Relationship between $l^p$ and $L^p$ space?











up vote
1
down vote

favorite












$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)



I give one definition of $l^p$ I've seen:



$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$



$l^p$ denotes the space of real sequences s with $||s||_p< infty$










share|cite|improve this question




















  • 1




    Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
    – User8128
    Nov 17 at 20:41















up vote
1
down vote

favorite












$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)



I give one definition of $l^p$ I've seen:



$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$



$l^p$ denotes the space of real sequences s with $||s||_p< infty$










share|cite|improve this question




















  • 1




    Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
    – User8128
    Nov 17 at 20:41













up vote
1
down vote

favorite









up vote
1
down vote

favorite











$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)



I give one definition of $l^p$ I've seen:



$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$



$l^p$ denotes the space of real sequences s with $||s||_p< infty$










share|cite|improve this question















$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)



I give one definition of $l^p$ I've seen:



$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$



$l^p$ denotes the space of real sequences s with $||s||_p< infty$







real-analysis functional-analysis






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 17 at 20:36

























asked Nov 17 at 20:23









The R

516




516








  • 1




    Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
    – User8128
    Nov 17 at 20:41














  • 1




    Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
    – User8128
    Nov 17 at 20:41








1




1




Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41




Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










Yes. The connection is, that both are the same kind of construction, but over different measure spaces.



The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
begin{align*}
||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
end{align*}



The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
begin{align*}
||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
end{align*}

integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
begin{align*}
int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
end{align*}

where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.






share|cite|improve this answer





















  • Thanks! It is so clear now.
    – The R
    Nov 17 at 20:44


















up vote
2
down vote













$L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
$$
int_Omega|f|^pdmu<+infty.
$$

$L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.






share|cite|improve this answer





















    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "69"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3002767%2frelationship-between-lp-and-lp-space%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    Yes. The connection is, that both are the same kind of construction, but over different measure spaces.



    The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
    begin{align*}
    ||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
    end{align*}



    The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
    begin{align*}
    ||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
    end{align*}

    integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
    begin{align*}
    int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
    end{align*}

    where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.






    share|cite|improve this answer





















    • Thanks! It is so clear now.
      – The R
      Nov 17 at 20:44















    up vote
    3
    down vote



    accepted










    Yes. The connection is, that both are the same kind of construction, but over different measure spaces.



    The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
    begin{align*}
    ||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
    end{align*}



    The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
    begin{align*}
    ||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
    end{align*}

    integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
    begin{align*}
    int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
    end{align*}

    where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.






    share|cite|improve this answer





















    • Thanks! It is so clear now.
      – The R
      Nov 17 at 20:44













    up vote
    3
    down vote



    accepted







    up vote
    3
    down vote



    accepted






    Yes. The connection is, that both are the same kind of construction, but over different measure spaces.



    The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
    begin{align*}
    ||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
    end{align*}



    The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
    begin{align*}
    ||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
    end{align*}

    integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
    begin{align*}
    int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
    end{align*}

    where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.






    share|cite|improve this answer












    Yes. The connection is, that both are the same kind of construction, but over different measure spaces.



    The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
    begin{align*}
    ||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
    end{align*}



    The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
    begin{align*}
    ||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
    end{align*}

    integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
    begin{align*}
    int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
    end{align*}

    where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Nov 17 at 20:41









    N.Beck

    1665




    1665












    • Thanks! It is so clear now.
      – The R
      Nov 17 at 20:44


















    • Thanks! It is so clear now.
      – The R
      Nov 17 at 20:44
















    Thanks! It is so clear now.
    – The R
    Nov 17 at 20:44




    Thanks! It is so clear now.
    – The R
    Nov 17 at 20:44










    up vote
    2
    down vote













    $L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
    $$
    int_Omega|f|^pdmu<+infty.
    $$

    $L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.






    share|cite|improve this answer

























      up vote
      2
      down vote













      $L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
      $$
      int_Omega|f|^pdmu<+infty.
      $$

      $L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.






      share|cite|improve this answer























        up vote
        2
        down vote










        up vote
        2
        down vote









        $L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
        $$
        int_Omega|f|^pdmu<+infty.
        $$

        $L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.






        share|cite|improve this answer












        $L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
        $$
        int_Omega|f|^pdmu<+infty.
        $$

        $L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 17 at 20:41









        Marco

        1909




        1909






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Mathematics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3002767%2frelationship-between-lp-and-lp-space%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Index of /

            Tribalistas

            Listed building