Relationship between $l^p$ and $L^p$ space?
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$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)
I give one definition of $l^p$ I've seen:
$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$
$l^p$ denotes the space of real sequences s with $||s||_p< infty$
real-analysis functional-analysis
add a comment |
up vote
1
down vote
favorite
$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)
I give one definition of $l^p$ I've seen:
$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$
$l^p$ denotes the space of real sequences s with $||s||_p< infty$
real-analysis functional-analysis
1
Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)
I give one definition of $l^p$ I've seen:
$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$
$l^p$ denotes the space of real sequences s with $||s||_p< infty$
real-analysis functional-analysis
$l^p$ appears frequently in undergrad real analysis courses, I wonder if there is any strong connection between $l^p$ and $L^p$ space? (Other than they look similar)
I give one definition of $l^p$ I've seen:
$begin{equation} ||s||_p=begin{cases}
sup_{ninmathbb{N}}left(sum_{i=1}^{n}|s_i|^pright)^{1/p},if
~1leq p<infty\
sup_{ninmathbb{N}}|s_n|, if~ p=infty
end{cases}end{equation}$
$l^p$ denotes the space of real sequences s with $||s||_p< infty$
real-analysis functional-analysis
real-analysis functional-analysis
edited Nov 17 at 20:36
asked Nov 17 at 20:23
The R
516
516
1
Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41
add a comment |
1
Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41
1
1
Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41
Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41
add a comment |
2 Answers
2
active
oldest
votes
up vote
3
down vote
accepted
Yes. The connection is, that both are the same kind of construction, but over different measure spaces.
The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
begin{align*}
||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
end{align*}
The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
begin{align*}
||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
end{align*}
integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
begin{align*}
int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
end{align*}
where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.
Thanks! It is so clear now.
– The R
Nov 17 at 20:44
add a comment |
up vote
2
down vote
$L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
$$
int_Omega|f|^pdmu<+infty.
$$
$L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
Yes. The connection is, that both are the same kind of construction, but over different measure spaces.
The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
begin{align*}
||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
end{align*}
The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
begin{align*}
||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
end{align*}
integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
begin{align*}
int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
end{align*}
where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.
Thanks! It is so clear now.
– The R
Nov 17 at 20:44
add a comment |
up vote
3
down vote
accepted
Yes. The connection is, that both are the same kind of construction, but over different measure spaces.
The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
begin{align*}
||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
end{align*}
The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
begin{align*}
||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
end{align*}
integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
begin{align*}
int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
end{align*}
where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.
Thanks! It is so clear now.
– The R
Nov 17 at 20:44
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
Yes. The connection is, that both are the same kind of construction, but over different measure spaces.
The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
begin{align*}
||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
end{align*}
The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
begin{align*}
||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
end{align*}
integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
begin{align*}
int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
end{align*}
where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.
Yes. The connection is, that both are the same kind of construction, but over different measure spaces.
The standard definition of $l^p$ spaces is: $l^p = {x: mathbb N to mathbb R|quad ||x||_p<infty}$ where
begin{align*}
||x||_p = left(sum_{ninmathbb N} |x(n)|^pright)^{1/p}
end{align*}
The standard definition of $L^p$ spaces is ${f: X to mathbb R |quad ||f||_p < infty}$ where $X$ is some compact subset of $mathbb R$ or sometimes even $mathbb R$ and
begin{align*}
||f||_p =left( int _X |f|^p, dlambda right)^{1/p}
end{align*}
integration with respect to the Lebesgue measure on the real line. Look how similar they are. The connection is: Let $(mathbb N, mathcal P(mathbb N), mu)$ be a measure space, where $mu$ is the counting measure, i.e. $mu({n})=1$ for all $nin mathbb N$ and $mu$ $sigma$-additive. Then
begin{align*}
int_{mathbb N} |x|^p, dmu = sum_{ninmathbb N} |x(n)|^p
end{align*}
where $x: mathbb N to mathbb R$ is some measurable function, i.e. a sequence. So they really are nearly the same thing and many measure theoretic results hold for both.
answered Nov 17 at 20:41
N.Beck
1665
1665
Thanks! It is so clear now.
– The R
Nov 17 at 20:44
add a comment |
Thanks! It is so clear now.
– The R
Nov 17 at 20:44
Thanks! It is so clear now.
– The R
Nov 17 at 20:44
Thanks! It is so clear now.
– The R
Nov 17 at 20:44
add a comment |
up vote
2
down vote
$L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
$$
int_Omega|f|^pdmu<+infty.
$$
$L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.
add a comment |
up vote
2
down vote
$L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
$$
int_Omega|f|^pdmu<+infty.
$$
$L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.
add a comment |
up vote
2
down vote
up vote
2
down vote
$L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
$$
int_Omega|f|^pdmu<+infty.
$$
$L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.
$L^p$ and $ell^p$ spaces both come from the same definition in measure theory. Given a measure space $(Omega,Sigma,mu)$ you can define $L^p(Omega,Sigma,mu)$ as the set of all $mu$-measurable functions defined on $Omega$ such that
$$
int_Omega|f|^pdmu<+infty.
$$
$L^p$ is simply $L^p(mathbb{R},mathcal{B},Leb)$, where $mathcal{B}$ is the Borel $sigma$-algebra and $Leb$ is the Lebesgue measure. On the other hand, $ell^p=L^p(mathbb{N},mathcal{P}(mathbb{N}),c)$ where $mathcal{P}(mathbb{N})$ is the $sigma$-algebra of the parts of $mathbb{N}$ and $c$ is the counting measure.
answered Nov 17 at 20:41
Marco
1909
1909
add a comment |
add a comment |
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1
Yes, measure theory is the unifying theory here. Any time you have a measure space you can define $L^p$ spaces. The typical $L^p$ spaces use the Lebesgue measure on $mathbb R^n$, whereas the $ell^p$ spaces use the counting measure on $mathbb N$.
– User8128
Nov 17 at 20:41