Prove this A∆B=C B∆C=A [duplicate]
0
$begingroup$
This question already has an answer here:
Show that $ADelta B = C$ if and only if $A = BDelta C$
5 answers
$A∆B=C <=> B∆A=C$
I don't idea. Is this correct task? Maybe the <=> means something else i don't know?
elementary-set-theory predicate-logic boolean-algebra
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
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marked as duplicate by Martin Sleziak, Xander Henderson, Alexander Gruber♦ Dec 12 '18 at 5:02
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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show 1 more comment
0
$begingroup$
This question already has an answer here:
Show that $ADelta B = C$ if and only if $A = BDelta C$
5 answers
$A∆B=C <=> B∆A=C$
I don't idea. Is this correct task? Maybe the <=> means something else i don't know?
elementary-set-theory predicate-logic boolean-algebra
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
$endgroup$
marked as duplicate by Martin Sleziak, Xander Henderson, Alexander Gruber♦ Dec 12 '18 at 5:02
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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You say you "don't idea", and I don't believe you. Begin with what you think $iff$ means, and what $Delta$ means.
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– Arthur
Dec 6 '18 at 5:40
1
$begingroup$
If my logic is correct, would this statement be equivalent to showing that the $∆$ operator is symmetric? Assuming that the double arrow is If and only If (sometimes written as iff, also known as a biconditional I believe?)... I think the $∆$ operator is known as the Symmetric Set difference.. So if this statement is true maybe that's why it is called Symmetric! But ye you need to define your symbols please :)
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– DanielOnMSE
Dec 6 '18 at 6:06
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"I don't idea." is an incomplete sentence, thus doesn't signify anything.
$endgroup$
– William Elliot
Dec 6 '18 at 6:37
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@DanielOnMSE , you are right about ∆, this is symmetric difference. Also my teacher use plus '+' instead of ∆. <=> is probably what you meant. I know it's totally not a =.
$endgroup$
– Kirill Andreev
Dec 6 '18 at 7:04
$begingroup$
Ye so chances are the double sided arrow is an implication that works both ways. A logical implication is this: "If x Then y" is written as x => y (read as x implies y). If both x => y AND y => x are True statements then we write x <=> y (or y <=> x). This can be read as x implies y and y implies x. Or I believe this is generally read as x if and only if y (or y if and only if x). Because if x is true then y must be and vice versa.
$endgroup$
– DanielOnMSE
Dec 6 '18 at 7:13
|
show 1 more comment
0
0
0
$begingroup$
This question already has an answer here:
Show that $ADelta B = C$ if and only if $A = BDelta C$
5 answers
$A∆B=C <=> B∆A=C$
I don't idea. Is this correct task? Maybe the <=> means something else i don't know?
elementary-set-theory predicate-logic boolean-algebra
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
$endgroup$
This question already has an answer here:
Show that $ADelta B = C$ if and only if $A = BDelta C$
5 answers
$A∆B=C <=> B∆A=C$
I don't idea. Is this correct task? Maybe the <=> means something else i don't know?
This question already has an answer here:
Show that $ADelta B = C$ if and only if $A = BDelta C$
5 answers
elementary-set-theory predicate-logic boolean-algebra
elementary-set-theory predicate-logic boolean-algebra
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
asked Dec 6 '18 at 5:33
Kirill AndreevKirill Andreev
1
1
marked as duplicate by Martin Sleziak, Xander Henderson, Alexander Gruber♦ Dec 12 '18 at 5:02
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Martin Sleziak, Xander Henderson, Alexander Gruber♦ Dec 12 '18 at 5:02
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
$begingroup$
You say you "don't idea", and I don't believe you. Begin with what you think $iff$ means, and what $Delta$ means.
$endgroup$
– Arthur
Dec 6 '18 at 5:40
1
$begingroup$
If my logic is correct, would this statement be equivalent to showing that the $∆$ operator is symmetric? Assuming that the double arrow is If and only If (sometimes written as iff, also known as a biconditional I believe?)... I think the $∆$ operator is known as the Symmetric Set difference.. So if this statement is true maybe that's why it is called Symmetric! But ye you need to define your symbols please :)
$endgroup$
– DanielOnMSE
Dec 6 '18 at 6:06
$begingroup$
"I don't idea." is an incomplete sentence, thus doesn't signify anything.
$endgroup$
– William Elliot
Dec 6 '18 at 6:37
$begingroup$
@DanielOnMSE , you are right about ∆, this is symmetric difference. Also my teacher use plus '+' instead of ∆. <=> is probably what you meant. I know it's totally not a =.
$endgroup$
– Kirill Andreev
Dec 6 '18 at 7:04
$begingroup$
Ye so chances are the double sided arrow is an implication that works both ways. A logical implication is this: "If x Then y" is written as x => y (read as x implies y). If both x => y AND y => x are True statements then we write x <=> y (or y <=> x). This can be read as x implies y and y implies x. Or I believe this is generally read as x if and only if y (or y if and only if x). Because if x is true then y must be and vice versa.
$endgroup$
– DanielOnMSE
Dec 6 '18 at 7:13
|
show 1 more comment
$begingroup$
You say you "don't idea", and I don't believe you. Begin with what you think $iff$ means, and what $Delta$ means.
$endgroup$
– Arthur
Dec 6 '18 at 5:40
1
$begingroup$
If my logic is correct, would this statement be equivalent to showing that the $∆$ operator is symmetric? Assuming that the double arrow is If and only If (sometimes written as iff, also known as a biconditional I believe?)... I think the $∆$ operator is known as the Symmetric Set difference.. So if this statement is true maybe that's why it is called Symmetric! But ye you need to define your symbols please :)
$endgroup$
– DanielOnMSE
Dec 6 '18 at 6:06
$begingroup$
"I don't idea." is an incomplete sentence, thus doesn't signify anything.
$endgroup$
– William Elliot
Dec 6 '18 at 6:37
$begingroup$
@DanielOnMSE , you are right about ∆, this is symmetric difference. Also my teacher use plus '+' instead of ∆. <=> is probably what you meant. I know it's totally not a =.
$endgroup$
– Kirill Andreev
Dec 6 '18 at 7:04
$begingroup$
Ye so chances are the double sided arrow is an implication that works both ways. A logical implication is this: "If x Then y" is written as x => y (read as x implies y). If both x => y AND y => x are True statements then we write x <=> y (or y <=> x). This can be read as x implies y and y implies x. Or I believe this is generally read as x if and only if y (or y if and only if x). Because if x is true then y must be and vice versa.
$endgroup$
– DanielOnMSE
Dec 6 '18 at 7:13
$begingroup$
You say you "don't idea", and I don't believe you. Begin with what you think $iff$ means, and what $Delta$ means.
$endgroup$
– Arthur
Dec 6 '18 at 5:40
$begingroup$
You say you "don't idea", and I don't believe you. Begin with what you think $iff$ means, and what $Delta$ means.
$endgroup$
– Arthur
Dec 6 '18 at 5:40
1
1
$begingroup$
If my logic is correct, would this statement be equivalent to showing that the $∆$ operator is symmetric? Assuming that the double arrow is If and only If (sometimes written as iff, also known as a biconditional I believe?)... I think the $∆$ operator is known as the Symmetric Set difference.. So if this statement is true maybe that's why it is called Symmetric! But ye you need to define your symbols please :)
$endgroup$
– DanielOnMSE
Dec 6 '18 at 6:06
$begingroup$
If my logic is correct, would this statement be equivalent to showing that the $∆$ operator is symmetric? Assuming that the double arrow is If and only If (sometimes written as iff, also known as a biconditional I believe?)... I think the $∆$ operator is known as the Symmetric Set difference.. So if this statement is true maybe that's why it is called Symmetric! But ye you need to define your symbols please :)
$endgroup$
– DanielOnMSE
Dec 6 '18 at 6:06
$begingroup$
"I don't idea." is an incomplete sentence, thus doesn't signify anything.
$endgroup$
– William Elliot
Dec 6 '18 at 6:37
$begingroup$
"I don't idea." is an incomplete sentence, thus doesn't signify anything.
$endgroup$
– William Elliot
Dec 6 '18 at 6:37
$begingroup$
@DanielOnMSE , you are right about ∆, this is symmetric difference. Also my teacher use plus '+' instead of ∆. <=> is probably what you meant. I know it's totally not a =.
$endgroup$
– Kirill Andreev
Dec 6 '18 at 7:04
$begingroup$
@DanielOnMSE , you are right about ∆, this is symmetric difference. Also my teacher use plus '+' instead of ∆. <=> is probably what you meant. I know it's totally not a =.
$endgroup$
– Kirill Andreev
Dec 6 '18 at 7:04
$begingroup$
Ye so chances are the double sided arrow is an implication that works both ways. A logical implication is this: "If x Then y" is written as x => y (read as x implies y). If both x => y AND y => x are True statements then we write x <=> y (or y <=> x). This can be read as x implies y and y implies x. Or I believe this is generally read as x if and only if y (or y if and only if x). Because if x is true then y must be and vice versa.
$endgroup$
– DanielOnMSE
Dec 6 '18 at 7:13
$begingroup$
Ye so chances are the double sided arrow is an implication that works both ways. A logical implication is this: "If x Then y" is written as x => y (read as x implies y). If both x => y AND y => x are True statements then we write x <=> y (or y <=> x). This can be read as x implies y and y implies x. Or I believe this is generally read as x if and only if y (or y if and only if x). Because if x is true then y must be and vice versa.
$endgroup$
– DanielOnMSE
Dec 6 '18 at 7:13
|
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1 Answer
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Hint.
Prove A $Delta$B = (A $cup$ B) - (A $cap$ B).
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
$begingroup$
Hint.
Prove A $Delta$B = (A $cup$ B) - (A $cap$ B).
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
$endgroup$
add a comment |
0
$begingroup$
Hint.
Prove A $Delta$B = (A $cup$ B) - (A $cap$ B).
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
$endgroup$
add a comment |
0
0
0
$begingroup$
Hint.
Prove A $Delta$B = (A $cup$ B) - (A $cap$ B).
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
$endgroup$
Hint.
Prove A $Delta$B = (A $cup$ B) - (A $cap$ B).
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
answered Dec 6 '18 at 6:44
William ElliotWilliam Elliot
7,7672720
7,7672720
add a comment |
add a comment |
$begingroup$
You say you "don't idea", and I don't believe you. Begin with what you think $iff$ means, and what $Delta$ means.
$endgroup$
– Arthur
Dec 6 '18 at 5:40
1
$begingroup$
If my logic is correct, would this statement be equivalent to showing that the $∆$ operator is symmetric? Assuming that the double arrow is If and only If (sometimes written as iff, also known as a biconditional I believe?)... I think the $∆$ operator is known as the Symmetric Set difference.. So if this statement is true maybe that's why it is called Symmetric! But ye you need to define your symbols please :)
$endgroup$
– DanielOnMSE
Dec 6 '18 at 6:06
$begingroup$
"I don't idea." is an incomplete sentence, thus doesn't signify anything.
$endgroup$
– William Elliot
Dec 6 '18 at 6:37
$begingroup$
@DanielOnMSE , you are right about ∆, this is symmetric difference. Also my teacher use plus '+' instead of ∆. <=> is probably what you meant. I know it's totally not a =.
$endgroup$
– Kirill Andreev
Dec 6 '18 at 7:04
$begingroup$
Ye so chances are the double sided arrow is an implication that works both ways. A logical implication is this: "If x Then y" is written as x => y (read as x implies y). If both x => y AND y => x are True statements then we write x <=> y (or y <=> x). This can be read as x implies y and y implies x. Or I believe this is generally read as x if and only if y (or y if and only if x). Because if x is true then y must be and vice versa.
$endgroup$
– DanielOnMSE
Dec 6 '18 at 7:13