CD-ROM Mode 1 vs DVD: which one has superior error correction?
CD-ROM Mode 1
98 (24B) Frames = 1 Block = 2352 bytes. Every Frame is protected by 8 Parity bytes.
These 8 bytes, the 1st level of error correction, are CIRC generated. CD-ROM Mode 1 also adds a 2nd level of error correction, within each Block: 4 bytes to perform CRC to detect errors and 276 bytes, generated by RSPC, to detect and correct errors.
12B + 4B + 2048B + 4B + 8B + 276B = 2352B
So, CD-ROM mode 1 uses 2 levels of error correction.
Level 1: every Frame is protected by 8B Parity, just like CD-DA.
Level 2: within each block, 2048B User Date is protected by 4B EDC and 276B ECC.
98 * 8B Parity + 4B EDC + 276B ECC = 788 bytes of CIRC/CRC/RSPC per 2048 bytes User Data
DVD
1 Frame = 2064B = 4B + 2B + 6B + 2048B + 4B
1 Block = 37856B = 16 Frames + 2752B PO + 2080B PI
16 * 4B EDC + 2752B PO + 2080B PI = 4836 bytes of CRC/RSPC per 32768 bytes User Data
4836B CRC/RSPC per 32768B < 788B CIRC/CRC/RSPC per 2048B
If this is correct, then CD-ROM Mode 1 uses relatively more bytes for EDC/ECC than DVD. Therefore it looks like CD-ROM Mode 1 has superior error correction over DVDs. But the following sources state otherwise:
[DVD] error correction is superior to CD and covers blocks at a time, so over 32 KB instead of 2 KB.
DVD uses only one level of error detection and correction code. Even with only one level of error detection and correction code, a BER of 10^15 can be achieved, which is [...] slightly better than CD-ROM Mode 1.
Is the DVD error protection scheme, while being simpler, really able to achieve a better BER (Bit Error Rate) than CD-ROM Mode 1? If so, then how is this possible?
dvd compact-disc data-integrity cd-r error-correction
asked Feb 18 at 16:02
FPUFPU
286
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CD-ROM Mode 1
98 (24B) Frames = 1 Block = 2352 bytes. Every Frame is protected by 8 Parity bytes.
These 8 bytes, the 1st level of error correction, are CIRC generated. CD-ROM Mode 1 also adds a 2nd level of error correction, within each Block: 4 bytes to perform CRC to detect errors and 276 bytes, generated by RSPC, to detect and correct errors.
12B + 4B + 2048B + 4B + 8B + 276B = 2352B
So, CD-ROM mode 1 uses 2 levels of error correction.
Level 1: every Frame is protected by 8B Parity, just like CD-DA.
Level 2: within each block, 2048B User Date is protected by 4B EDC and 276B ECC.
98 * 8B Parity + 4B EDC + 276B ECC = 788 bytes of CIRC/CRC/RSPC per 2048 bytes User Data
DVD
1 Frame = 2064B = 4B + 2B + 6B + 2048B + 4B
1 Block = 37856B = 16 Frames + 2752B PO + 2080B PI
16 * 4B EDC + 2752B PO + 2080B PI = 4836 bytes of CRC/RSPC per 32768 bytes User Data
4836B CRC/RSPC per 32768B < 788B CIRC/CRC/RSPC per 2048B
If this is correct, then CD-ROM Mode 1 uses relatively more bytes for EDC/ECC than DVD. Therefore it looks like CD-ROM Mode 1 has superior error correction over DVDs. But the following sources state otherwise:
[DVD] error correction is superior to CD and covers blocks at a time, so over 32 KB instead of 2 KB.
DVD uses only one level of error detection and correction code. Even with only one level of error detection and correction code, a BER of 10^15 can be achieved, which is [...] slightly better than CD-ROM Mode 1.
Is the DVD error protection scheme, while being simpler, really able to achieve a better BER (Bit Error Rate) than CD-ROM Mode 1? If so, then how is this possible?
dvd compact-disc data-integrity cd-r error-correction
asked Feb 18 at 16:02
FPUFPU
286
add a comment |
CD-ROM Mode 1
98 (24B) Frames = 1 Block = 2352 bytes. Every Frame is protected by 8 Parity bytes.
These 8 bytes, the 1st level of error correction, are CIRC generated. CD-ROM Mode 1 also adds a 2nd level of error correction, within each Block: 4 bytes to perform CRC to detect errors and 276 bytes, generated by RSPC, to detect and correct errors.
12B + 4B + 2048B + 4B + 8B + 276B = 2352B
So, CD-ROM mode 1 uses 2 levels of error correction.
Level 1: every Frame is protected by 8B Parity, just like CD-DA.
Level 2: within each block, 2048B User Date is protected by 4B EDC and 276B ECC.
98 * 8B Parity + 4B EDC + 276B ECC = 788 bytes of CIRC/CRC/RSPC per 2048 bytes User Data
DVD
1 Frame = 2064B = 4B + 2B + 6B + 2048B + 4B
1 Block = 37856B = 16 Frames + 2752B PO + 2080B PI
16 * 4B EDC + 2752B PO + 2080B PI = 4836 bytes of CRC/RSPC per 32768 bytes User Data
4836B CRC/RSPC per 32768B < 788B CIRC/CRC/RSPC per 2048B
If this is correct, then CD-ROM Mode 1 uses relatively more bytes for EDC/ECC than DVD. Therefore it looks like CD-ROM Mode 1 has superior error correction over DVDs. But the following sources state otherwise:
[DVD] error correction is superior to CD and covers blocks at a time, so over 32 KB instead of 2 KB.
DVD uses only one level of error detection and correction code. Even with only one level of error detection and correction code, a BER of 10^15 can be achieved, which is [...] slightly better than CD-ROM Mode 1.
Is the DVD error protection scheme, while being simpler, really able to achieve a better BER (Bit Error Rate) than CD-ROM Mode 1? If so, then how is this possible?
dvd compact-disc data-integrity cd-r error-correction
asked Feb 18 at 16:02
FPUFPU
286
CD-ROM Mode 1
98 (24B) Frames = 1 Block = 2352 bytes. Every Frame is protected by 8 Parity bytes.
These 8 bytes, the 1st level of error correction, are CIRC generated. CD-ROM Mode 1 also adds a 2nd level of error correction, within each Block: 4 bytes to perform CRC to detect errors and 276 bytes, generated by RSPC, to detect and correct errors.
12B + 4B + 2048B + 4B + 8B + 276B = 2352B
So, CD-ROM mode 1 uses 2 levels of error correction.
Level 1: every Frame is protected by 8B Parity, just like CD-DA.
Level 2: within each block, 2048B User Date is protected by 4B EDC and 276B ECC.
98 * 8B Parity + 4B EDC + 276B ECC = 788 bytes of CIRC/CRC/RSPC per 2048 bytes User Data
DVD
1 Frame = 2064B = 4B + 2B + 6B + 2048B + 4B
1 Block = 37856B = 16 Frames + 2752B PO + 2080B PI
16 * 4B EDC + 2752B PO + 2080B PI = 4836 bytes of CRC/RSPC per 32768 bytes User Data
4836B CRC/RSPC per 32768B < 788B CIRC/CRC/RSPC per 2048B
If this is correct, then CD-ROM Mode 1 uses relatively more bytes for EDC/ECC than DVD. Therefore it looks like CD-ROM Mode 1 has superior error correction over DVDs. But the following sources state otherwise:
[DVD] error correction is superior to CD and covers blocks at a time, so over 32 KB instead of 2 KB.
DVD uses only one level of error detection and correction code. Even with only one level of error detection and correction code, a BER of 10^15 can be achieved, which is [...] slightly better than CD-ROM Mode 1.
Is the DVD error protection scheme, while being simpler, really able to achieve a better BER (Bit Error Rate) than CD-ROM Mode 1? If so, then how is this possible?
dvd compact-disc data-integrity cd-r error-correction
dvd compact-disc data-integrity cd-r error-correction
asked Feb 18 at 16:02
FPUFPU
286
asked Feb 18 at 16:02
FPUFPU
286
edited Feb 18 at 16:12
FPU
asked Feb 18 at 16:02
FPUFPU
286
asked Feb 18 at 16:02
FPUFPU
286
asked Feb 18 at 16:02
FPUFPU
286
286
add a comment |
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