Add variable space at the end of line in file
I want to add white space at the end of each line. Number of white space is in variable. If number of white space is fixed then I can use this command
sed 's/$/ /g'
for two spaces.
space_variable=4;
But if number of white space is variable (space_variable=4) then how can I use it?
sed awk echo
add a comment |
I want to add white space at the end of each line. Number of white space is in variable. If number of white space is fixed then I can use this command
sed 's/$/ /g'
for two spaces.
space_variable=4;
But if number of white space is variable (space_variable=4) then how can I use it?
sed awk echo
Where is the variable defined? Script?
– harrymc
Feb 7 at 12:44
add a comment |
I want to add white space at the end of each line. Number of white space is in variable. If number of white space is fixed then I can use this command
sed 's/$/ /g'
for two spaces.
space_variable=4;
But if number of white space is variable (space_variable=4) then how can I use it?
sed awk echo
I want to add white space at the end of each line. Number of white space is in variable. If number of white space is fixed then I can use this command
sed 's/$/ /g'
for two spaces.
space_variable=4;
But if number of white space is variable (space_variable=4) then how can I use it?
sed awk echo
sed awk echo
edited Feb 7 at 13:39
Ahmed Ashour
1,3271716
1,3271716
asked Feb 7 at 12:42
Vishal PatelVishal Patel
111
111
Where is the variable defined? Script?
– harrymc
Feb 7 at 12:44
add a comment |
Where is the variable defined? Script?
– harrymc
Feb 7 at 12:44
Where is the variable defined? Script?
– harrymc
Feb 7 at 12:44
Where is the variable defined? Script?
– harrymc
Feb 7 at 12:44
add a comment |
1 Answer
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spaces=$(printf "%*s" "$space_variable" "")
That will return the empty string padded with spaces to a field N characters wide.
Then: sed "s/$/$spaces/"
In bash, you can use the builtin
printf -v spaces "%*s" "$space_variable" ""
but I find this less readable as it hides the variable name somewhat.
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1 Answer
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1 Answer
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active
oldest
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votes
spaces=$(printf "%*s" "$space_variable" "")
That will return the empty string padded with spaces to a field N characters wide.
Then: sed "s/$/$spaces/"
In bash, you can use the builtin
printf -v spaces "%*s" "$space_variable" ""
but I find this less readable as it hides the variable name somewhat.
add a comment |
spaces=$(printf "%*s" "$space_variable" "")
That will return the empty string padded with spaces to a field N characters wide.
Then: sed "s/$/$spaces/"
In bash, you can use the builtin
printf -v spaces "%*s" "$space_variable" ""
but I find this less readable as it hides the variable name somewhat.
add a comment |
spaces=$(printf "%*s" "$space_variable" "")
That will return the empty string padded with spaces to a field N characters wide.
Then: sed "s/$/$spaces/"
In bash, you can use the builtin
printf -v spaces "%*s" "$space_variable" ""
but I find this less readable as it hides the variable name somewhat.
spaces=$(printf "%*s" "$space_variable" "")
That will return the empty string padded with spaces to a field N characters wide.
Then: sed "s/$/$spaces/"
In bash, you can use the builtin
printf -v spaces "%*s" "$space_variable" ""
but I find this less readable as it hides the variable name somewhat.
answered Feb 7 at 16:10
glenn jackmanglenn jackman
16.1k22645
16.1k22645
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Where is the variable defined? Script?
– harrymc
Feb 7 at 12:44