Deducing the value of one parameter
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0
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I'm working with Javascript and I need some help because I'm not great at math. I have the following code:
let x = (1 - t) * (1 - t) * (1 - t) * x0
+ 3 * (1 - t) * (1 - t) * t * x1
+ 3 * (1 - t) * t * t * x2
+ t * t * t * x3;
I know the values of x, x0, x1, x2 and x3. Is it possible to deduce the value of t?
algebras
asked Nov 17 at 19:37
enxaneta
1011
add a comment |
up vote
0
down vote
favorite
I'm working with Javascript and I need some help because I'm not great at math. I have the following code:
let x = (1 - t) * (1 - t) * (1 - t) * x0
+ 3 * (1 - t) * (1 - t) * t * x1
+ 3 * (1 - t) * t * t * x2
+ t * t * t * x3;
I know the values of x, x0, x1, x2 and x3. Is it possible to deduce the value of t?
algebras
asked Nov 17 at 19:37
enxaneta
1011
Do you know Cardano's method to solve third degree equation.
– hamam_Abdallah
Nov 17 at 19:44
No, I'm sorry, I don't
– enxaneta
Nov 17 at 19:49
1
Google it and you will get an idea.
– hamam_Abdallah
Nov 17 at 19:50
1
First you should expand out the expression so it has the following form: $at^3 + bt^2 + ct + (d-x) = 0$, where $a,b,c,d$ will be functions of $x_0,x_1,x_2,x_3$. Then you can use Cardano's method. You can implement it yourself, but you may even be able to find template code online or a built in library in JS.
– Aditya Dua
Nov 18 at 3:49
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm working with Javascript and I need some help because I'm not great at math. I have the following code:
let x = (1 - t) * (1 - t) * (1 - t) * x0
+ 3 * (1 - t) * (1 - t) * t * x1
+ 3 * (1 - t) * t * t * x2
+ t * t * t * x3;
I know the values of x, x0, x1, x2 and x3. Is it possible to deduce the value of t?
algebras
asked Nov 17 at 19:37
enxaneta
1011
I'm working with Javascript and I need some help because I'm not great at math. I have the following code:
let x = (1 - t) * (1 - t) * (1 - t) * x0
+ 3 * (1 - t) * (1 - t) * t * x1
+ 3 * (1 - t) * t * t * x2
+ t * t * t * x3;
I know the values of x, x0, x1, x2 and x3. Is it possible to deduce the value of t?
algebras
algebras
asked Nov 17 at 19:37
enxaneta
1011
asked Nov 17 at 19:37
enxaneta
1011
asked Nov 17 at 19:37
enxaneta
1011
asked Nov 17 at 19:37
enxaneta
1011
asked Nov 17 at 19:37
enxaneta
1011
1011
Do you know Cardano's method to solve third degree equation.
– hamam_Abdallah
Nov 17 at 19:44
No, I'm sorry, I don't
– enxaneta
Nov 17 at 19:49
1
Google it and you will get an idea.
– hamam_Abdallah
Nov 17 at 19:50
1
First you should expand out the expression so it has the following form: $at^3 + bt^2 + ct + (d-x) = 0$, where $a,b,c,d$ will be functions of $x_0,x_1,x_2,x_3$. Then you can use Cardano's method. You can implement it yourself, but you may even be able to find template code online or a built in library in JS.
– Aditya Dua
Nov 18 at 3:49
add a comment |
Do you know Cardano's method to solve third degree equation.
– hamam_Abdallah
Nov 17 at 19:44
No, I'm sorry, I don't
– enxaneta
Nov 17 at 19:49
1
Google it and you will get an idea.
– hamam_Abdallah
Nov 17 at 19:50
1
First you should expand out the expression so it has the following form: $at^3 + bt^2 + ct + (d-x) = 0$, where $a,b,c,d$ will be functions of $x_0,x_1,x_2,x_3$. Then you can use Cardano's method. You can implement it yourself, but you may even be able to find template code online or a built in library in JS.
– Aditya Dua
Nov 18 at 3:49
Do you know Cardano's method to solve third degree equation.
– hamam_Abdallah
Nov 17 at 19:44
Do you know Cardano's method to solve third degree equation.
– hamam_Abdallah
Nov 17 at 19:44
No, I'm sorry, I don't
– enxaneta
Nov 17 at 19:49
No, I'm sorry, I don't
– enxaneta
Nov 17 at 19:49
1
1
Google it and you will get an idea.
– hamam_Abdallah
Nov 17 at 19:50
Google it and you will get an idea.
– hamam_Abdallah
Nov 17 at 19:50
1
1
First you should expand out the expression so it has the following form: $at^3 + bt^2 + ct + (d-x) = 0$, where $a,b,c,d$ will be functions of $x_0,x_1,x_2,x_3$. Then you can use Cardano's method. You can implement it yourself, but you may even be able to find template code online or a built in library in JS.
– Aditya Dua
Nov 18 at 3:49
First you should expand out the expression so it has the following form: $at^3 + bt^2 + ct + (d-x) = 0$, where $a,b,c,d$ will be functions of $x_0,x_1,x_2,x_3$. Then you can use Cardano's method. You can implement it yourself, but you may even be able to find template code online or a built in library in JS.
– Aditya Dua
Nov 18 at 3:49
add a comment |
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Do you know Cardano's method to solve third degree equation.
– hamam_Abdallah
Nov 17 at 19:44
No, I'm sorry, I don't
– enxaneta
Nov 17 at 19:49
1
Google it and you will get an idea.
– hamam_Abdallah
Nov 17 at 19:50
1
First you should expand out the expression so it has the following form: $at^3 + bt^2 + ct + (d-x) = 0$, where $a,b,c,d$ will be functions of $x_0,x_1,x_2,x_3$. Then you can use Cardano's method. You can implement it yourself, but you may even be able to find template code online or a built in library in JS.
– Aditya Dua
Nov 18 at 3:49