Finding angle of sector which forms a cone
$begingroup$
To find the angle where it is in rad,
am I right to say that $10*(angle in rad)=2pi*(radius of cone)$
calculus
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add a comment |
$begingroup$
To find the angle where it is in rad,
am I right to say that $10*(angle in rad)=2pi*(radius of cone)$
calculus
$endgroup$
add a comment |
$begingroup$
To find the angle where it is in rad,
am I right to say that $10*(angle in rad)=2pi*(radius of cone)$
calculus
$endgroup$
To find the angle where it is in rad,
am I right to say that $10*(angle in rad)=2pi*(radius of cone)$
calculus
calculus
edited Jul 27 '16 at 17:40
Widawensen
4,81531447
4,81531447
asked Mar 27 '14 at 11:31
Jake MitchJake Mitch
847
847
add a comment |
add a comment |
1 Answer
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$begingroup$
The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
$$theta=frac{2pi r}{2pi l}=frac rl$$
measured in radians.
$endgroup$
$begingroup$
Why do you divide by $2pi l$ instead of just $l$?
$endgroup$
– Christoph
Mar 27 '14 at 11:56
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
$$theta=frac{2pi r}{2pi l}=frac rl$$
measured in radians.
$endgroup$
$begingroup$
Why do you divide by $2pi l$ instead of just $l$?
$endgroup$
– Christoph
Mar 27 '14 at 11:56
add a comment |
$begingroup$
The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
$$theta=frac{2pi r}{2pi l}=frac rl$$
measured in radians.
$endgroup$
$begingroup$
Why do you divide by $2pi l$ instead of just $l$?
$endgroup$
– Christoph
Mar 27 '14 at 11:56
add a comment |
$begingroup$
The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
$$theta=frac{2pi r}{2pi l}=frac rl$$
measured in radians.
$endgroup$
The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
$$theta=frac{2pi r}{2pi l}=frac rl$$
measured in radians.
answered Mar 27 '14 at 11:40
ajotatxeajotatxe
54.2k24190
54.2k24190
$begingroup$
Why do you divide by $2pi l$ instead of just $l$?
$endgroup$
– Christoph
Mar 27 '14 at 11:56
add a comment |
$begingroup$
Why do you divide by $2pi l$ instead of just $l$?
$endgroup$
– Christoph
Mar 27 '14 at 11:56
$begingroup$
Why do you divide by $2pi l$ instead of just $l$?
$endgroup$
– Christoph
Mar 27 '14 at 11:56
$begingroup$
Why do you divide by $2pi l$ instead of just $l$?
$endgroup$
– Christoph
Mar 27 '14 at 11:56
add a comment |
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