Multiple index repetition in Einstein notation












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My textbook says that $(X_1)^2 +(X_2)^2+(X_3)^2$ would be written $X_i cdot X_i$ in Einstein notation. It also says that you can only have 2 of the same index. But what if I wanted to express $(X_1)^3 +(X_2)^3+(X_3)^3$



Automatically, I would want to write $X_i cdot X_icdot X_i$, but this is not allowed.



Why does Einstein notation not allow an index to be repeated three times?
Is there some sort of ambiguity that it would cause?










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    $begingroup$


    My textbook says that $(X_1)^2 +(X_2)^2+(X_3)^2$ would be written $X_i cdot X_i$ in Einstein notation. It also says that you can only have 2 of the same index. But what if I wanted to express $(X_1)^3 +(X_2)^3+(X_3)^3$



    Automatically, I would want to write $X_i cdot X_icdot X_i$, but this is not allowed.



    Why does Einstein notation not allow an index to be repeated three times?
    Is there some sort of ambiguity that it would cause?










    share|cite|improve this question











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      0








      0





      $begingroup$


      My textbook says that $(X_1)^2 +(X_2)^2+(X_3)^2$ would be written $X_i cdot X_i$ in Einstein notation. It also says that you can only have 2 of the same index. But what if I wanted to express $(X_1)^3 +(X_2)^3+(X_3)^3$



      Automatically, I would want to write $X_i cdot X_icdot X_i$, but this is not allowed.



      Why does Einstein notation not allow an index to be repeated three times?
      Is there some sort of ambiguity that it would cause?










      share|cite|improve this question











      $endgroup$




      My textbook says that $(X_1)^2 +(X_2)^2+(X_3)^2$ would be written $X_i cdot X_i$ in Einstein notation. It also says that you can only have 2 of the same index. But what if I wanted to express $(X_1)^3 +(X_2)^3+(X_3)^3$



      Automatically, I would want to write $X_i cdot X_icdot X_i$, but this is not allowed.



      Why does Einstein notation not allow an index to be repeated three times?
      Is there some sort of ambiguity that it would cause?







      tensors






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      edited Dec 25 '18 at 5:08







      Ion Sme

















      asked Dec 24 '18 at 5:17









      Ion SmeIon Sme

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          The reason for that not being allowed is that the result is not a tensor. It doesn't transform in a good way when the coordinate system is changed.






          share|cite|improve this answer









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            $begingroup$

            The reason for that not being allowed is that the result is not a tensor. It doesn't transform in a good way when the coordinate system is changed.






            share|cite|improve this answer









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              0












              $begingroup$

              The reason for that not being allowed is that the result is not a tensor. It doesn't transform in a good way when the coordinate system is changed.






              share|cite|improve this answer









              $endgroup$
















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                $begingroup$

                The reason for that not being allowed is that the result is not a tensor. It doesn't transform in a good way when the coordinate system is changed.






                share|cite|improve this answer









                $endgroup$



                The reason for that not being allowed is that the result is not a tensor. It doesn't transform in a good way when the coordinate system is changed.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 24 '18 at 10:20









                md2perpemd2perpe

                8,22111028




                8,22111028






























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