Exporting an variable
up vote
1
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I have one script that exports an variable and second which reads it:
script1:
var1=abc
export var1
./script2
script2:
echo $var1
Of course the variable var1 is accessible from script2 (returns "abc")
Now when i remove the script2 call in script1 (the "export var1" line is the last one in the script1) and move the scripts calls to another script like so:
script3:
./script1
./script2
the var1 variable isn't available in script2 anymore. Why is it like that?
linux bash
asked Nov 28 at 11:08
Mulligun007
72
add a comment |
up vote
1
down vote
favorite
I have one script that exports an variable and second which reads it:
script1:
var1=abc
export var1
./script2
script2:
echo $var1
Of course the variable var1 is accessible from script2 (returns "abc")
Now when i remove the script2 call in script1 (the "export var1" line is the last one in the script1) and move the scripts calls to another script like so:
script3:
./script1
./script2
the var1 variable isn't available in script2 anymore. Why is it like that?
linux bash
asked Nov 28 at 11:08
Mulligun007
72
2
See stackoverflow.com/questions/496702/… and in particular this answer
– xenoid
Nov 28 at 13:01
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have one script that exports an variable and second which reads it:
script1:
var1=abc
export var1
./script2
script2:
echo $var1
Of course the variable var1 is accessible from script2 (returns "abc")
Now when i remove the script2 call in script1 (the "export var1" line is the last one in the script1) and move the scripts calls to another script like so:
script3:
./script1
./script2
the var1 variable isn't available in script2 anymore. Why is it like that?
linux bash
asked Nov 28 at 11:08
Mulligun007
72
I have one script that exports an variable and second which reads it:
script1:
var1=abc
export var1
./script2
script2:
echo $var1
Of course the variable var1 is accessible from script2 (returns "abc")
Now when i remove the script2 call in script1 (the "export var1" line is the last one in the script1) and move the scripts calls to another script like so:
script3:
./script1
./script2
the var1 variable isn't available in script2 anymore. Why is it like that?
linux bash
linux bash
asked Nov 28 at 11:08
Mulligun007
72
asked Nov 28 at 11:08
Mulligun007
72
asked Nov 28 at 11:08
Mulligun007
72
asked Nov 28 at 11:08
Mulligun007
72
asked Nov 28 at 11:08
Mulligun007
72
72
2
See stackoverflow.com/questions/496702/… and in particular this answer
– xenoid
Nov 28 at 13:01
add a comment |
2
See stackoverflow.com/questions/496702/… and in particular this answer
– xenoid
Nov 28 at 13:01
2
2
See stackoverflow.com/questions/496702/… and in particular this answer
– xenoid
Nov 28 at 13:01
See stackoverflow.com/questions/496702/… and in particular this answer
– xenoid
Nov 28 at 13:01
add a comment |
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See stackoverflow.com/questions/496702/… and in particular this answer
– xenoid
Nov 28 at 13:01