Setting flag column depending on whether column contains a given string












12














Can anyone see why this isn't working?



Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1



df.loc[df['Name'].str.contains(['Andy']),'Andy']=1









share|improve this question
























  • If you are planning to do this for other names then consider get_dummies method pandas.pydata.org/pandas-docs/stable/generated/…
    – shantanuo
    Dec 16 at 14:01
















12














Can anyone see why this isn't working?



Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1



df.loc[df['Name'].str.contains(['Andy']),'Andy']=1









share|improve this question
























  • If you are planning to do this for other names then consider get_dummies method pandas.pydata.org/pandas-docs/stable/generated/…
    – shantanuo
    Dec 16 at 14:01














12












12








12







Can anyone see why this isn't working?



Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1



df.loc[df['Name'].str.contains(['Andy']),'Andy']=1









share|improve this question















Can anyone see why this isn't working?



Its trying to do; if Column Name Contains the text 'Andy', then make a column called Andy and set that row = to 1



df.loc[df['Name'].str.contains(['Andy']),'Andy']=1






python string pandas series






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 14 at 9:32

























asked Dec 13 at 9:25









fred.schwartz

2958




2958












  • If you are planning to do this for other names then consider get_dummies method pandas.pydata.org/pandas-docs/stable/generated/…
    – shantanuo
    Dec 16 at 14:01


















  • If you are planning to do this for other names then consider get_dummies method pandas.pydata.org/pandas-docs/stable/generated/…
    – shantanuo
    Dec 16 at 14:01
















If you are planning to do this for other names then consider get_dummies method pandas.pydata.org/pandas-docs/stable/generated/…
– shantanuo
Dec 16 at 14:01




If you are planning to do this for other names then consider get_dummies method pandas.pydata.org/pandas-docs/stable/generated/…
– shantanuo
Dec 16 at 14:01












2 Answers
2






active

oldest

votes


















8














You have to remove list, need only string:



df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1


For multiple values chain by |:



df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1





share|improve this answer





























    5














    pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.



    Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:



    # Name includes 'Andy'
    df['Andy'] = df['Name'].str.contains('Andy').astype(int)

    # Name includes 'Andy' or 'George'
    df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)





    share|improve this answer





















    • @fred.Schwartz, Yes, that's not valid regex for what you want. That's a separate question.
      – jpp
      Dec 14 at 9:31













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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    8














    You have to remove list, need only string:



    df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1


    For multiple values chain by |:



    df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1





    share|improve this answer


























      8














      You have to remove list, need only string:



      df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1


      For multiple values chain by |:



      df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1





      share|improve this answer
























        8












        8








        8






        You have to remove list, need only string:



        df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1


        For multiple values chain by |:



        df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1





        share|improve this answer












        You have to remove list, need only string:



        df.loc[df['Name'].str.contains('Andy'),'Andy'] = 1


        For multiple values chain by |:



        df.loc[df['Name'].str.contains('Andy|George'),'Andy'] = 1






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 13 at 9:30









        jezrael

        319k22258337




        319k22258337

























            5














            pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.



            Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:



            # Name includes 'Andy'
            df['Andy'] = df['Name'].str.contains('Andy').astype(int)

            # Name includes 'Andy' or 'George'
            df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)





            share|improve this answer





















            • @fred.Schwartz, Yes, that's not valid regex for what you want. That's a separate question.
              – jpp
              Dec 14 at 9:31


















            5














            pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.



            Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:



            # Name includes 'Andy'
            df['Andy'] = df['Name'].str.contains('Andy').astype(int)

            # Name includes 'Andy' or 'George'
            df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)





            share|improve this answer





















            • @fred.Schwartz, Yes, that's not valid regex for what you want. That's a separate question.
              – jpp
              Dec 14 at 9:31
















            5












            5








            5






            pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.



            Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:



            # Name includes 'Andy'
            df['Andy'] = df['Name'].str.contains('Andy').astype(int)

            # Name includes 'Andy' or 'George'
            df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)





            share|improve this answer












            pd.Series.str.contains requires for its pat argument a "Character sequence or regular expression", not a list.



            Just use Boolean assignment and convert to int. This will set unmatched rows to 0. For example:



            # Name includes 'Andy'
            df['Andy'] = df['Name'].str.contains('Andy').astype(int)

            # Name includes 'Andy' or 'George'
            df['Andy'] = df['Name'].str.contains('Andy|George').astype(int)






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Dec 13 at 9:46









            jpp

            90.4k2052101




            90.4k2052101












            • @fred.Schwartz, Yes, that's not valid regex for what you want. That's a separate question.
              – jpp
              Dec 14 at 9:31




















            • @fred.Schwartz, Yes, that's not valid regex for what you want. That's a separate question.
              – jpp
              Dec 14 at 9:31


















            @fred.Schwartz, Yes, that's not valid regex for what you want. That's a separate question.
            – jpp
            Dec 14 at 9:31






            @fred.Schwartz, Yes, that's not valid regex for what you want. That's a separate question.
            – jpp
            Dec 14 at 9:31




















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