How to transform this Diffusion equation ?











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I have a diffusion equation:



$$ nabla^2C = frac{partial C}{partial t}$$.



Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.



Can anyone explain how to go about it ?










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    up vote
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    down vote

    favorite












    I have a diffusion equation:



    $$ nabla^2C = frac{partial C}{partial t}$$.



    Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.



    Can anyone explain how to go about it ?










    share|cite|improve this question


























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have a diffusion equation:



      $$ nabla^2C = frac{partial C}{partial t}$$.



      Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.



      Can anyone explain how to go about it ?










      share|cite|improve this question















      I have a diffusion equation:



      $$ nabla^2C = frac{partial C}{partial t}$$.



      Now I would like to transform this equation into a co-ordiante frame which movies with the unperturbed palaner interface($z=0$ ) with steady state veloity $v_o$, i.e. $z = z -v_0t$.



      Can anyone explain how to go about it ?







      differential-equations pde transformation substitution






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      edited Nov 13 at 10:24

























      asked Nov 13 at 10:12









      newstudent

      154




      154






















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          The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
          $$
          frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
          $$



          Therefore, the equation is now
          $$
          nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
          $$

          i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.






          share|cite|improve this answer





















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            1 Answer
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            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

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            active

            oldest

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            up vote
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            down vote



            accepted










            The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
            $$
            frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
            $$



            Therefore, the equation is now
            $$
            nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
            $$

            i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.






            share|cite|improve this answer

























              up vote
              0
              down vote



              accepted










              The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
              $$
              frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
              $$



              Therefore, the equation is now
              $$
              nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
              $$

              i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.






              share|cite|improve this answer























                up vote
                0
                down vote



                accepted







                up vote
                0
                down vote



                accepted






                The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
                $$
                frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
                $$



                Therefore, the equation is now
                $$
                nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
                $$

                i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.






                share|cite|improve this answer












                The current variables are the position $mathbf{x}$ and the time $t$, that will be transformed to $mathbf{x}'=mathbf{x}-mathbf{v}_0 t$ and $t'=t$. According to the chain rule,
                $$
                frac{partial}{partial t} = frac{partial t'}{partial t} frac{partial}{partial t'} + frac{partial x'}{partial t} frac{partial}{partial x'} + frac{partial y'}{partial t} frac{partial}{partial y'}+ frac{partial z'}{partial t} frac{partial}{partial z'} = frac{partial}{partial t'} + mathbf{v}_0 cdot nabla
                $$



                Therefore, the equation is now
                $$
                nabla^2 C = frac{partial C}{partial t} + mathbf{v}_0 cdot nabla C,
                $$

                i.e., in the moving frame the diffusion equation takes the form of an advection-diffusion equation. Naturally, using $mathbf{v}_0=0$ in the equation leads back to the original diffusion equation.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 13 at 12:59









                rafa11111

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