Monotonicity property of expectation

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Let $X$ and $Y$ be random variables such that whenever $Xle Y$ we have $f(X)ge f(Y)$, where $f$ is some function on the domain of the random variables (i don't think you'd need any properties of $f$ for this...)
Then, if it holds that $E[X]le E[Y]$, is it true that $E[f(X)]ge E[f(Y)]$. Intuitively this seems like it should be true, but I can't formalize it. If the statement is false as it is, are there conditions under which it would hold?










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    1












    $begingroup$


    Let $X$ and $Y$ be random variables such that whenever $Xle Y$ we have $f(X)ge f(Y)$, where $f$ is some function on the domain of the random variables (i don't think you'd need any properties of $f$ for this...)
    Then, if it holds that $E[X]le E[Y]$, is it true that $E[f(X)]ge E[f(Y)]$. Intuitively this seems like it should be true, but I can't formalize it. If the statement is false as it is, are there conditions under which it would hold?










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      Let $X$ and $Y$ be random variables such that whenever $Xle Y$ we have $f(X)ge f(Y)$, where $f$ is some function on the domain of the random variables (i don't think you'd need any properties of $f$ for this...)
      Then, if it holds that $E[X]le E[Y]$, is it true that $E[f(X)]ge E[f(Y)]$. Intuitively this seems like it should be true, but I can't formalize it. If the statement is false as it is, are there conditions under which it would hold?










      share|cite|improve this question









      $endgroup$




      Let $X$ and $Y$ be random variables such that whenever $Xle Y$ we have $f(X)ge f(Y)$, where $f$ is some function on the domain of the random variables (i don't think you'd need any properties of $f$ for this...)
      Then, if it holds that $E[X]le E[Y]$, is it true that $E[f(X)]ge E[f(Y)]$. Intuitively this seems like it should be true, but I can't formalize it. If the statement is false as it is, are there conditions under which it would hold?







      probability expected-value






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      asked Dec 1 '18 at 23:41









      user114743user114743

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