Foliated de Rham Cohomology - Fiberwise Exact Implies Exact?











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Let $F:X to Y$ be a surjective submersion between smooth manifolds. Consider the induced foliated de Rham cohomology on $X$. Is it true that if a closed form is leafwise exact, then it is exact in foliated cohomology? If not, are there other conditions that will ensure a leafwise exact form is exact? I'm fine with assuming the submersion has a section, and maybe some connectedness assumptions of the leaves. References would be appreciated.










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    Let $F:X to Y$ be a surjective submersion between smooth manifolds. Consider the induced foliated de Rham cohomology on $X$. Is it true that if a closed form is leafwise exact, then it is exact in foliated cohomology? If not, are there other conditions that will ensure a leafwise exact form is exact? I'm fine with assuming the submersion has a section, and maybe some connectedness assumptions of the leaves. References would be appreciated.










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      Let $F:X to Y$ be a surjective submersion between smooth manifolds. Consider the induced foliated de Rham cohomology on $X$. Is it true that if a closed form is leafwise exact, then it is exact in foliated cohomology? If not, are there other conditions that will ensure a leafwise exact form is exact? I'm fine with assuming the submersion has a section, and maybe some connectedness assumptions of the leaves. References would be appreciated.










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      Let $F:X to Y$ be a surjective submersion between smooth manifolds. Consider the induced foliated de Rham cohomology on $X$. Is it true that if a closed form is leafwise exact, then it is exact in foliated cohomology? If not, are there other conditions that will ensure a leafwise exact form is exact? I'm fine with assuming the submersion has a section, and maybe some connectedness assumptions of the leaves. References would be appreciated.







      smooth-manifolds de-rham-cohomology foliations






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