Using the Gauss-Bonnet theorem to determine a surface
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I'm using the Gauss-Bonnet theorem on the following exercise and I would like to see if what I've done is correct.
Given a compact, connected surface $M$ with area $A(M)=1984707$ and Gauss curvature $K=frac{-31658} {10^6}$, determine the surface.
So, using Gauss-Bonnet to determine the Euler characteristic $χ(M)$ of $M$, I get:
$K*A(M)=2π*χ(M)$ which of course will gives a non integer characteristic.
I'm assuming it's just the numbers given but I thought to ask.
So, did I use Gauss-Bonnet correctly or this is not how it's done?
Also, if I did everything right, is there a way to determine if this surface is orientable or not with the information that the exercise gives?
Again, I'm sorry if this is trivial
differential-geometry geometric-topology
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add a comment |
$begingroup$
I'm using the Gauss-Bonnet theorem on the following exercise and I would like to see if what I've done is correct.
Given a compact, connected surface $M$ with area $A(M)=1984707$ and Gauss curvature $K=frac{-31658} {10^6}$, determine the surface.
So, using Gauss-Bonnet to determine the Euler characteristic $χ(M)$ of $M$, I get:
$K*A(M)=2π*χ(M)$ which of course will gives a non integer characteristic.
I'm assuming it's just the numbers given but I thought to ask.
So, did I use Gauss-Bonnet correctly or this is not how it's done?
Also, if I did everything right, is there a way to determine if this surface is orientable or not with the information that the exercise gives?
Again, I'm sorry if this is trivial
differential-geometry geometric-topology
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1
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You're doing it right. I think the spirit of the problem is that this arithmetic is going to give a (very good) approximation to an integer.
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– Ted Shifrin
Dec 21 '18 at 17:08
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It does indeed. Thank you!
$endgroup$
– Amontillado
Dec 21 '18 at 19:03
add a comment |
$begingroup$
I'm using the Gauss-Bonnet theorem on the following exercise and I would like to see if what I've done is correct.
Given a compact, connected surface $M$ with area $A(M)=1984707$ and Gauss curvature $K=frac{-31658} {10^6}$, determine the surface.
So, using Gauss-Bonnet to determine the Euler characteristic $χ(M)$ of $M$, I get:
$K*A(M)=2π*χ(M)$ which of course will gives a non integer characteristic.
I'm assuming it's just the numbers given but I thought to ask.
So, did I use Gauss-Bonnet correctly or this is not how it's done?
Also, if I did everything right, is there a way to determine if this surface is orientable or not with the information that the exercise gives?
Again, I'm sorry if this is trivial
differential-geometry geometric-topology
$endgroup$
I'm using the Gauss-Bonnet theorem on the following exercise and I would like to see if what I've done is correct.
Given a compact, connected surface $M$ with area $A(M)=1984707$ and Gauss curvature $K=frac{-31658} {10^6}$, determine the surface.
So, using Gauss-Bonnet to determine the Euler characteristic $χ(M)$ of $M$, I get:
$K*A(M)=2π*χ(M)$ which of course will gives a non integer characteristic.
I'm assuming it's just the numbers given but I thought to ask.
So, did I use Gauss-Bonnet correctly or this is not how it's done?
Also, if I did everything right, is there a way to determine if this surface is orientable or not with the information that the exercise gives?
Again, I'm sorry if this is trivial
differential-geometry geometric-topology
differential-geometry geometric-topology
asked Dec 21 '18 at 15:40
AmontilladoAmontillado
449313
449313
1
$begingroup$
You're doing it right. I think the spirit of the problem is that this arithmetic is going to give a (very good) approximation to an integer.
$endgroup$
– Ted Shifrin
Dec 21 '18 at 17:08
$begingroup$
It does indeed. Thank you!
$endgroup$
– Amontillado
Dec 21 '18 at 19:03
add a comment |
1
$begingroup$
You're doing it right. I think the spirit of the problem is that this arithmetic is going to give a (very good) approximation to an integer.
$endgroup$
– Ted Shifrin
Dec 21 '18 at 17:08
$begingroup$
It does indeed. Thank you!
$endgroup$
– Amontillado
Dec 21 '18 at 19:03
1
1
$begingroup$
You're doing it right. I think the spirit of the problem is that this arithmetic is going to give a (very good) approximation to an integer.
$endgroup$
– Ted Shifrin
Dec 21 '18 at 17:08
$begingroup$
You're doing it right. I think the spirit of the problem is that this arithmetic is going to give a (very good) approximation to an integer.
$endgroup$
– Ted Shifrin
Dec 21 '18 at 17:08
$begingroup$
It does indeed. Thank you!
$endgroup$
– Amontillado
Dec 21 '18 at 19:03
$begingroup$
It does indeed. Thank you!
$endgroup$
– Amontillado
Dec 21 '18 at 19:03
add a comment |
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1
$begingroup$
You're doing it right. I think the spirit of the problem is that this arithmetic is going to give a (very good) approximation to an integer.
$endgroup$
– Ted Shifrin
Dec 21 '18 at 17:08
$begingroup$
It does indeed. Thank you!
$endgroup$
– Amontillado
Dec 21 '18 at 19:03