Find a linear transformation defined by $T(0,1,2) = (3,1,2)$ and $T(1,1,1) = (2,2,2)$. [closed]












-1












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The transformation here (as per my calculations) will be $Tcolon U rightarrow V$ such that $T(x,y,z) = (y+z, 3y-z, 2y)$ where $z=-x+2y$.



Now what should $U$ be $Bbb R^3$ or a subset of $Bbb R^3$?










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closed as off-topic by Saad, John B, Brahadeesh, ncmathsadist, GNUSupporter 8964民主女神 地下教會 Dec 10 '18 at 14:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, John B, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    There will be many linear maps that do this, since you have only specified where a 2 dimensional subspace goes
    $endgroup$
    – qbert
    Dec 6 '18 at 4:57










  • $begingroup$
    @qbert I could only find a single transformation. Can you hint how to find others?
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:02










  • $begingroup$
    To find others just extend ${(0,1,2),(1,1,1)}$ to a basis for $mathbb R^3$. For instance, you could use $(1,0,0)$. Then just map it to different vectors to get other examples.
    $endgroup$
    – Chris Custer
    Dec 6 '18 at 5:58










  • $begingroup$
    If this is exactly the problem as it was presented to you (where did it come from, by the way?), then it’s common to assume that $T:mathbb R^3tomathbb R^3$ was intended. If this is from some textbook, compare this exercise to other examples and exercises in the book to be sure.
    $endgroup$
    – amd
    Dec 6 '18 at 6:36






  • 1




    $begingroup$
    There’s no way for anyone else to know for sure unless you provide a source or some other context for comparison. At any rate, the right person to ask is whomever is going to be grading your work.
    $endgroup$
    – amd
    Dec 6 '18 at 19:15


















-1












$begingroup$


The transformation here (as per my calculations) will be $Tcolon U rightarrow V$ such that $T(x,y,z) = (y+z, 3y-z, 2y)$ where $z=-x+2y$.



Now what should $U$ be $Bbb R^3$ or a subset of $Bbb R^3$?










share|cite|improve this question











$endgroup$



closed as off-topic by Saad, John B, Brahadeesh, ncmathsadist, GNUSupporter 8964民主女神 地下教會 Dec 10 '18 at 14:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, John B, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    There will be many linear maps that do this, since you have only specified where a 2 dimensional subspace goes
    $endgroup$
    – qbert
    Dec 6 '18 at 4:57










  • $begingroup$
    @qbert I could only find a single transformation. Can you hint how to find others?
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:02










  • $begingroup$
    To find others just extend ${(0,1,2),(1,1,1)}$ to a basis for $mathbb R^3$. For instance, you could use $(1,0,0)$. Then just map it to different vectors to get other examples.
    $endgroup$
    – Chris Custer
    Dec 6 '18 at 5:58










  • $begingroup$
    If this is exactly the problem as it was presented to you (where did it come from, by the way?), then it’s common to assume that $T:mathbb R^3tomathbb R^3$ was intended. If this is from some textbook, compare this exercise to other examples and exercises in the book to be sure.
    $endgroup$
    – amd
    Dec 6 '18 at 6:36






  • 1




    $begingroup$
    There’s no way for anyone else to know for sure unless you provide a source or some other context for comparison. At any rate, the right person to ask is whomever is going to be grading your work.
    $endgroup$
    – amd
    Dec 6 '18 at 19:15
















-1












-1








-1





$begingroup$


The transformation here (as per my calculations) will be $Tcolon U rightarrow V$ such that $T(x,y,z) = (y+z, 3y-z, 2y)$ where $z=-x+2y$.



Now what should $U$ be $Bbb R^3$ or a subset of $Bbb R^3$?










share|cite|improve this question











$endgroup$




The transformation here (as per my calculations) will be $Tcolon U rightarrow V$ such that $T(x,y,z) = (y+z, 3y-z, 2y)$ where $z=-x+2y$.



Now what should $U$ be $Bbb R^3$ or a subset of $Bbb R^3$?







linear-algebra linear-transformations






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 6 '18 at 5:14









Tianlalu

3,08621038




3,08621038










asked Dec 6 '18 at 4:45









Ajay ChoudharyAjay Choudhary

788




788




closed as off-topic by Saad, John B, Brahadeesh, ncmathsadist, GNUSupporter 8964民主女神 地下教會 Dec 10 '18 at 14:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, John B, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Saad, John B, Brahadeesh, ncmathsadist, GNUSupporter 8964民主女神 地下教會 Dec 10 '18 at 14:07


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, John B, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    There will be many linear maps that do this, since you have only specified where a 2 dimensional subspace goes
    $endgroup$
    – qbert
    Dec 6 '18 at 4:57










  • $begingroup$
    @qbert I could only find a single transformation. Can you hint how to find others?
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:02










  • $begingroup$
    To find others just extend ${(0,1,2),(1,1,1)}$ to a basis for $mathbb R^3$. For instance, you could use $(1,0,0)$. Then just map it to different vectors to get other examples.
    $endgroup$
    – Chris Custer
    Dec 6 '18 at 5:58










  • $begingroup$
    If this is exactly the problem as it was presented to you (where did it come from, by the way?), then it’s common to assume that $T:mathbb R^3tomathbb R^3$ was intended. If this is from some textbook, compare this exercise to other examples and exercises in the book to be sure.
    $endgroup$
    – amd
    Dec 6 '18 at 6:36






  • 1




    $begingroup$
    There’s no way for anyone else to know for sure unless you provide a source or some other context for comparison. At any rate, the right person to ask is whomever is going to be grading your work.
    $endgroup$
    – amd
    Dec 6 '18 at 19:15




















  • $begingroup$
    There will be many linear maps that do this, since you have only specified where a 2 dimensional subspace goes
    $endgroup$
    – qbert
    Dec 6 '18 at 4:57










  • $begingroup$
    @qbert I could only find a single transformation. Can you hint how to find others?
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:02










  • $begingroup$
    To find others just extend ${(0,1,2),(1,1,1)}$ to a basis for $mathbb R^3$. For instance, you could use $(1,0,0)$. Then just map it to different vectors to get other examples.
    $endgroup$
    – Chris Custer
    Dec 6 '18 at 5:58










  • $begingroup$
    If this is exactly the problem as it was presented to you (where did it come from, by the way?), then it’s common to assume that $T:mathbb R^3tomathbb R^3$ was intended. If this is from some textbook, compare this exercise to other examples and exercises in the book to be sure.
    $endgroup$
    – amd
    Dec 6 '18 at 6:36






  • 1




    $begingroup$
    There’s no way for anyone else to know for sure unless you provide a source or some other context for comparison. At any rate, the right person to ask is whomever is going to be grading your work.
    $endgroup$
    – amd
    Dec 6 '18 at 19:15


















$begingroup$
There will be many linear maps that do this, since you have only specified where a 2 dimensional subspace goes
$endgroup$
– qbert
Dec 6 '18 at 4:57




$begingroup$
There will be many linear maps that do this, since you have only specified where a 2 dimensional subspace goes
$endgroup$
– qbert
Dec 6 '18 at 4:57












$begingroup$
@qbert I could only find a single transformation. Can you hint how to find others?
$endgroup$
– Ajay Choudhary
Dec 6 '18 at 5:02




$begingroup$
@qbert I could only find a single transformation. Can you hint how to find others?
$endgroup$
– Ajay Choudhary
Dec 6 '18 at 5:02












$begingroup$
To find others just extend ${(0,1,2),(1,1,1)}$ to a basis for $mathbb R^3$. For instance, you could use $(1,0,0)$. Then just map it to different vectors to get other examples.
$endgroup$
– Chris Custer
Dec 6 '18 at 5:58




$begingroup$
To find others just extend ${(0,1,2),(1,1,1)}$ to a basis for $mathbb R^3$. For instance, you could use $(1,0,0)$. Then just map it to different vectors to get other examples.
$endgroup$
– Chris Custer
Dec 6 '18 at 5:58












$begingroup$
If this is exactly the problem as it was presented to you (where did it come from, by the way?), then it’s common to assume that $T:mathbb R^3tomathbb R^3$ was intended. If this is from some textbook, compare this exercise to other examples and exercises in the book to be sure.
$endgroup$
– amd
Dec 6 '18 at 6:36




$begingroup$
If this is exactly the problem as it was presented to you (where did it come from, by the way?), then it’s common to assume that $T:mathbb R^3tomathbb R^3$ was intended. If this is from some textbook, compare this exercise to other examples and exercises in the book to be sure.
$endgroup$
– amd
Dec 6 '18 at 6:36




1




1




$begingroup$
There’s no way for anyone else to know for sure unless you provide a source or some other context for comparison. At any rate, the right person to ask is whomever is going to be grading your work.
$endgroup$
– amd
Dec 6 '18 at 19:15






$begingroup$
There’s no way for anyone else to know for sure unless you provide a source or some other context for comparison. At any rate, the right person to ask is whomever is going to be grading your work.
$endgroup$
– amd
Dec 6 '18 at 19:15












1 Answer
1






active

oldest

votes


















1












$begingroup$

If you want a linear transformation $T$ such that $T(u_1)=v_1$ and $T(u_2)=v_2$ where $u_1$ and $u_2$ are linearly independent, then we want $T(alpha u_1+beta u_2)=alpha T(u_1)+beta T(u_2)$ for scalars $alpha,beta$, and then $T$ is defined on the subspace $operatorname{span}(u_1,u_2)$. Also, the range will be $operatorname{span}(v_1,v_2)$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Yes, I was also thinking the same, but needed some corroboration. Thanks.
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:00


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

If you want a linear transformation $T$ such that $T(u_1)=v_1$ and $T(u_2)=v_2$ where $u_1$ and $u_2$ are linearly independent, then we want $T(alpha u_1+beta u_2)=alpha T(u_1)+beta T(u_2)$ for scalars $alpha,beta$, and then $T$ is defined on the subspace $operatorname{span}(u_1,u_2)$. Also, the range will be $operatorname{span}(v_1,v_2)$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Yes, I was also thinking the same, but needed some corroboration. Thanks.
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:00
















1












$begingroup$

If you want a linear transformation $T$ such that $T(u_1)=v_1$ and $T(u_2)=v_2$ where $u_1$ and $u_2$ are linearly independent, then we want $T(alpha u_1+beta u_2)=alpha T(u_1)+beta T(u_2)$ for scalars $alpha,beta$, and then $T$ is defined on the subspace $operatorname{span}(u_1,u_2)$. Also, the range will be $operatorname{span}(v_1,v_2)$.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Yes, I was also thinking the same, but needed some corroboration. Thanks.
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:00














1












1








1





$begingroup$

If you want a linear transformation $T$ such that $T(u_1)=v_1$ and $T(u_2)=v_2$ where $u_1$ and $u_2$ are linearly independent, then we want $T(alpha u_1+beta u_2)=alpha T(u_1)+beta T(u_2)$ for scalars $alpha,beta$, and then $T$ is defined on the subspace $operatorname{span}(u_1,u_2)$. Also, the range will be $operatorname{span}(v_1,v_2)$.






share|cite|improve this answer









$endgroup$



If you want a linear transformation $T$ such that $T(u_1)=v_1$ and $T(u_2)=v_2$ where $u_1$ and $u_2$ are linearly independent, then we want $T(alpha u_1+beta u_2)=alpha T(u_1)+beta T(u_2)$ for scalars $alpha,beta$, and then $T$ is defined on the subspace $operatorname{span}(u_1,u_2)$. Also, the range will be $operatorname{span}(v_1,v_2)$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 6 '18 at 4:55









DaveDave

8,76711033




8,76711033












  • $begingroup$
    Yes, I was also thinking the same, but needed some corroboration. Thanks.
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:00


















  • $begingroup$
    Yes, I was also thinking the same, but needed some corroboration. Thanks.
    $endgroup$
    – Ajay Choudhary
    Dec 6 '18 at 5:00
















$begingroup$
Yes, I was also thinking the same, but needed some corroboration. Thanks.
$endgroup$
– Ajay Choudhary
Dec 6 '18 at 5:00




$begingroup$
Yes, I was also thinking the same, but needed some corroboration. Thanks.
$endgroup$
– Ajay Choudhary
Dec 6 '18 at 5:00



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