Why does my bumper scrape when driving fast over a bump but not slow?











up vote
17
down vote

favorite
3












When driving my car over a bump or a quick change in gradient (from flat to uphill or downhill to flat), if I don't drive slowly and the bump/change in gradient is large enough, I'll end up with my front bumper dragging on the road/bump. But if I go slowly, there's no such issue.



I would expect that the wheels are still taking the same path regardless of the speed, so the car's body should also act the same regardless. Why does it make a difference when speed is changed? Why doesn't the car behave the same way regardless?










share|cite|improve this question









New contributor




scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • youtube.com/watch?v=UB9gA9Af5Tw
    – Jasper
    yesterday















up vote
17
down vote

favorite
3












When driving my car over a bump or a quick change in gradient (from flat to uphill or downhill to flat), if I don't drive slowly and the bump/change in gradient is large enough, I'll end up with my front bumper dragging on the road/bump. But if I go slowly, there's no such issue.



I would expect that the wheels are still taking the same path regardless of the speed, so the car's body should also act the same regardless. Why does it make a difference when speed is changed? Why doesn't the car behave the same way regardless?










share|cite|improve this question









New contributor




scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • youtube.com/watch?v=UB9gA9Af5Tw
    – Jasper
    yesterday













up vote
17
down vote

favorite
3









up vote
17
down vote

favorite
3






3





When driving my car over a bump or a quick change in gradient (from flat to uphill or downhill to flat), if I don't drive slowly and the bump/change in gradient is large enough, I'll end up with my front bumper dragging on the road/bump. But if I go slowly, there's no such issue.



I would expect that the wheels are still taking the same path regardless of the speed, so the car's body should also act the same regardless. Why does it make a difference when speed is changed? Why doesn't the car behave the same way regardless?










share|cite|improve this question









New contributor




scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











When driving my car over a bump or a quick change in gradient (from flat to uphill or downhill to flat), if I don't drive slowly and the bump/change in gradient is large enough, I'll end up with my front bumper dragging on the road/bump. But if I go slowly, there's no such issue.



I would expect that the wheels are still taking the same path regardless of the speed, so the car's body should also act the same regardless. Why does it make a difference when speed is changed? Why doesn't the car behave the same way regardless?







newtonian-mechanics everyday-life collision spring






share|cite|improve this question









New contributor




scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 17 hours ago









Qmechanic

99.2k121781104




99.2k121781104






New contributor




scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









scohe001

197111




197111




New contributor




scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






scohe001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • youtube.com/watch?v=UB9gA9Af5Tw
    – Jasper
    yesterday


















  • youtube.com/watch?v=UB9gA9Af5Tw
    – Jasper
    yesterday
















youtube.com/watch?v=UB9gA9Af5Tw
– Jasper
yesterday




youtube.com/watch?v=UB9gA9Af5Tw
– Jasper
yesterday










4 Answers
4






active

oldest

votes

















up vote
14
down vote



accepted










I think that physics.SE deserves an answer in physics terminology.



Change of direction = acceleration. Acceleration is caused by force. Force is applied through suspension and compresses it.



Larger speeds lead to larger acceleration and larger force which in turn compresses the spring more.



To be a bit more precise, we could model the upwards curve as consisting of arc segments. It would mean that at the segment with curvature radius $r$ the acceleration is $v^2/r$ and the force is $mv^2/r$. If we suppose the spring is linear, the compression will equal force over the spring constant - $frac{mv^2}{rk}$.



Disclaimer: the spring is probably not linear, it should become increasingly high-degree-polynomial near the extremes of it's range (i.e. it should try to stop itself from compressing too much). The $m$ is not the mass of the car but something like the portion that rests on the axis in question. Which depends on multiple factors including the road curvature and the absolute acceleration of car. And the $r$ is not the curvature radius of the road but that of the car's body. Suspension is intended exactly to make it less than the curvature of the road - smoothen the bump.






share|cite|improve this answer

















  • 2




    Car suspension is designed to be pretty close to linear across the entire motion ratio, so it's a valid assumption to make - also +1 for being the only answer to mention the velocity squared part, as that's the key issue I see - the question's assumption about the car's wheels and body taking the same path is false
    – user2813274
    20 hours ago










  • Awesome explanation. The v^2 relationship specifically explains why there's such a big difference in just a few mph.
    – scohe001
    2 hours ago


















up vote
47
down vote













Because your car has a suspension.



A car's wheels are not rigidly attached to the frame. Rather, they are attached with springs and shock absorbers that allow the wheels to move somewhat relative to the rest of the car. This is generally speaking a good thing, as it means that when the wheels go over a small bump or pothole in the road, the frame does not necessarily need to move up and down; and so you, the passenger, get a smoother ride. But if the bumps are large and the speeds are too high, this same "smoothing" effect means that the frame of the car can come into contact with the road surface.



As to why this smoothing effect occurs: imagine that you have, on a table, a large block (standing in for the car), attached by a spring (the suspension) to a smaller block (the wheel.) Suppose that the table is very smooth, so that we can ignore friction between the table and the smaller blocks. If you pull the small block quickly & suddenly away from the larger block, the spring stretches a lot and the large block won't move very much at all: it has a lot of inertia, and so it can't accelerate very quickly. This is the equivalent of going over a bump or pothole at high speed: the wheel suddenly moves up or down relative to the frame, but the frame doesn't move up or down much at all.



But if you pull the small block away from the large block slowly, then the large block will follow the small block, while the spring doesn't stretch terribly much. In this case, the low acceleration of the large mass takes place over a longer time, and so it can move more while the force is being exerted on it. This is the equivalent of going over a bump/pothole at low speed; since the wheels move up or down relatively slowly, the frame of the car will follow them. If you go over a bump at low speed, this means that the frame will follow the wheels (which follow the road surface), rather than moving in something resembling a straight line and possibly hitting the road surface.






share|cite|improve this answer



















  • 1




    Also worth pointing out that suspensions can behave differently depending on the stiffness of the springs. Cars that are low to the ground need to have a relatively stiff suspension to prevent bottoming out, since there's little room for the spring to travel. Vehicles that ride higher can have a softer suspension that absorbs more bumps without dragging the chassis on the ground. It's a smoother ride, but can also make the car less responsive as steering input is dampened by the shocks.
    – Nuclear Wang
    4 hours ago










  • I really wish I could accept 2 answers. Your thought experiment is perfect, but I was hoping for a more physics answer, so I'm going with Džuris'. Thanks for the great answer!!
    – scohe001
    2 hours ago


















up vote
3
down vote













In order to avoid the issue, your car needs to be lifted over the bump. In the case of fast motion, this has to occur in a shorter time span, hence with a higher acceleration, hence with greater force - and this force has to be transferred from the ground via your wheels to the car body. However, the positional relation between your tires and the car body is governed by springs and shock absorbers, which are compressed under strong forces. Additionally, your tire bottom may be compressed for the same reason. It follows that the car body moves closer to the bump than it would in slow motion.



You could avoid this phenomenon by getting rid of all springs and dampers (and also the air-filled tires) and replacing them with rigid connections. In that case, the car body would be accelerated quite suddenly with great force at the bump - probably resulting in structural failure! There's a reason why these elastic elements are built into your car after all ...






share|cite|improve this answer






























    up vote
    1
    down vote













    Shocks have time factor. They will absorb more if the change is rapid. This is by design as your body and car do not want a rapid impact.



    I believe springs also have a time factor.






    share|cite|improve this answer





















      Your Answer





      StackExchange.ifUsing("editor", function () {
      return StackExchange.using("mathjaxEditing", function () {
      StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
      StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
      });
      });
      }, "mathjax-editing");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "151"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      convertImagesToLinks: false,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: null,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      noCode: true, onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });






      scohe001 is a new contributor. Be nice, and check out our Code of Conduct.










       

      draft saved


      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f440510%2fwhy-does-my-bumper-scrape-when-driving-fast-over-a-bump-but-not-slow%23new-answer', 'question_page');
      }
      );

      Post as a guest
































      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      14
      down vote



      accepted










      I think that physics.SE deserves an answer in physics terminology.



      Change of direction = acceleration. Acceleration is caused by force. Force is applied through suspension and compresses it.



      Larger speeds lead to larger acceleration and larger force which in turn compresses the spring more.



      To be a bit more precise, we could model the upwards curve as consisting of arc segments. It would mean that at the segment with curvature radius $r$ the acceleration is $v^2/r$ and the force is $mv^2/r$. If we suppose the spring is linear, the compression will equal force over the spring constant - $frac{mv^2}{rk}$.



      Disclaimer: the spring is probably not linear, it should become increasingly high-degree-polynomial near the extremes of it's range (i.e. it should try to stop itself from compressing too much). The $m$ is not the mass of the car but something like the portion that rests on the axis in question. Which depends on multiple factors including the road curvature and the absolute acceleration of car. And the $r$ is not the curvature radius of the road but that of the car's body. Suspension is intended exactly to make it less than the curvature of the road - smoothen the bump.






      share|cite|improve this answer

















      • 2




        Car suspension is designed to be pretty close to linear across the entire motion ratio, so it's a valid assumption to make - also +1 for being the only answer to mention the velocity squared part, as that's the key issue I see - the question's assumption about the car's wheels and body taking the same path is false
        – user2813274
        20 hours ago










      • Awesome explanation. The v^2 relationship specifically explains why there's such a big difference in just a few mph.
        – scohe001
        2 hours ago















      up vote
      14
      down vote



      accepted










      I think that physics.SE deserves an answer in physics terminology.



      Change of direction = acceleration. Acceleration is caused by force. Force is applied through suspension and compresses it.



      Larger speeds lead to larger acceleration and larger force which in turn compresses the spring more.



      To be a bit more precise, we could model the upwards curve as consisting of arc segments. It would mean that at the segment with curvature radius $r$ the acceleration is $v^2/r$ and the force is $mv^2/r$. If we suppose the spring is linear, the compression will equal force over the spring constant - $frac{mv^2}{rk}$.



      Disclaimer: the spring is probably not linear, it should become increasingly high-degree-polynomial near the extremes of it's range (i.e. it should try to stop itself from compressing too much). The $m$ is not the mass of the car but something like the portion that rests on the axis in question. Which depends on multiple factors including the road curvature and the absolute acceleration of car. And the $r$ is not the curvature radius of the road but that of the car's body. Suspension is intended exactly to make it less than the curvature of the road - smoothen the bump.






      share|cite|improve this answer

















      • 2




        Car suspension is designed to be pretty close to linear across the entire motion ratio, so it's a valid assumption to make - also +1 for being the only answer to mention the velocity squared part, as that's the key issue I see - the question's assumption about the car's wheels and body taking the same path is false
        – user2813274
        20 hours ago










      • Awesome explanation. The v^2 relationship specifically explains why there's such a big difference in just a few mph.
        – scohe001
        2 hours ago













      up vote
      14
      down vote



      accepted







      up vote
      14
      down vote



      accepted






      I think that physics.SE deserves an answer in physics terminology.



      Change of direction = acceleration. Acceleration is caused by force. Force is applied through suspension and compresses it.



      Larger speeds lead to larger acceleration and larger force which in turn compresses the spring more.



      To be a bit more precise, we could model the upwards curve as consisting of arc segments. It would mean that at the segment with curvature radius $r$ the acceleration is $v^2/r$ and the force is $mv^2/r$. If we suppose the spring is linear, the compression will equal force over the spring constant - $frac{mv^2}{rk}$.



      Disclaimer: the spring is probably not linear, it should become increasingly high-degree-polynomial near the extremes of it's range (i.e. it should try to stop itself from compressing too much). The $m$ is not the mass of the car but something like the portion that rests on the axis in question. Which depends on multiple factors including the road curvature and the absolute acceleration of car. And the $r$ is not the curvature radius of the road but that of the car's body. Suspension is intended exactly to make it less than the curvature of the road - smoothen the bump.






      share|cite|improve this answer












      I think that physics.SE deserves an answer in physics terminology.



      Change of direction = acceleration. Acceleration is caused by force. Force is applied through suspension and compresses it.



      Larger speeds lead to larger acceleration and larger force which in turn compresses the spring more.



      To be a bit more precise, we could model the upwards curve as consisting of arc segments. It would mean that at the segment with curvature radius $r$ the acceleration is $v^2/r$ and the force is $mv^2/r$. If we suppose the spring is linear, the compression will equal force over the spring constant - $frac{mv^2}{rk}$.



      Disclaimer: the spring is probably not linear, it should become increasingly high-degree-polynomial near the extremes of it's range (i.e. it should try to stop itself from compressing too much). The $m$ is not the mass of the car but something like the portion that rests on the axis in question. Which depends on multiple factors including the road curvature and the absolute acceleration of car. And the $r$ is not the curvature radius of the road but that of the car's body. Suspension is intended exactly to make it less than the curvature of the road - smoothen the bump.







      share|cite|improve this answer












      share|cite|improve this answer



      share|cite|improve this answer










      answered 20 hours ago









      Džuris

      1,80711228




      1,80711228








      • 2




        Car suspension is designed to be pretty close to linear across the entire motion ratio, so it's a valid assumption to make - also +1 for being the only answer to mention the velocity squared part, as that's the key issue I see - the question's assumption about the car's wheels and body taking the same path is false
        – user2813274
        20 hours ago










      • Awesome explanation. The v^2 relationship specifically explains why there's such a big difference in just a few mph.
        – scohe001
        2 hours ago














      • 2




        Car suspension is designed to be pretty close to linear across the entire motion ratio, so it's a valid assumption to make - also +1 for being the only answer to mention the velocity squared part, as that's the key issue I see - the question's assumption about the car's wheels and body taking the same path is false
        – user2813274
        20 hours ago










      • Awesome explanation. The v^2 relationship specifically explains why there's such a big difference in just a few mph.
        – scohe001
        2 hours ago








      2




      2




      Car suspension is designed to be pretty close to linear across the entire motion ratio, so it's a valid assumption to make - also +1 for being the only answer to mention the velocity squared part, as that's the key issue I see - the question's assumption about the car's wheels and body taking the same path is false
      – user2813274
      20 hours ago




      Car suspension is designed to be pretty close to linear across the entire motion ratio, so it's a valid assumption to make - also +1 for being the only answer to mention the velocity squared part, as that's the key issue I see - the question's assumption about the car's wheels and body taking the same path is false
      – user2813274
      20 hours ago












      Awesome explanation. The v^2 relationship specifically explains why there's such a big difference in just a few mph.
      – scohe001
      2 hours ago




      Awesome explanation. The v^2 relationship specifically explains why there's such a big difference in just a few mph.
      – scohe001
      2 hours ago










      up vote
      47
      down vote













      Because your car has a suspension.



      A car's wheels are not rigidly attached to the frame. Rather, they are attached with springs and shock absorbers that allow the wheels to move somewhat relative to the rest of the car. This is generally speaking a good thing, as it means that when the wheels go over a small bump or pothole in the road, the frame does not necessarily need to move up and down; and so you, the passenger, get a smoother ride. But if the bumps are large and the speeds are too high, this same "smoothing" effect means that the frame of the car can come into contact with the road surface.



      As to why this smoothing effect occurs: imagine that you have, on a table, a large block (standing in for the car), attached by a spring (the suspension) to a smaller block (the wheel.) Suppose that the table is very smooth, so that we can ignore friction between the table and the smaller blocks. If you pull the small block quickly & suddenly away from the larger block, the spring stretches a lot and the large block won't move very much at all: it has a lot of inertia, and so it can't accelerate very quickly. This is the equivalent of going over a bump or pothole at high speed: the wheel suddenly moves up or down relative to the frame, but the frame doesn't move up or down much at all.



      But if you pull the small block away from the large block slowly, then the large block will follow the small block, while the spring doesn't stretch terribly much. In this case, the low acceleration of the large mass takes place over a longer time, and so it can move more while the force is being exerted on it. This is the equivalent of going over a bump/pothole at low speed; since the wheels move up or down relatively slowly, the frame of the car will follow them. If you go over a bump at low speed, this means that the frame will follow the wheels (which follow the road surface), rather than moving in something resembling a straight line and possibly hitting the road surface.






      share|cite|improve this answer



















      • 1




        Also worth pointing out that suspensions can behave differently depending on the stiffness of the springs. Cars that are low to the ground need to have a relatively stiff suspension to prevent bottoming out, since there's little room for the spring to travel. Vehicles that ride higher can have a softer suspension that absorbs more bumps without dragging the chassis on the ground. It's a smoother ride, but can also make the car less responsive as steering input is dampened by the shocks.
        – Nuclear Wang
        4 hours ago










      • I really wish I could accept 2 answers. Your thought experiment is perfect, but I was hoping for a more physics answer, so I'm going with Džuris'. Thanks for the great answer!!
        – scohe001
        2 hours ago















      up vote
      47
      down vote













      Because your car has a suspension.



      A car's wheels are not rigidly attached to the frame. Rather, they are attached with springs and shock absorbers that allow the wheels to move somewhat relative to the rest of the car. This is generally speaking a good thing, as it means that when the wheels go over a small bump or pothole in the road, the frame does not necessarily need to move up and down; and so you, the passenger, get a smoother ride. But if the bumps are large and the speeds are too high, this same "smoothing" effect means that the frame of the car can come into contact with the road surface.



      As to why this smoothing effect occurs: imagine that you have, on a table, a large block (standing in for the car), attached by a spring (the suspension) to a smaller block (the wheel.) Suppose that the table is very smooth, so that we can ignore friction between the table and the smaller blocks. If you pull the small block quickly & suddenly away from the larger block, the spring stretches a lot and the large block won't move very much at all: it has a lot of inertia, and so it can't accelerate very quickly. This is the equivalent of going over a bump or pothole at high speed: the wheel suddenly moves up or down relative to the frame, but the frame doesn't move up or down much at all.



      But if you pull the small block away from the large block slowly, then the large block will follow the small block, while the spring doesn't stretch terribly much. In this case, the low acceleration of the large mass takes place over a longer time, and so it can move more while the force is being exerted on it. This is the equivalent of going over a bump/pothole at low speed; since the wheels move up or down relatively slowly, the frame of the car will follow them. If you go over a bump at low speed, this means that the frame will follow the wheels (which follow the road surface), rather than moving in something resembling a straight line and possibly hitting the road surface.






      share|cite|improve this answer



















      • 1




        Also worth pointing out that suspensions can behave differently depending on the stiffness of the springs. Cars that are low to the ground need to have a relatively stiff suspension to prevent bottoming out, since there's little room for the spring to travel. Vehicles that ride higher can have a softer suspension that absorbs more bumps without dragging the chassis on the ground. It's a smoother ride, but can also make the car less responsive as steering input is dampened by the shocks.
        – Nuclear Wang
        4 hours ago










      • I really wish I could accept 2 answers. Your thought experiment is perfect, but I was hoping for a more physics answer, so I'm going with Džuris'. Thanks for the great answer!!
        – scohe001
        2 hours ago













      up vote
      47
      down vote










      up vote
      47
      down vote









      Because your car has a suspension.



      A car's wheels are not rigidly attached to the frame. Rather, they are attached with springs and shock absorbers that allow the wheels to move somewhat relative to the rest of the car. This is generally speaking a good thing, as it means that when the wheels go over a small bump or pothole in the road, the frame does not necessarily need to move up and down; and so you, the passenger, get a smoother ride. But if the bumps are large and the speeds are too high, this same "smoothing" effect means that the frame of the car can come into contact with the road surface.



      As to why this smoothing effect occurs: imagine that you have, on a table, a large block (standing in for the car), attached by a spring (the suspension) to a smaller block (the wheel.) Suppose that the table is very smooth, so that we can ignore friction between the table and the smaller blocks. If you pull the small block quickly & suddenly away from the larger block, the spring stretches a lot and the large block won't move very much at all: it has a lot of inertia, and so it can't accelerate very quickly. This is the equivalent of going over a bump or pothole at high speed: the wheel suddenly moves up or down relative to the frame, but the frame doesn't move up or down much at all.



      But if you pull the small block away from the large block slowly, then the large block will follow the small block, while the spring doesn't stretch terribly much. In this case, the low acceleration of the large mass takes place over a longer time, and so it can move more while the force is being exerted on it. This is the equivalent of going over a bump/pothole at low speed; since the wheels move up or down relatively slowly, the frame of the car will follow them. If you go over a bump at low speed, this means that the frame will follow the wheels (which follow the road surface), rather than moving in something resembling a straight line and possibly hitting the road surface.






      share|cite|improve this answer














      Because your car has a suspension.



      A car's wheels are not rigidly attached to the frame. Rather, they are attached with springs and shock absorbers that allow the wheels to move somewhat relative to the rest of the car. This is generally speaking a good thing, as it means that when the wheels go over a small bump or pothole in the road, the frame does not necessarily need to move up and down; and so you, the passenger, get a smoother ride. But if the bumps are large and the speeds are too high, this same "smoothing" effect means that the frame of the car can come into contact with the road surface.



      As to why this smoothing effect occurs: imagine that you have, on a table, a large block (standing in for the car), attached by a spring (the suspension) to a smaller block (the wheel.) Suppose that the table is very smooth, so that we can ignore friction between the table and the smaller blocks. If you pull the small block quickly & suddenly away from the larger block, the spring stretches a lot and the large block won't move very much at all: it has a lot of inertia, and so it can't accelerate very quickly. This is the equivalent of going over a bump or pothole at high speed: the wheel suddenly moves up or down relative to the frame, but the frame doesn't move up or down much at all.



      But if you pull the small block away from the large block slowly, then the large block will follow the small block, while the spring doesn't stretch terribly much. In this case, the low acceleration of the large mass takes place over a longer time, and so it can move more while the force is being exerted on it. This is the equivalent of going over a bump/pothole at low speed; since the wheels move up or down relatively slowly, the frame of the car will follow them. If you go over a bump at low speed, this means that the frame will follow the wheels (which follow the road surface), rather than moving in something resembling a straight line and possibly hitting the road surface.







      share|cite|improve this answer














      share|cite|improve this answer



      share|cite|improve this answer








      edited 6 hours ago









      Roger Lipscombe

      1033




      1033










      answered yesterday









      Michael Seifert

      14.3k22752




      14.3k22752








      • 1




        Also worth pointing out that suspensions can behave differently depending on the stiffness of the springs. Cars that are low to the ground need to have a relatively stiff suspension to prevent bottoming out, since there's little room for the spring to travel. Vehicles that ride higher can have a softer suspension that absorbs more bumps without dragging the chassis on the ground. It's a smoother ride, but can also make the car less responsive as steering input is dampened by the shocks.
        – Nuclear Wang
        4 hours ago










      • I really wish I could accept 2 answers. Your thought experiment is perfect, but I was hoping for a more physics answer, so I'm going with Džuris'. Thanks for the great answer!!
        – scohe001
        2 hours ago














      • 1




        Also worth pointing out that suspensions can behave differently depending on the stiffness of the springs. Cars that are low to the ground need to have a relatively stiff suspension to prevent bottoming out, since there's little room for the spring to travel. Vehicles that ride higher can have a softer suspension that absorbs more bumps without dragging the chassis on the ground. It's a smoother ride, but can also make the car less responsive as steering input is dampened by the shocks.
        – Nuclear Wang
        4 hours ago










      • I really wish I could accept 2 answers. Your thought experiment is perfect, but I was hoping for a more physics answer, so I'm going with Džuris'. Thanks for the great answer!!
        – scohe001
        2 hours ago








      1




      1




      Also worth pointing out that suspensions can behave differently depending on the stiffness of the springs. Cars that are low to the ground need to have a relatively stiff suspension to prevent bottoming out, since there's little room for the spring to travel. Vehicles that ride higher can have a softer suspension that absorbs more bumps without dragging the chassis on the ground. It's a smoother ride, but can also make the car less responsive as steering input is dampened by the shocks.
      – Nuclear Wang
      4 hours ago




      Also worth pointing out that suspensions can behave differently depending on the stiffness of the springs. Cars that are low to the ground need to have a relatively stiff suspension to prevent bottoming out, since there's little room for the spring to travel. Vehicles that ride higher can have a softer suspension that absorbs more bumps without dragging the chassis on the ground. It's a smoother ride, but can also make the car less responsive as steering input is dampened by the shocks.
      – Nuclear Wang
      4 hours ago












      I really wish I could accept 2 answers. Your thought experiment is perfect, but I was hoping for a more physics answer, so I'm going with Džuris'. Thanks for the great answer!!
      – scohe001
      2 hours ago




      I really wish I could accept 2 answers. Your thought experiment is perfect, but I was hoping for a more physics answer, so I'm going with Džuris'. Thanks for the great answer!!
      – scohe001
      2 hours ago










      up vote
      3
      down vote













      In order to avoid the issue, your car needs to be lifted over the bump. In the case of fast motion, this has to occur in a shorter time span, hence with a higher acceleration, hence with greater force - and this force has to be transferred from the ground via your wheels to the car body. However, the positional relation between your tires and the car body is governed by springs and shock absorbers, which are compressed under strong forces. Additionally, your tire bottom may be compressed for the same reason. It follows that the car body moves closer to the bump than it would in slow motion.



      You could avoid this phenomenon by getting rid of all springs and dampers (and also the air-filled tires) and replacing them with rigid connections. In that case, the car body would be accelerated quite suddenly with great force at the bump - probably resulting in structural failure! There's a reason why these elastic elements are built into your car after all ...






      share|cite|improve this answer



























        up vote
        3
        down vote













        In order to avoid the issue, your car needs to be lifted over the bump. In the case of fast motion, this has to occur in a shorter time span, hence with a higher acceleration, hence with greater force - and this force has to be transferred from the ground via your wheels to the car body. However, the positional relation between your tires and the car body is governed by springs and shock absorbers, which are compressed under strong forces. Additionally, your tire bottom may be compressed for the same reason. It follows that the car body moves closer to the bump than it would in slow motion.



        You could avoid this phenomenon by getting rid of all springs and dampers (and also the air-filled tires) and replacing them with rigid connections. In that case, the car body would be accelerated quite suddenly with great force at the bump - probably resulting in structural failure! There's a reason why these elastic elements are built into your car after all ...






        share|cite|improve this answer

























          up vote
          3
          down vote










          up vote
          3
          down vote









          In order to avoid the issue, your car needs to be lifted over the bump. In the case of fast motion, this has to occur in a shorter time span, hence with a higher acceleration, hence with greater force - and this force has to be transferred from the ground via your wheels to the car body. However, the positional relation between your tires and the car body is governed by springs and shock absorbers, which are compressed under strong forces. Additionally, your tire bottom may be compressed for the same reason. It follows that the car body moves closer to the bump than it would in slow motion.



          You could avoid this phenomenon by getting rid of all springs and dampers (and also the air-filled tires) and replacing them with rigid connections. In that case, the car body would be accelerated quite suddenly with great force at the bump - probably resulting in structural failure! There's a reason why these elastic elements are built into your car after all ...






          share|cite|improve this answer














          In order to avoid the issue, your car needs to be lifted over the bump. In the case of fast motion, this has to occur in a shorter time span, hence with a higher acceleration, hence with greater force - and this force has to be transferred from the ground via your wheels to the car body. However, the positional relation between your tires and the car body is governed by springs and shock absorbers, which are compressed under strong forces. Additionally, your tire bottom may be compressed for the same reason. It follows that the car body moves closer to the bump than it would in slow motion.



          You could avoid this phenomenon by getting rid of all springs and dampers (and also the air-filled tires) and replacing them with rigid connections. In that case, the car body would be accelerated quite suddenly with great force at the bump - probably resulting in structural failure! There's a reason why these elastic elements are built into your car after all ...







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited 2 hours ago









          SiHa

          1032




          1032










          answered yesterday









          Hagen von Eitzen

          1915




          1915






















              up vote
              1
              down vote













              Shocks have time factor. They will absorb more if the change is rapid. This is by design as your body and car do not want a rapid impact.



              I believe springs also have a time factor.






              share|cite|improve this answer

























                up vote
                1
                down vote













                Shocks have time factor. They will absorb more if the change is rapid. This is by design as your body and car do not want a rapid impact.



                I believe springs also have a time factor.






                share|cite|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  Shocks have time factor. They will absorb more if the change is rapid. This is by design as your body and car do not want a rapid impact.



                  I believe springs also have a time factor.






                  share|cite|improve this answer












                  Shocks have time factor. They will absorb more if the change is rapid. This is by design as your body and car do not want a rapid impact.



                  I believe springs also have a time factor.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered yesterday









                  paparazzo

                  1,165511




                  1,165511






















                      scohe001 is a new contributor. Be nice, and check out our Code of Conduct.










                       

                      draft saved


                      draft discarded


















                      scohe001 is a new contributor. Be nice, and check out our Code of Conduct.













                      scohe001 is a new contributor. Be nice, and check out our Code of Conduct.












                      scohe001 is a new contributor. Be nice, and check out our Code of Conduct.















                       


                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f440510%2fwhy-does-my-bumper-scrape-when-driving-fast-over-a-bump-but-not-slow%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest




















































































                      Popular posts from this blog

                      How do I know what Microsoft account the skydrive app is syncing to?

                      When does type information flow backwards in C++?

                      Grease: Live!