How to use Exclusions in ContourPlot?












3












$begingroup$


I want to achieve this effect:
enter image description here



then, I try the following code:



p = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, 

Axes -> True, Frame -> False, AxesOrigin -> {0, 0}, 

PlotRange -> All, AspectRatio -> Automatic, 

Exclusions -> {x <= 2 || y <= 0}, ExclusionsStyle -> Dashed]


however, it didn't work. How to do?






plotting







share|improve this question











$endgroup$








  • 1




    $begingroup$
    That means you don't want to exclude the dashed line? Try RegionFunctioninstead of Exclusions!
    $endgroup$
    – Ulrich Neumann
    Feb 7 at 10:15
















3












$begingroup$


I want to achieve this effect:
enter image description here



then, I try the following code:



p = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, 

Axes -> True, Frame -> False, AxesOrigin -> {0, 0}, 

PlotRange -> All, AspectRatio -> Automatic, 

Exclusions -> {x <= 2 || y <= 0}, ExclusionsStyle -> Dashed]


however, it didn't work. How to do?






plotting







share|improve this question











$endgroup$








  • 1




    $begingroup$
    That means you don't want to exclude the dashed line? Try RegionFunctioninstead of Exclusions!
    $endgroup$
    – Ulrich Neumann
    Feb 7 at 10:15














3












3








3





$begingroup$


I want to achieve this effect:
enter image description here



then, I try the following code:



p = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, 

Axes -> True, Frame -> False, AxesOrigin -> {0, 0}, 

PlotRange -> All, AspectRatio -> Automatic, 

Exclusions -> {x <= 2 || y <= 0}, ExclusionsStyle -> Dashed]


however, it didn't work. How to do?






plotting







share|improve this question











$endgroup$




I want to achieve this effect:
enter image description here



then, I try the following code:



p = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, 

Axes -> True, Frame -> False, AxesOrigin -> {0, 0}, 

PlotRange -> All, AspectRatio -> Automatic, 

Exclusions -> {x <= 2 || y <= 0}, ExclusionsStyle -> Dashed]


however, it didn't work. How to do?






plotting




plotting






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Feb 7 at 9:57









Carl Lange

4,1431735




4,1431735










asked Feb 7 at 9:37









FacetFacet

424




424








  • 1




    $begingroup$
    That means you don't want to exclude the dashed line? Try RegionFunctioninstead of Exclusions!
    $endgroup$
    – Ulrich Neumann
    Feb 7 at 10:15














  • 1




    $begingroup$
    That means you don't want to exclude the dashed line? Try RegionFunctioninstead of Exclusions!
    $endgroup$
    – Ulrich Neumann
    Feb 7 at 10:15








1




1




$begingroup$
That means you don't want to exclude the dashed line? Try RegionFunctioninstead of Exclusions!
$endgroup$
– Ulrich Neumann
Feb 7 at 10:15




$begingroup$
That means you don't want to exclude the dashed line? Try RegionFunctioninstead of Exclusions!
$endgroup$
– Ulrich Neumann
Feb 7 at 10:15










1 Answer
1






active

oldest

votes


















5












$begingroup$

Try RegionFunction instead of Exclusions:



p1 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, RegionFunction ->  (#2 <= 0 || #1 <= 2 &) , ContourStyle -> Dashed];

p2 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1},RegionFunction ->   (#2 > 0 && 2 <= #1 <= 3 &) ,ContourStyle -> Blue];

Show[{p1, p2}, Axes -> True, Frame -> False, AxesOrigin -> {0, 0},PlotRange -> All, AspectRatio -> Automatic]


enter image description here






share|improve this answer









$endgroup$













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    5












    $begingroup$

    Try RegionFunction instead of Exclusions:



    p1 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, RegionFunction ->  (#2 <= 0 || #1 <= 2 &) , ContourStyle -> Dashed];
    
p2 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1},RegionFunction ->   (#2 > 0 && 2 <= #1 <= 3 &) ,ContourStyle -> Blue];
    
Show[{p1, p2}, Axes -> True, Frame -> False, AxesOrigin -> {0, 0},PlotRange -> All, AspectRatio -> Automatic]


    enter image description here






    share|improve this answer









    $endgroup$


















      5












      $begingroup$

      Try RegionFunction instead of Exclusions:



      p1 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, RegionFunction ->  (#2 <= 0 || #1 <= 2 &) , ContourStyle -> Dashed];
      
p2 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1},RegionFunction ->   (#2 > 0 && 2 <= #1 <= 3 &) ,ContourStyle -> Blue];
      
Show[{p1, p2}, Axes -> True, Frame -> False, AxesOrigin -> {0, 0},PlotRange -> All, AspectRatio -> Automatic]


      enter image description here






      share|improve this answer









      $endgroup$
















        5












        5








        5





        $begingroup$

        Try RegionFunction instead of Exclusions:



        p1 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, RegionFunction ->  (#2 <= 0 || #1 <= 2 &) , ContourStyle -> Dashed];
        
p2 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1},RegionFunction ->   (#2 > 0 && 2 <= #1 <= 3 &) ,ContourStyle -> Blue];
        
Show[{p1, p2}, Axes -> True, Frame -> False, AxesOrigin -> {0, 0},PlotRange -> All, AspectRatio -> Automatic]


        enter image description here






        share|improve this answer









        $endgroup$



        Try RegionFunction instead of Exclusions:



        p1 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1}, RegionFunction ->  (#2 <= 0 || #1 <= 2 &) , ContourStyle -> Dashed];
        
p2 = ContourPlot[(x - 2)^2 + y^2 == 1, {x, 1, 3}, {y, -1, 1},RegionFunction ->   (#2 > 0 && 2 <= #1 <= 3 &) ,ContourStyle -> Blue];
        
Show[{p1, p2}, Axes -> True, Frame -> False, AxesOrigin -> {0, 0},PlotRange -> All, AspectRatio -> Automatic]


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Feb 7 at 10:20









        Ulrich NeumannUlrich Neumann

        9,446516




        9,446516






























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