Slice Chart Condition Proof - Topological Embedding











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Below is some background information from Lee's Introduction To Smooth Manifolds about slice charts of embedded submanifolds. My question is at the bottom.





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What I don't understand in the proof is the part highlighted in red. I don't understand how we can conclude that $S$ is a topological embedding from what we proved so far.










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    up vote
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    down vote

    favorite












    Below is some background information from Lee's Introduction To Smooth Manifolds about slice charts of embedded submanifolds. My question is at the bottom.





    enter image description here



    enter image description here



    enter image description here



    enter image description here





    What I don't understand in the proof is the part highlighted in red. I don't understand how we can conclude that $S$ is a topological embedding from what we proved so far.










    share|cite|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Below is some background information from Lee's Introduction To Smooth Manifolds about slice charts of embedded submanifolds. My question is at the bottom.





      enter image description here



      enter image description here



      enter image description here



      enter image description here





      What I don't understand in the proof is the part highlighted in red. I don't understand how we can conclude that $S$ is a topological embedding from what we proved so far.










      share|cite|improve this question















      Below is some background information from Lee's Introduction To Smooth Manifolds about slice charts of embedded submanifolds. My question is at the bottom.





      enter image description here



      enter image description here



      enter image description here



      enter image description here





      What I don't understand in the proof is the part highlighted in red. I don't understand how we can conclude that $S$ is a topological embedding from what we proved so far.







      general-topology differential-geometry manifolds differential-topology smooth-manifolds






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      edited yesterday

























      asked 2 days ago









      Frederic Chopin

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      31218






















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          Up to the point you have highlighted, we have shown that for any point $p$ in $S$, we can define a chart $(psi,V)$, where $V$ is open in $S$ and contains $p$, with $psicolon Vto widehat Vsubset Bbb R^k$ a homeomorphism. The inclusion map $iotacolon Shookrightarrow M$ is a topological embedding because $S$ is given the subspace topology, hence $iota$ is a homeomorphism onto its image.






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            1 Answer
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            active

            oldest

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            Up to the point you have highlighted, we have shown that for any point $p$ in $S$, we can define a chart $(psi,V)$, where $V$ is open in $S$ and contains $p$, with $psicolon Vto widehat Vsubset Bbb R^k$ a homeomorphism. The inclusion map $iotacolon Shookrightarrow M$ is a topological embedding because $S$ is given the subspace topology, hence $iota$ is a homeomorphism onto its image.






            share|cite|improve this answer

























              up vote
              1
              down vote



              accepted










              Up to the point you have highlighted, we have shown that for any point $p$ in $S$, we can define a chart $(psi,V)$, where $V$ is open in $S$ and contains $p$, with $psicolon Vto widehat Vsubset Bbb R^k$ a homeomorphism. The inclusion map $iotacolon Shookrightarrow M$ is a topological embedding because $S$ is given the subspace topology, hence $iota$ is a homeomorphism onto its image.






              share|cite|improve this answer























                up vote
                1
                down vote



                accepted







                up vote
                1
                down vote



                accepted






                Up to the point you have highlighted, we have shown that for any point $p$ in $S$, we can define a chart $(psi,V)$, where $V$ is open in $S$ and contains $p$, with $psicolon Vto widehat Vsubset Bbb R^k$ a homeomorphism. The inclusion map $iotacolon Shookrightarrow M$ is a topological embedding because $S$ is given the subspace topology, hence $iota$ is a homeomorphism onto its image.






                share|cite|improve this answer












                Up to the point you have highlighted, we have shown that for any point $p$ in $S$, we can define a chart $(psi,V)$, where $V$ is open in $S$ and contains $p$, with $psicolon Vto widehat Vsubset Bbb R^k$ a homeomorphism. The inclusion map $iotacolon Shookrightarrow M$ is a topological embedding because $S$ is given the subspace topology, hence $iota$ is a homeomorphism onto its image.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered yesterday









                AOrtiz

                10.3k21239




                10.3k21239






























                     

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