What is integral of a scalar field with respect to a variable?
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I was reading Tom Apostol calculus volume 2 and came across theorem 10.8 (page 350)
The theorem is:
My doubt is, What is the definition of the right hand side of the underlined equation that is, What is the definition of $$int_{a}^b psi(vec x,t)dt $$, this integral formally? I know integral of real valued function formally to some extent? But what is the FORMAL DEFINITION OF THIS INTEGRAL?
real-analysis calculus functional-analysis multivariable-calculus vector-analysis
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add a comment |
$begingroup$
I was reading Tom Apostol calculus volume 2 and came across theorem 10.8 (page 350)
The theorem is:
My doubt is, What is the definition of the right hand side of the underlined equation that is, What is the definition of $$int_{a}^b psi(vec x,t)dt $$, this integral formally? I know integral of real valued function formally to some extent? But what is the FORMAL DEFINITION OF THIS INTEGRAL?
real-analysis calculus functional-analysis multivariable-calculus vector-analysis
$endgroup$
add a comment |
$begingroup$
I was reading Tom Apostol calculus volume 2 and came across theorem 10.8 (page 350)
The theorem is:
My doubt is, What is the definition of the right hand side of the underlined equation that is, What is the definition of $$int_{a}^b psi(vec x,t)dt $$, this integral formally? I know integral of real valued function formally to some extent? But what is the FORMAL DEFINITION OF THIS INTEGRAL?
real-analysis calculus functional-analysis multivariable-calculus vector-analysis
$endgroup$
I was reading Tom Apostol calculus volume 2 and came across theorem 10.8 (page 350)
The theorem is:
My doubt is, What is the definition of the right hand side of the underlined equation that is, What is the definition of $$int_{a}^b psi(vec x,t)dt $$, this integral formally? I know integral of real valued function formally to some extent? But what is the FORMAL DEFINITION OF THIS INTEGRAL?
real-analysis calculus functional-analysis multivariable-calculus vector-analysis
real-analysis calculus functional-analysis multivariable-calculus vector-analysis
asked Dec 27 '18 at 17:46
Bijayan RayBijayan Ray
136112
136112
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1 Answer
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You're confused because $psi(vec{x},,t)$ depends on multiple variables. But for each value of $vec{x}$, $psi(vec{x},,t)$ becomes just a function of $t$; you know how to integrate that. This recipe gives each $varphi(vec{x})$, thus defining the function $varphi$.
$endgroup$
$begingroup$
I had thought of that about defining a different function g for each $vec x$, as a function of only t, then integrating g. But then how would you explain the next equation that is taking the partial derivative of $phi(vec x)$ ?
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– Bijayan Ray
Dec 28 '18 at 5:09
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@BijayanRag You have s function of $vec{x}$; differentiate it.
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– J.G.
Dec 28 '18 at 7:18
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your statement about function g (as per my last comment) is :- for all $vec x$ there exist a function g such that $psi (vec x,t)$=g(t)
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:38
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can you please tell me in formal words where are you getting a function of $vec x$ to differentiate?
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– Bijayan Ray
Dec 28 '18 at 10:42
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I think what I want to tell from the comments above is similar to the logical difference between uniform convergence and pointwise convergence & and also similar to logic behind existence of all directional derivative does not imply continuity
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:52
|
show 5 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You're confused because $psi(vec{x},,t)$ depends on multiple variables. But for each value of $vec{x}$, $psi(vec{x},,t)$ becomes just a function of $t$; you know how to integrate that. This recipe gives each $varphi(vec{x})$, thus defining the function $varphi$.
$endgroup$
$begingroup$
I had thought of that about defining a different function g for each $vec x$, as a function of only t, then integrating g. But then how would you explain the next equation that is taking the partial derivative of $phi(vec x)$ ?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 5:09
$begingroup$
@BijayanRag You have s function of $vec{x}$; differentiate it.
$endgroup$
– J.G.
Dec 28 '18 at 7:18
$begingroup$
your statement about function g (as per my last comment) is :- for all $vec x$ there exist a function g such that $psi (vec x,t)$=g(t)
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:38
$begingroup$
can you please tell me in formal words where are you getting a function of $vec x$ to differentiate?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:42
$begingroup$
I think what I want to tell from the comments above is similar to the logical difference between uniform convergence and pointwise convergence & and also similar to logic behind existence of all directional derivative does not imply continuity
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:52
|
show 5 more comments
$begingroup$
You're confused because $psi(vec{x},,t)$ depends on multiple variables. But for each value of $vec{x}$, $psi(vec{x},,t)$ becomes just a function of $t$; you know how to integrate that. This recipe gives each $varphi(vec{x})$, thus defining the function $varphi$.
$endgroup$
$begingroup$
I had thought of that about defining a different function g for each $vec x$, as a function of only t, then integrating g. But then how would you explain the next equation that is taking the partial derivative of $phi(vec x)$ ?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 5:09
$begingroup$
@BijayanRag You have s function of $vec{x}$; differentiate it.
$endgroup$
– J.G.
Dec 28 '18 at 7:18
$begingroup$
your statement about function g (as per my last comment) is :- for all $vec x$ there exist a function g such that $psi (vec x,t)$=g(t)
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:38
$begingroup$
can you please tell me in formal words where are you getting a function of $vec x$ to differentiate?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:42
$begingroup$
I think what I want to tell from the comments above is similar to the logical difference between uniform convergence and pointwise convergence & and also similar to logic behind existence of all directional derivative does not imply continuity
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:52
|
show 5 more comments
$begingroup$
You're confused because $psi(vec{x},,t)$ depends on multiple variables. But for each value of $vec{x}$, $psi(vec{x},,t)$ becomes just a function of $t$; you know how to integrate that. This recipe gives each $varphi(vec{x})$, thus defining the function $varphi$.
$endgroup$
You're confused because $psi(vec{x},,t)$ depends on multiple variables. But for each value of $vec{x}$, $psi(vec{x},,t)$ becomes just a function of $t$; you know how to integrate that. This recipe gives each $varphi(vec{x})$, thus defining the function $varphi$.
answered Dec 27 '18 at 17:59
J.G.J.G.
30.6k23149
30.6k23149
$begingroup$
I had thought of that about defining a different function g for each $vec x$, as a function of only t, then integrating g. But then how would you explain the next equation that is taking the partial derivative of $phi(vec x)$ ?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 5:09
$begingroup$
@BijayanRag You have s function of $vec{x}$; differentiate it.
$endgroup$
– J.G.
Dec 28 '18 at 7:18
$begingroup$
your statement about function g (as per my last comment) is :- for all $vec x$ there exist a function g such that $psi (vec x,t)$=g(t)
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:38
$begingroup$
can you please tell me in formal words where are you getting a function of $vec x$ to differentiate?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:42
$begingroup$
I think what I want to tell from the comments above is similar to the logical difference between uniform convergence and pointwise convergence & and also similar to logic behind existence of all directional derivative does not imply continuity
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:52
|
show 5 more comments
$begingroup$
I had thought of that about defining a different function g for each $vec x$, as a function of only t, then integrating g. But then how would you explain the next equation that is taking the partial derivative of $phi(vec x)$ ?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 5:09
$begingroup$
@BijayanRag You have s function of $vec{x}$; differentiate it.
$endgroup$
– J.G.
Dec 28 '18 at 7:18
$begingroup$
your statement about function g (as per my last comment) is :- for all $vec x$ there exist a function g such that $psi (vec x,t)$=g(t)
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:38
$begingroup$
can you please tell me in formal words where are you getting a function of $vec x$ to differentiate?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:42
$begingroup$
I think what I want to tell from the comments above is similar to the logical difference between uniform convergence and pointwise convergence & and also similar to logic behind existence of all directional derivative does not imply continuity
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:52
$begingroup$
I had thought of that about defining a different function g for each $vec x$, as a function of only t, then integrating g. But then how would you explain the next equation that is taking the partial derivative of $phi(vec x)$ ?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 5:09
$begingroup$
I had thought of that about defining a different function g for each $vec x$, as a function of only t, then integrating g. But then how would you explain the next equation that is taking the partial derivative of $phi(vec x)$ ?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 5:09
$begingroup$
@BijayanRag You have s function of $vec{x}$; differentiate it.
$endgroup$
– J.G.
Dec 28 '18 at 7:18
$begingroup$
@BijayanRag You have s function of $vec{x}$; differentiate it.
$endgroup$
– J.G.
Dec 28 '18 at 7:18
$begingroup$
your statement about function g (as per my last comment) is :- for all $vec x$ there exist a function g such that $psi (vec x,t)$=g(t)
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:38
$begingroup$
your statement about function g (as per my last comment) is :- for all $vec x$ there exist a function g such that $psi (vec x,t)$=g(t)
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:38
$begingroup$
can you please tell me in formal words where are you getting a function of $vec x$ to differentiate?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:42
$begingroup$
can you please tell me in formal words where are you getting a function of $vec x$ to differentiate?
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:42
$begingroup$
I think what I want to tell from the comments above is similar to the logical difference between uniform convergence and pointwise convergence & and also similar to logic behind existence of all directional derivative does not imply continuity
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:52
$begingroup$
I think what I want to tell from the comments above is similar to the logical difference between uniform convergence and pointwise convergence & and also similar to logic behind existence of all directional derivative does not imply continuity
$endgroup$
– Bijayan Ray
Dec 28 '18 at 10:52
|
show 5 more comments
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