How to transform this Diffusion equation ?
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I have a diffusion equation:
$$ nabla^2C = frac{partial C}{partial t}$$.
Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.
Can anyone explain how to go about it ?
differential-equations pde transformation substitution
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up vote
0
down vote
favorite
I have a diffusion equation:
$$ nabla^2C = frac{partial C}{partial t}$$.
Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.
Can anyone explain how to go about it ?
differential-equations pde transformation substitution
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a diffusion equation:
$$ nabla^2C = frac{partial C}{partial t}$$.
Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.
Can anyone explain how to go about it ?
differential-equations pde transformation substitution
I have a diffusion equation:
$$ nabla^2C = frac{partial C}{partial t}$$.
Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.
Can anyone explain how to go about it ?
differential-equations pde transformation substitution
differential-equations pde transformation substitution
edited Nov 13 at 10:24
asked Nov 13 at 10:12
newstudent
154
154
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1 Answer
1
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up vote
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The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
$$
frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
$$
Therefore, the equation is now
$$
nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
$$
i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
$$
frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
$$
Therefore, the equation is now
$$
nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
$$
i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.
add a comment |
up vote
0
down vote
accepted
The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
$$
frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
$$
Therefore, the equation is now
$$
nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
$$
i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
$$
frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
$$
Therefore, the equation is now
$$
nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
$$
i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.
The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
$$
frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
$$
Therefore, the equation is now
$$
nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
$$
i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.
answered Nov 13 at 12:59
rafa11111
748315
748315
add a comment |
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