Understanding the definitions of Embedded Surface and Locally Parametrised Embedded Surface
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I recently learned about the definitions of Embedded Surface (ES) and Locally Parametrised Embedded Surface (LEPS) in a lecture of mine. We defined them as follows:
ES: A regular parametrisation $f$ is called an Embedded Surface if for $f:D rightarrow f(D) = S subseteq mathbb{R}^n$ holds:
- For all $uin D$ and for all open $V subseteq D$ with $u in V$ there exists an open $U subseteq mathbb{R}^n$ with $f(u) in U$ such that $U cap S = f(V)$.
LPES: We say $S subseteq mathbb{R}^n$ is a Locally Parametrised Embedded (regular)($k$-dimensional) Surface if for all $x in S$ there exists an open neighbourhood $U subseteq mathbb{R}^n$ of $x$ in $mathbb{R}^n$ and a domain $D subseteq mathbb{R}^k$ as well as a regular parametrisation $f:Drightarrow mathbb{R}^n$ sucht that
$$U cap S = f(D)$$
Regular Parametrisation: Let $D subseteq mathbb{R}^k$ be a domain an $n,k in mathbb{N}$ such that $n ge k$. Now consider the injective function $f: D rightarrow mathbb{R}^n in C^1(D,mathbb{R}^n)$ and assume that it's Jacobian has rank $k$. We call $f$ a regular parametrisation (of a k-dimensional surface in $mathbb{R}^n$).
I got the following questions:
- If I understand these definitions correctly then every ES is also an LPES but the other direction does not hold since an ES requires that $f$ is alwys the same parametrisation for every $x in S$. Is this rigth?
- Are there any intuitive examples of an LPES that is not an ES? I can hardly imagine something such as an LPES in terms of "real-world" geometry.
calculus differential-geometry manifolds surfaces
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I recently learned about the definitions of Embedded Surface (ES) and Locally Parametrised Embedded Surface (LEPS) in a lecture of mine. We defined them as follows:
ES: A regular parametrisation $f$ is called an Embedded Surface if for $f:D rightarrow f(D) = S subseteq mathbb{R}^n$ holds:
- For all $uin D$ and for all open $V subseteq D$ with $u in V$ there exists an open $U subseteq mathbb{R}^n$ with $f(u) in U$ such that $U cap S = f(V)$.
LPES: We say $S subseteq mathbb{R}^n$ is a Locally Parametrised Embedded (regular)($k$-dimensional) Surface if for all $x in S$ there exists an open neighbourhood $U subseteq mathbb{R}^n$ of $x$ in $mathbb{R}^n$ and a domain $D subseteq mathbb{R}^k$ as well as a regular parametrisation $f:Drightarrow mathbb{R}^n$ sucht that
$$U cap S = f(D)$$
Regular Parametrisation: Let $D subseteq mathbb{R}^k$ be a domain an $n,k in mathbb{N}$ such that $n ge k$. Now consider the injective function $f: D rightarrow mathbb{R}^n in C^1(D,mathbb{R}^n)$ and assume that it's Jacobian has rank $k$. We call $f$ a regular parametrisation (of a k-dimensional surface in $mathbb{R}^n$).
I got the following questions:
- If I understand these definitions correctly then every ES is also an LPES but the other direction does not hold since an ES requires that $f$ is alwys the same parametrisation for every $x in S$. Is this rigth?
- Are there any intuitive examples of an LPES that is not an ES? I can hardly imagine something such as an LPES in terms of "real-world" geometry.
calculus differential-geometry manifolds surfaces
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1
down vote
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up vote
1
down vote
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I recently learned about the definitions of Embedded Surface (ES) and Locally Parametrised Embedded Surface (LEPS) in a lecture of mine. We defined them as follows:
ES: A regular parametrisation $f$ is called an Embedded Surface if for $f:D rightarrow f(D) = S subseteq mathbb{R}^n$ holds:
- For all $uin D$ and for all open $V subseteq D$ with $u in V$ there exists an open $U subseteq mathbb{R}^n$ with $f(u) in U$ such that $U cap S = f(V)$.
LPES: We say $S subseteq mathbb{R}^n$ is a Locally Parametrised Embedded (regular)($k$-dimensional) Surface if for all $x in S$ there exists an open neighbourhood $U subseteq mathbb{R}^n$ of $x$ in $mathbb{R}^n$ and a domain $D subseteq mathbb{R}^k$ as well as a regular parametrisation $f:Drightarrow mathbb{R}^n$ sucht that
$$U cap S = f(D)$$
Regular Parametrisation: Let $D subseteq mathbb{R}^k$ be a domain an $n,k in mathbb{N}$ such that $n ge k$. Now consider the injective function $f: D rightarrow mathbb{R}^n in C^1(D,mathbb{R}^n)$ and assume that it's Jacobian has rank $k$. We call $f$ a regular parametrisation (of a k-dimensional surface in $mathbb{R}^n$).
I got the following questions:
- If I understand these definitions correctly then every ES is also an LPES but the other direction does not hold since an ES requires that $f$ is alwys the same parametrisation for every $x in S$. Is this rigth?
- Are there any intuitive examples of an LPES that is not an ES? I can hardly imagine something such as an LPES in terms of "real-world" geometry.
calculus differential-geometry manifolds surfaces
I recently learned about the definitions of Embedded Surface (ES) and Locally Parametrised Embedded Surface (LEPS) in a lecture of mine. We defined them as follows:
ES: A regular parametrisation $f$ is called an Embedded Surface if for $f:D rightarrow f(D) = S subseteq mathbb{R}^n$ holds:
- For all $uin D$ and for all open $V subseteq D$ with $u in V$ there exists an open $U subseteq mathbb{R}^n$ with $f(u) in U$ such that $U cap S = f(V)$.
LPES: We say $S subseteq mathbb{R}^n$ is a Locally Parametrised Embedded (regular)($k$-dimensional) Surface if for all $x in S$ there exists an open neighbourhood $U subseteq mathbb{R}^n$ of $x$ in $mathbb{R}^n$ and a domain $D subseteq mathbb{R}^k$ as well as a regular parametrisation $f:Drightarrow mathbb{R}^n$ sucht that
$$U cap S = f(D)$$
Regular Parametrisation: Let $D subseteq mathbb{R}^k$ be a domain an $n,k in mathbb{N}$ such that $n ge k$. Now consider the injective function $f: D rightarrow mathbb{R}^n in C^1(D,mathbb{R}^n)$ and assume that it's Jacobian has rank $k$. We call $f$ a regular parametrisation (of a k-dimensional surface in $mathbb{R}^n$).
I got the following questions:
- If I understand these definitions correctly then every ES is also an LPES but the other direction does not hold since an ES requires that $f$ is alwys the same parametrisation for every $x in S$. Is this rigth?
- Are there any intuitive examples of an LPES that is not an ES? I can hardly imagine something such as an LPES in terms of "real-world" geometry.
calculus differential-geometry manifolds surfaces
calculus differential-geometry manifolds surfaces
edited Nov 13 at 22:23
asked Nov 13 at 21:50
3nondatur
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350111
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Before answering the question, I want to point out that these terms are not standard. The standard terms for "regular parametrization," "embedded surface," and "locally parametrized embedded surface" are, respectively: "injective immersion," "embedding," and "embedded submanifold."
As to your question: Technically speaking, according to the definitions you've given: An ES refers to a special kind of function. That is, an ES is a regular parametrization that satisfies a nice property. By contrast, an LPES is a special kind of subset of $mathbb{R}^n$.
An LPES is a very concrete, geometric object. Here's an example:
Example: The unit sphere $mathbb{S} = {(x,y,z) in mathbb{R}^3 colon x^2 + y^2 + z^2 = 1}$ is an LPES. Indeed, for any point $(x,y,z) in mathbb{S}$ on the sphere, you can find an open set $U subset mathbb{R}^3$ containing $(x,y,z)$ for which $U cap mathbb{S} = f(D)$ for some domain $D subset mathbb{R}^2$ and some regular parametrization $f colon D to mathbb{R}^3$.
So, let's say we take $(x,y,z) = (0,0,1)$. Then the upper half-space $U = {(x,y,z) colon z > 0}$ is an open subset in $mathbb{R}^3$ with $(x,y,z) in U$, and the intersection $U cap mathbb{S}$ is the upper hemisphere. You can then take $D = {(u,v) in mathbb{R}^2 colon u^2 + v^2 = 1}$ to be the unit disk in $mathbb{R}^2$ and take $f colon D to mathbb{R}^3$ to be $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$.
One of the things to take away from this example is that the regular parametrization $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$ only gives you points on the upper hemisphere. You will need a different regular parametrization to get points on the lower hemisphere. Even then you haven't covered the entire sphere: the points on the equator will require (at least) one additional regular parametrization.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Before answering the question, I want to point out that these terms are not standard. The standard terms for "regular parametrization," "embedded surface," and "locally parametrized embedded surface" are, respectively: "injective immersion," "embedding," and "embedded submanifold."
As to your question: Technically speaking, according to the definitions you've given: An ES refers to a special kind of function. That is, an ES is a regular parametrization that satisfies a nice property. By contrast, an LPES is a special kind of subset of $mathbb{R}^n$.
An LPES is a very concrete, geometric object. Here's an example:
Example: The unit sphere $mathbb{S} = {(x,y,z) in mathbb{R}^3 colon x^2 + y^2 + z^2 = 1}$ is an LPES. Indeed, for any point $(x,y,z) in mathbb{S}$ on the sphere, you can find an open set $U subset mathbb{R}^3$ containing $(x,y,z)$ for which $U cap mathbb{S} = f(D)$ for some domain $D subset mathbb{R}^2$ and some regular parametrization $f colon D to mathbb{R}^3$.
So, let's say we take $(x,y,z) = (0,0,1)$. Then the upper half-space $U = {(x,y,z) colon z > 0}$ is an open subset in $mathbb{R}^3$ with $(x,y,z) in U$, and the intersection $U cap mathbb{S}$ is the upper hemisphere. You can then take $D = {(u,v) in mathbb{R}^2 colon u^2 + v^2 = 1}$ to be the unit disk in $mathbb{R}^2$ and take $f colon D to mathbb{R}^3$ to be $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$.
One of the things to take away from this example is that the regular parametrization $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$ only gives you points on the upper hemisphere. You will need a different regular parametrization to get points on the lower hemisphere. Even then you haven't covered the entire sphere: the points on the equator will require (at least) one additional regular parametrization.
add a comment |
up vote
1
down vote
accepted
Before answering the question, I want to point out that these terms are not standard. The standard terms for "regular parametrization," "embedded surface," and "locally parametrized embedded surface" are, respectively: "injective immersion," "embedding," and "embedded submanifold."
As to your question: Technically speaking, according to the definitions you've given: An ES refers to a special kind of function. That is, an ES is a regular parametrization that satisfies a nice property. By contrast, an LPES is a special kind of subset of $mathbb{R}^n$.
An LPES is a very concrete, geometric object. Here's an example:
Example: The unit sphere $mathbb{S} = {(x,y,z) in mathbb{R}^3 colon x^2 + y^2 + z^2 = 1}$ is an LPES. Indeed, for any point $(x,y,z) in mathbb{S}$ on the sphere, you can find an open set $U subset mathbb{R}^3$ containing $(x,y,z)$ for which $U cap mathbb{S} = f(D)$ for some domain $D subset mathbb{R}^2$ and some regular parametrization $f colon D to mathbb{R}^3$.
So, let's say we take $(x,y,z) = (0,0,1)$. Then the upper half-space $U = {(x,y,z) colon z > 0}$ is an open subset in $mathbb{R}^3$ with $(x,y,z) in U$, and the intersection $U cap mathbb{S}$ is the upper hemisphere. You can then take $D = {(u,v) in mathbb{R}^2 colon u^2 + v^2 = 1}$ to be the unit disk in $mathbb{R}^2$ and take $f colon D to mathbb{R}^3$ to be $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$.
One of the things to take away from this example is that the regular parametrization $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$ only gives you points on the upper hemisphere. You will need a different regular parametrization to get points on the lower hemisphere. Even then you haven't covered the entire sphere: the points on the equator will require (at least) one additional regular parametrization.
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Before answering the question, I want to point out that these terms are not standard. The standard terms for "regular parametrization," "embedded surface," and "locally parametrized embedded surface" are, respectively: "injective immersion," "embedding," and "embedded submanifold."
As to your question: Technically speaking, according to the definitions you've given: An ES refers to a special kind of function. That is, an ES is a regular parametrization that satisfies a nice property. By contrast, an LPES is a special kind of subset of $mathbb{R}^n$.
An LPES is a very concrete, geometric object. Here's an example:
Example: The unit sphere $mathbb{S} = {(x,y,z) in mathbb{R}^3 colon x^2 + y^2 + z^2 = 1}$ is an LPES. Indeed, for any point $(x,y,z) in mathbb{S}$ on the sphere, you can find an open set $U subset mathbb{R}^3$ containing $(x,y,z)$ for which $U cap mathbb{S} = f(D)$ for some domain $D subset mathbb{R}^2$ and some regular parametrization $f colon D to mathbb{R}^3$.
So, let's say we take $(x,y,z) = (0,0,1)$. Then the upper half-space $U = {(x,y,z) colon z > 0}$ is an open subset in $mathbb{R}^3$ with $(x,y,z) in U$, and the intersection $U cap mathbb{S}$ is the upper hemisphere. You can then take $D = {(u,v) in mathbb{R}^2 colon u^2 + v^2 = 1}$ to be the unit disk in $mathbb{R}^2$ and take $f colon D to mathbb{R}^3$ to be $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$.
One of the things to take away from this example is that the regular parametrization $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$ only gives you points on the upper hemisphere. You will need a different regular parametrization to get points on the lower hemisphere. Even then you haven't covered the entire sphere: the points on the equator will require (at least) one additional regular parametrization.
Before answering the question, I want to point out that these terms are not standard. The standard terms for "regular parametrization," "embedded surface," and "locally parametrized embedded surface" are, respectively: "injective immersion," "embedding," and "embedded submanifold."
As to your question: Technically speaking, according to the definitions you've given: An ES refers to a special kind of function. That is, an ES is a regular parametrization that satisfies a nice property. By contrast, an LPES is a special kind of subset of $mathbb{R}^n$.
An LPES is a very concrete, geometric object. Here's an example:
Example: The unit sphere $mathbb{S} = {(x,y,z) in mathbb{R}^3 colon x^2 + y^2 + z^2 = 1}$ is an LPES. Indeed, for any point $(x,y,z) in mathbb{S}$ on the sphere, you can find an open set $U subset mathbb{R}^3$ containing $(x,y,z)$ for which $U cap mathbb{S} = f(D)$ for some domain $D subset mathbb{R}^2$ and some regular parametrization $f colon D to mathbb{R}^3$.
So, let's say we take $(x,y,z) = (0,0,1)$. Then the upper half-space $U = {(x,y,z) colon z > 0}$ is an open subset in $mathbb{R}^3$ with $(x,y,z) in U$, and the intersection $U cap mathbb{S}$ is the upper hemisphere. You can then take $D = {(u,v) in mathbb{R}^2 colon u^2 + v^2 = 1}$ to be the unit disk in $mathbb{R}^2$ and take $f colon D to mathbb{R}^3$ to be $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$.
One of the things to take away from this example is that the regular parametrization $f(u,v) = (u,v, sqrt{1 - u^2 - v^2})$ only gives you points on the upper hemisphere. You will need a different regular parametrization to get points on the lower hemisphere. Even then you haven't covered the entire sphere: the points on the equator will require (at least) one additional regular parametrization.
answered Nov 14 at 0:30
Jesse Madnick
19.4k562122
19.4k562122
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