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HINT: Since $$frac{d}{dtheta}tan theta=sec^2theta$$, you have $$int sec^2theta tan^{n-2}theta dtheta=int tan^{n-2}theta d(tantheta)$$






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    1 Answer
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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

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    2












    $begingroup$

    HINT: Since $$frac{d}{dtheta}tan theta=sec^2theta$$, you have $$int sec^2theta tan^{n-2}theta dtheta=int tan^{n-2}theta d(tantheta)$$






    share|cite|improve this answer









    $endgroup$


















      2












      $begingroup$

      HINT: Since $$frac{d}{dtheta}tan theta=sec^2theta$$, you have $$int sec^2theta tan^{n-2}theta dtheta=int tan^{n-2}theta d(tantheta)$$






      share|cite|improve this answer









      $endgroup$
















        2












        2








        2





        $begingroup$

        HINT: Since $$frac{d}{dtheta}tan theta=sec^2theta$$, you have $$int sec^2theta tan^{n-2}theta dtheta=int tan^{n-2}theta d(tantheta)$$






        share|cite|improve this answer









        $endgroup$



        HINT: Since $$frac{d}{dtheta}tan theta=sec^2theta$$, you have $$int sec^2theta tan^{n-2}theta dtheta=int tan^{n-2}theta d(tantheta)$$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered May 13 '14 at 13:04









        Samrat MukhopadhyaySamrat Mukhopadhyay

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