Generalized Circumcenter: minimizing the range of distances from a point to the vertices of a polygon
$begingroup$
It is well known that the circumcenter of a polygon exists if and only if the polygon is cyclic.
I would like to extend the definition of a circumcenter for noncyclic polygons.
Let us define $c(A)$ as the range of the lengths of the distances from $A$ to the vertices of the polygon; that is, the longest minus shortest distance from $A$ to the vertices of the polygon. The range is chosen as a simple measure of spread.
If there exists an $A_0$ such that $0 leq c(A_0) < c(A)$ for all $A$ not equal to $A_0$, and $A_0$ is not equivalently at infinity, then this $A_0$ is defined to be the generalized circumcenter of the polygon.
Note that this generalization follows from the fact that the distances from the circumcenter to the vertices of a cyclic polygon are equal to each other.
Does the generalized circumcenter exist for all n-gons?
geometry statistics euclidean-geometry
$endgroup$
add a comment |
$begingroup$
It is well known that the circumcenter of a polygon exists if and only if the polygon is cyclic.
I would like to extend the definition of a circumcenter for noncyclic polygons.
Let us define $c(A)$ as the range of the lengths of the distances from $A$ to the vertices of the polygon; that is, the longest minus shortest distance from $A$ to the vertices of the polygon. The range is chosen as a simple measure of spread.
If there exists an $A_0$ such that $0 leq c(A_0) < c(A)$ for all $A$ not equal to $A_0$, and $A_0$ is not equivalently at infinity, then this $A_0$ is defined to be the generalized circumcenter of the polygon.
Note that this generalization follows from the fact that the distances from the circumcenter to the vertices of a cyclic polygon are equal to each other.
Does the generalized circumcenter exist for all n-gons?
geometry statistics euclidean-geometry
$endgroup$
$begingroup$
What does $A_0$ ` is not equivalently at infinity` mean?
$endgroup$
– sds
Jan 2 at 21:17
$begingroup$
If we define $A_0$ arbitrarily far away then we can make $c(A_0)$ as close to zero as possible, since the range of the lengths of the distances from $A_0$ to the vertices of the polygon would increase as $A_0$ tends to infinity. This is not what we want, so I have excluded it in the definition.
$endgroup$
– pacosta
Jan 5 at 0:21
add a comment |
$begingroup$
It is well known that the circumcenter of a polygon exists if and only if the polygon is cyclic.
I would like to extend the definition of a circumcenter for noncyclic polygons.
Let us define $c(A)$ as the range of the lengths of the distances from $A$ to the vertices of the polygon; that is, the longest minus shortest distance from $A$ to the vertices of the polygon. The range is chosen as a simple measure of spread.
If there exists an $A_0$ such that $0 leq c(A_0) < c(A)$ for all $A$ not equal to $A_0$, and $A_0$ is not equivalently at infinity, then this $A_0$ is defined to be the generalized circumcenter of the polygon.
Note that this generalization follows from the fact that the distances from the circumcenter to the vertices of a cyclic polygon are equal to each other.
Does the generalized circumcenter exist for all n-gons?
geometry statistics euclidean-geometry
$endgroup$
It is well known that the circumcenter of a polygon exists if and only if the polygon is cyclic.
I would like to extend the definition of a circumcenter for noncyclic polygons.
Let us define $c(A)$ as the range of the lengths of the distances from $A$ to the vertices of the polygon; that is, the longest minus shortest distance from $A$ to the vertices of the polygon. The range is chosen as a simple measure of spread.
If there exists an $A_0$ such that $0 leq c(A_0) < c(A)$ for all $A$ not equal to $A_0$, and $A_0$ is not equivalently at infinity, then this $A_0$ is defined to be the generalized circumcenter of the polygon.
Note that this generalization follows from the fact that the distances from the circumcenter to the vertices of a cyclic polygon are equal to each other.
Does the generalized circumcenter exist for all n-gons?
geometry statistics euclidean-geometry
geometry statistics euclidean-geometry
edited Jan 2 at 23:01
Blue
49.3k870157
49.3k870157
asked Jan 2 at 21:08
pacostapacosta
1535
1535
$begingroup$
What does $A_0$ ` is not equivalently at infinity` mean?
$endgroup$
– sds
Jan 2 at 21:17
$begingroup$
If we define $A_0$ arbitrarily far away then we can make $c(A_0)$ as close to zero as possible, since the range of the lengths of the distances from $A_0$ to the vertices of the polygon would increase as $A_0$ tends to infinity. This is not what we want, so I have excluded it in the definition.
$endgroup$
– pacosta
Jan 5 at 0:21
add a comment |
$begingroup$
What does $A_0$ ` is not equivalently at infinity` mean?
$endgroup$
– sds
Jan 2 at 21:17
$begingroup$
If we define $A_0$ arbitrarily far away then we can make $c(A_0)$ as close to zero as possible, since the range of the lengths of the distances from $A_0$ to the vertices of the polygon would increase as $A_0$ tends to infinity. This is not what we want, so I have excluded it in the definition.
$endgroup$
– pacosta
Jan 5 at 0:21
$begingroup$
What does $A_0$ ` is not equivalently at infinity` mean?
$endgroup$
– sds
Jan 2 at 21:17
$begingroup$
What does $A_0$ ` is not equivalently at infinity` mean?
$endgroup$
– sds
Jan 2 at 21:17
$begingroup$
If we define $A_0$ arbitrarily far away then we can make $c(A_0)$ as close to zero as possible, since the range of the lengths of the distances from $A_0$ to the vertices of the polygon would increase as $A_0$ tends to infinity. This is not what we want, so I have excluded it in the definition.
$endgroup$
– pacosta
Jan 5 at 0:21
$begingroup$
If we define $A_0$ arbitrarily far away then we can make $c(A_0)$ as close to zero as possible, since the range of the lengths of the distances from $A_0$ to the vertices of the polygon would increase as $A_0$ tends to infinity. This is not what we want, so I have excluded it in the definition.
$endgroup$
– pacosta
Jan 5 at 0:21
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Assuming by "range" you mean the maximum distance from $A_0$ to the vertices of the polygon, your "generalized circumcenter" is actually the center of the minimum covering circle
It is indeed unique: if there were two such points and circles with the same radius all the points then they would overlap and the a circle centered on that overlap would have a strictly smaller radius
It is not really a circumcenter. For example with an obtuse-angled triangle, the minimum covering circle is smaller than the circumcircle, the center of the minimum covering circle is the midpoint of the longest edge, and the minimum covering circle only passes through two of the vertices
$endgroup$
add a comment |
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3059975%2fgeneralized-circumcenter-minimizing-the-range-of-distances-from-a-point-to-the%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Assuming by "range" you mean the maximum distance from $A_0$ to the vertices of the polygon, your "generalized circumcenter" is actually the center of the minimum covering circle
It is indeed unique: if there were two such points and circles with the same radius all the points then they would overlap and the a circle centered on that overlap would have a strictly smaller radius
It is not really a circumcenter. For example with an obtuse-angled triangle, the minimum covering circle is smaller than the circumcircle, the center of the minimum covering circle is the midpoint of the longest edge, and the minimum covering circle only passes through two of the vertices
$endgroup$
add a comment |
$begingroup$
Assuming by "range" you mean the maximum distance from $A_0$ to the vertices of the polygon, your "generalized circumcenter" is actually the center of the minimum covering circle
It is indeed unique: if there were two such points and circles with the same radius all the points then they would overlap and the a circle centered on that overlap would have a strictly smaller radius
It is not really a circumcenter. For example with an obtuse-angled triangle, the minimum covering circle is smaller than the circumcircle, the center of the minimum covering circle is the midpoint of the longest edge, and the minimum covering circle only passes through two of the vertices
$endgroup$
add a comment |
$begingroup$
Assuming by "range" you mean the maximum distance from $A_0$ to the vertices of the polygon, your "generalized circumcenter" is actually the center of the minimum covering circle
It is indeed unique: if there were two such points and circles with the same radius all the points then they would overlap and the a circle centered on that overlap would have a strictly smaller radius
It is not really a circumcenter. For example with an obtuse-angled triangle, the minimum covering circle is smaller than the circumcircle, the center of the minimum covering circle is the midpoint of the longest edge, and the minimum covering circle only passes through two of the vertices
$endgroup$
Assuming by "range" you mean the maximum distance from $A_0$ to the vertices of the polygon, your "generalized circumcenter" is actually the center of the minimum covering circle
It is indeed unique: if there were two such points and circles with the same radius all the points then they would overlap and the a circle centered on that overlap would have a strictly smaller radius
It is not really a circumcenter. For example with an obtuse-angled triangle, the minimum covering circle is smaller than the circumcircle, the center of the minimum covering circle is the midpoint of the longest edge, and the minimum covering circle only passes through two of the vertices
answered Jan 2 at 22:51
HenryHenry
101k482169
101k482169
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3059975%2fgeneralized-circumcenter-minimizing-the-range-of-distances-from-a-point-to-the%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown

$begingroup$
What does $A_0$ ` is not equivalently at infinity` mean?
$endgroup$
– sds
Jan 2 at 21:17
$begingroup$
If we define $A_0$ arbitrarily far away then we can make $c(A_0)$ as close to zero as possible, since the range of the lengths of the distances from $A_0$ to the vertices of the polygon would increase as $A_0$ tends to infinity. This is not what we want, so I have excluded it in the definition.
$endgroup$
– pacosta
Jan 5 at 0:21