Notation for eigenvalues
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Is there a specific notation for eigenvalues? specifically, I'd like to write:
$$mequiv text{smallest eigenvaue of }H$$
I've seen some sources write this as: $Hsucceq mI$, where "$succeq0$" means the matrix is semi positive definite, but it seems a bit convoluted.
Is there a simpler, more accepted way to write this?
notation eigenvalues-eigenvectors
$endgroup$
add a comment |
$begingroup$
Is there a specific notation for eigenvalues? specifically, I'd like to write:
$$mequiv text{smallest eigenvaue of }H$$
I've seen some sources write this as: $Hsucceq mI$, where "$succeq0$" means the matrix is semi positive definite, but it seems a bit convoluted.
Is there a simpler, more accepted way to write this?
notation eigenvalues-eigenvectors
$endgroup$
1
$begingroup$
I don't believe there's a standard notation for the smallest eigenvalue. I assume you mean smallest in absolute value? And it wouldn't necessarily be unique so that's also problematic.
$endgroup$
– Gregory Grant
Dec 26 '15 at 15:03
1
$begingroup$
What's wrong with saying something like "let $m$ be the smallest eigenvalue of $H$"? Provided that this makes sense, of course (see Gregory's comment above)...
$endgroup$
– A.P.
Dec 26 '15 at 15:07
add a comment |
$begingroup$
Is there a specific notation for eigenvalues? specifically, I'd like to write:
$$mequiv text{smallest eigenvaue of }H$$
I've seen some sources write this as: $Hsucceq mI$, where "$succeq0$" means the matrix is semi positive definite, but it seems a bit convoluted.
Is there a simpler, more accepted way to write this?
notation eigenvalues-eigenvectors
$endgroup$
Is there a specific notation for eigenvalues? specifically, I'd like to write:
$$mequiv text{smallest eigenvaue of }H$$
I've seen some sources write this as: $Hsucceq mI$, where "$succeq0$" means the matrix is semi positive definite, but it seems a bit convoluted.
Is there a simpler, more accepted way to write this?
notation eigenvalues-eigenvectors
notation eigenvalues-eigenvectors
asked Dec 26 '15 at 15:01
nbubisnbubis
27.3k552110
27.3k552110
1
$begingroup$
I don't believe there's a standard notation for the smallest eigenvalue. I assume you mean smallest in absolute value? And it wouldn't necessarily be unique so that's also problematic.
$endgroup$
– Gregory Grant
Dec 26 '15 at 15:03
1
$begingroup$
What's wrong with saying something like "let $m$ be the smallest eigenvalue of $H$"? Provided that this makes sense, of course (see Gregory's comment above)...
$endgroup$
– A.P.
Dec 26 '15 at 15:07
add a comment |
1
$begingroup$
I don't believe there's a standard notation for the smallest eigenvalue. I assume you mean smallest in absolute value? And it wouldn't necessarily be unique so that's also problematic.
$endgroup$
– Gregory Grant
Dec 26 '15 at 15:03
1
$begingroup$
What's wrong with saying something like "let $m$ be the smallest eigenvalue of $H$"? Provided that this makes sense, of course (see Gregory's comment above)...
$endgroup$
– A.P.
Dec 26 '15 at 15:07
1
1
$begingroup$
I don't believe there's a standard notation for the smallest eigenvalue. I assume you mean smallest in absolute value? And it wouldn't necessarily be unique so that's also problematic.
$endgroup$
– Gregory Grant
Dec 26 '15 at 15:03
$begingroup$
I don't believe there's a standard notation for the smallest eigenvalue. I assume you mean smallest in absolute value? And it wouldn't necessarily be unique so that's also problematic.
$endgroup$
– Gregory Grant
Dec 26 '15 at 15:03
1
1
$begingroup$
What's wrong with saying something like "let $m$ be the smallest eigenvalue of $H$"? Provided that this makes sense, of course (see Gregory's comment above)...
$endgroup$
– A.P.
Dec 26 '15 at 15:07
$begingroup$
What's wrong with saying something like "let $m$ be the smallest eigenvalue of $H$"? Provided that this makes sense, of course (see Gregory's comment above)...
$endgroup$
– A.P.
Dec 26 '15 at 15:07
add a comment |
1 Answer
1
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$begingroup$
Normally one says something like "Let $lambda_1, ldots, lambda_n$ be the eigenvalues of $H$ in non-decreasing order." or "Let $lambda_1 leq ldotsleq lambda_n$ be the eigenvalues of $H$."
Then, you just say $lambda_1$.
$endgroup$
$begingroup$
I take this as "no".
$endgroup$
– nbubis
Dec 29 '15 at 10:08
$begingroup$
Pretty much. Just stating the fact in words is a good way to go as well ("Let $m$ be the smallest eigenvalue of $H$) if you only need the smallest eigenvalue, as suggested in the comments to the original question
$endgroup$
– Batman
Dec 29 '15 at 15:46
add a comment |
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$begingroup$
Normally one says something like "Let $lambda_1, ldots, lambda_n$ be the eigenvalues of $H$ in non-decreasing order." or "Let $lambda_1 leq ldotsleq lambda_n$ be the eigenvalues of $H$."
Then, you just say $lambda_1$.
$endgroup$
$begingroup$
I take this as "no".
$endgroup$
– nbubis
Dec 29 '15 at 10:08
$begingroup$
Pretty much. Just stating the fact in words is a good way to go as well ("Let $m$ be the smallest eigenvalue of $H$) if you only need the smallest eigenvalue, as suggested in the comments to the original question
$endgroup$
– Batman
Dec 29 '15 at 15:46
add a comment |
$begingroup$
Normally one says something like "Let $lambda_1, ldots, lambda_n$ be the eigenvalues of $H$ in non-decreasing order." or "Let $lambda_1 leq ldotsleq lambda_n$ be the eigenvalues of $H$."
Then, you just say $lambda_1$.
$endgroup$
$begingroup$
I take this as "no".
$endgroup$
– nbubis
Dec 29 '15 at 10:08
$begingroup$
Pretty much. Just stating the fact in words is a good way to go as well ("Let $m$ be the smallest eigenvalue of $H$) if you only need the smallest eigenvalue, as suggested in the comments to the original question
$endgroup$
– Batman
Dec 29 '15 at 15:46
add a comment |
$begingroup$
Normally one says something like "Let $lambda_1, ldots, lambda_n$ be the eigenvalues of $H$ in non-decreasing order." or "Let $lambda_1 leq ldotsleq lambda_n$ be the eigenvalues of $H$."
Then, you just say $lambda_1$.
$endgroup$
Normally one says something like "Let $lambda_1, ldots, lambda_n$ be the eigenvalues of $H$ in non-decreasing order." or "Let $lambda_1 leq ldotsleq lambda_n$ be the eigenvalues of $H$."
Then, you just say $lambda_1$.
answered Dec 26 '15 at 15:04
BatmanBatman
16.5k11735
16.5k11735
$begingroup$
I take this as "no".
$endgroup$
– nbubis
Dec 29 '15 at 10:08
$begingroup$
Pretty much. Just stating the fact in words is a good way to go as well ("Let $m$ be the smallest eigenvalue of $H$) if you only need the smallest eigenvalue, as suggested in the comments to the original question
$endgroup$
– Batman
Dec 29 '15 at 15:46
add a comment |
$begingroup$
I take this as "no".
$endgroup$
– nbubis
Dec 29 '15 at 10:08
$begingroup$
Pretty much. Just stating the fact in words is a good way to go as well ("Let $m$ be the smallest eigenvalue of $H$) if you only need the smallest eigenvalue, as suggested in the comments to the original question
$endgroup$
– Batman
Dec 29 '15 at 15:46
$begingroup$
I take this as "no".
$endgroup$
– nbubis
Dec 29 '15 at 10:08
$begingroup$
I take this as "no".
$endgroup$
– nbubis
Dec 29 '15 at 10:08
$begingroup$
Pretty much. Just stating the fact in words is a good way to go as well ("Let $m$ be the smallest eigenvalue of $H$) if you only need the smallest eigenvalue, as suggested in the comments to the original question
$endgroup$
– Batman
Dec 29 '15 at 15:46
$begingroup$
Pretty much. Just stating the fact in words is a good way to go as well ("Let $m$ be the smallest eigenvalue of $H$) if you only need the smallest eigenvalue, as suggested in the comments to the original question
$endgroup$
– Batman
Dec 29 '15 at 15:46
add a comment |
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$begingroup$
I don't believe there's a standard notation for the smallest eigenvalue. I assume you mean smallest in absolute value? And it wouldn't necessarily be unique so that's also problematic.
$endgroup$
– Gregory Grant
Dec 26 '15 at 15:03
1
$begingroup$
What's wrong with saying something like "let $m$ be the smallest eigenvalue of $H$"? Provided that this makes sense, of course (see Gregory's comment above)...
$endgroup$
– A.P.
Dec 26 '15 at 15:07