Finding angle of sector which forms a cone












1












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To find the angle where it is in rad,
am I right to say that $10*(angle in rad)=2pi*(radius of cone)$



Cone










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    1












    $begingroup$


    To find the angle where it is in rad,
    am I right to say that $10*(angle in rad)=2pi*(radius of cone)$



    Cone










    share|cite|improve this question











    $endgroup$















      1












      1








      1





      $begingroup$


      To find the angle where it is in rad,
      am I right to say that $10*(angle in rad)=2pi*(radius of cone)$



      Cone










      share|cite|improve this question











      $endgroup$




      To find the angle where it is in rad,
      am I right to say that $10*(angle in rad)=2pi*(radius of cone)$



      Cone







      calculus






      share|cite|improve this question















      share|cite|improve this question













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      share|cite|improve this question








      edited Jul 27 '16 at 17:40









      Widawensen

      4,81531447




      4,81531447










      asked Mar 27 '14 at 11:31









      Jake MitchJake Mitch

      847




      847






















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          $begingroup$

          The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
          $$theta=frac{2pi r}{2pi l}=frac rl$$
          measured in radians.






          share|cite|improve this answer









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          • $begingroup$
            Why do you divide by $2pi l$ instead of just $l$?
            $endgroup$
            – Christoph
            Mar 27 '14 at 11:56












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          0












          $begingroup$

          The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
          $$theta=frac{2pi r}{2pi l}=frac rl$$
          measured in radians.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Why do you divide by $2pi l$ instead of just $l$?
            $endgroup$
            – Christoph
            Mar 27 '14 at 11:56
















          0












          $begingroup$

          The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
          $$theta=frac{2pi r}{2pi l}=frac rl$$
          measured in radians.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Why do you divide by $2pi l$ instead of just $l$?
            $endgroup$
            – Christoph
            Mar 27 '14 at 11:56














          0












          0








          0





          $begingroup$

          The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
          $$theta=frac{2pi r}{2pi l}=frac rl$$
          measured in radians.






          share|cite|improve this answer









          $endgroup$



          The radius of the sector is the lateral height $l$ of the cone, and the length of the arc is the circumference of the base, that is, $2pi r$. So the angle you ask for is
          $$theta=frac{2pi r}{2pi l}=frac rl$$
          measured in radians.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 27 '14 at 11:40









          ajotatxeajotatxe

          54.2k24190




          54.2k24190












          • $begingroup$
            Why do you divide by $2pi l$ instead of just $l$?
            $endgroup$
            – Christoph
            Mar 27 '14 at 11:56


















          • $begingroup$
            Why do you divide by $2pi l$ instead of just $l$?
            $endgroup$
            – Christoph
            Mar 27 '14 at 11:56
















          $begingroup$
          Why do you divide by $2pi l$ instead of just $l$?
          $endgroup$
          – Christoph
          Mar 27 '14 at 11:56




          $begingroup$
          Why do you divide by $2pi l$ instead of just $l$?
          $endgroup$
          – Christoph
          Mar 27 '14 at 11:56


















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