Macro expansion inside href
I want to make a shortcut for
href{tel:0123456789}{01,23,45,67,89}
I can use StrSubstitute
from the xstring
package as
StrSubstitute{01 23 45 67 89}{ }{,}
inside the second argument to href
. But the same thing with
StrSubstitute{01 23 45 67 89}{ }{}
in the first argument won't work.
I think, I understand that this is an issue with macro expansion order. But how can I get LaTeX to first expand StrSubstitute
into a string that can be parsed by href
?
Here is a minimal example of what I actually want to achieve:
documentclass{minimal}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{href{tel:StrSubstitute{#1}{ }{}}{StrSubstitute{#1}{ }{,}}}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
href{StrSubstitute{01 23 45 67 89}{ }{}}{StrSubstitute{01 23 45 67 89}{ }{,}}
phone{01 23 45 67 89}
end{document}
Edit: The pairwise pattern is not important, since different countries have different number format conventions. I really only want to replace/remove spaces (and maybe other things).
hyperref xstring href
add a comment |
I want to make a shortcut for
href{tel:0123456789}{01,23,45,67,89}
I can use StrSubstitute
from the xstring
package as
StrSubstitute{01 23 45 67 89}{ }{,}
inside the second argument to href
. But the same thing with
StrSubstitute{01 23 45 67 89}{ }{}
in the first argument won't work.
I think, I understand that this is an issue with macro expansion order. But how can I get LaTeX to first expand StrSubstitute
into a string that can be parsed by href
?
Here is a minimal example of what I actually want to achieve:
documentclass{minimal}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{href{tel:StrSubstitute{#1}{ }{}}{StrSubstitute{#1}{ }{,}}}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
href{StrSubstitute{01 23 45 67 89}{ }{}}{StrSubstitute{01 23 45 67 89}{ }{,}}
phone{01 23 45 67 89}
end{document}
Edit: The pairwise pattern is not important, since different countries have different number format conventions. I really only want to replace/remove spaces (and maybe other things).
hyperref xstring href
add a comment |
I want to make a shortcut for
href{tel:0123456789}{01,23,45,67,89}
I can use StrSubstitute
from the xstring
package as
StrSubstitute{01 23 45 67 89}{ }{,}
inside the second argument to href
. But the same thing with
StrSubstitute{01 23 45 67 89}{ }{}
in the first argument won't work.
I think, I understand that this is an issue with macro expansion order. But how can I get LaTeX to first expand StrSubstitute
into a string that can be parsed by href
?
Here is a minimal example of what I actually want to achieve:
documentclass{minimal}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{href{tel:StrSubstitute{#1}{ }{}}{StrSubstitute{#1}{ }{,}}}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
href{StrSubstitute{01 23 45 67 89}{ }{}}{StrSubstitute{01 23 45 67 89}{ }{,}}
phone{01 23 45 67 89}
end{document}
Edit: The pairwise pattern is not important, since different countries have different number format conventions. I really only want to replace/remove spaces (and maybe other things).
hyperref xstring href
I want to make a shortcut for
href{tel:0123456789}{01,23,45,67,89}
I can use StrSubstitute
from the xstring
package as
StrSubstitute{01 23 45 67 89}{ }{,}
inside the second argument to href
. But the same thing with
StrSubstitute{01 23 45 67 89}{ }{}
in the first argument won't work.
I think, I understand that this is an issue with macro expansion order. But how can I get LaTeX to first expand StrSubstitute
into a string that can be parsed by href
?
Here is a minimal example of what I actually want to achieve:
documentclass{minimal}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{href{tel:StrSubstitute{#1}{ }{}}{StrSubstitute{#1}{ }{,}}}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
href{StrSubstitute{01 23 45 67 89}{ }{}}{StrSubstitute{01 23 45 67 89}{ }{,}}
phone{01 23 45 67 89}
end{document}
Edit: The pairwise pattern is not important, since different countries have different number format conventions. I really only want to replace/remove spaces (and maybe other things).
hyperref xstring href
hyperref xstring href
edited Feb 27 at 6:24
DLichti
asked Feb 26 at 21:41
DLichtiDLichti
1176
1176
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Expand the string substitution first by storing it in an argument, which you can then use with hyperref
's href
:
documentclass{article}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{%
StrSubstitute{#1}{ }{}[firstarg]% Store first substitution in firstarg
StrSubstitute{#1}{ }{,}[secondarg]% Store second substitution in secondarg
href{tel:firstarg}{secondarg}% Use stored arguments in href
}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
add a comment |
You can't use StrSubstitute
in those places, because it doesn't produce the string after the substitution, but rather a fairly complicated set of instructions to produce that string.
A more complicated solution that avoids the need to input spaces between pairs of digits, so it will work even if you forget them.
documentclass{article}
usepackage{xparse}
usepackage{hyperref}
ExplSyntaxOn
NewDocumentCommand{phone}{m}
{
dlichti_phone:n { #1 }
}
tl_new:N l_dlichti_phone_href_tl
tl_new:N l_dlichti_phone_print_tl
cs_new_protected:Nn dlichti_phone:n
{
tl_set:Nx l_dlichti_phone_href_tl { #1 }
% remove all spaces
tl_replace_all:Nnn l_dlichti_phone_href_tl { ~ } { }
% save a copy
tl_set_eq:NN l_dlichti_phone_print_tl l_dlichti_phone_href_tl
% insert a thin space between any pair of digits
regex_replace_all:nnN
{ ([0-9][0-9]) } % two digits followed by another digit
{ 1c{,} } % the same with , in between
l_dlichti_phone_print_tl
% remove the trailing ,
regex_replace_once:nnN { c{,} Z } { } l_dlichti_phone_print_tl
dlichti_phone_href:VVV
c_colon_str
l_dlichti_phone_href_tl
l_dlichti_phone_print_tl
}
cs_new_protected:Nn dlichti_phone_href:nnn
{
href{tel#1#2}{#3}
}
cs_generate_variant:Nn dlichti_phone_href:nnn { VVV }
ExplSyntaxOff
begin{document}
phone{01 23 45 67 89}
phone{0123456789}
end{document}
add a comment |
The xstring
commands are not expandable so can't in general be used inline in other commands. You can use a simple expandable replacement here.
documentclass{minimal}
usepackage{hyperref}
makeatletter
defzza#1 {#1zza}
defzzb#1 {#1,zzb}
newcommandphone[1]{{def!##1{}def$##1##2{}href{tel:zza#1! }{zzb#1$ }}}
makeatother
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Expand the string substitution first by storing it in an argument, which you can then use with hyperref
's href
:
documentclass{article}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{%
StrSubstitute{#1}{ }{}[firstarg]% Store first substitution in firstarg
StrSubstitute{#1}{ }{,}[secondarg]% Store second substitution in secondarg
href{tel:firstarg}{secondarg}% Use stored arguments in href
}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
add a comment |
Expand the string substitution first by storing it in an argument, which you can then use with hyperref
's href
:
documentclass{article}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{%
StrSubstitute{#1}{ }{}[firstarg]% Store first substitution in firstarg
StrSubstitute{#1}{ }{,}[secondarg]% Store second substitution in secondarg
href{tel:firstarg}{secondarg}% Use stored arguments in href
}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
add a comment |
Expand the string substitution first by storing it in an argument, which you can then use with hyperref
's href
:
documentclass{article}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{%
StrSubstitute{#1}{ }{}[firstarg]% Store first substitution in firstarg
StrSubstitute{#1}{ }{,}[secondarg]% Store second substitution in secondarg
href{tel:firstarg}{secondarg}% Use stored arguments in href
}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
Expand the string substitution first by storing it in an argument, which you can then use with hyperref
's href
:
documentclass{article}
usepackage{xstring}
usepackage{hyperref}
newcommandphone[1]{%
StrSubstitute{#1}{ }{}[firstarg]% Store first substitution in firstarg
StrSubstitute{#1}{ }{,}[secondarg]% Store second substitution in secondarg
href{tel:firstarg}{secondarg}% Use stored arguments in href
}
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
answered Feb 26 at 22:28
WernerWerner
449k729961703
449k729961703
add a comment |
add a comment |
You can't use StrSubstitute
in those places, because it doesn't produce the string after the substitution, but rather a fairly complicated set of instructions to produce that string.
A more complicated solution that avoids the need to input spaces between pairs of digits, so it will work even if you forget them.
documentclass{article}
usepackage{xparse}
usepackage{hyperref}
ExplSyntaxOn
NewDocumentCommand{phone}{m}
{
dlichti_phone:n { #1 }
}
tl_new:N l_dlichti_phone_href_tl
tl_new:N l_dlichti_phone_print_tl
cs_new_protected:Nn dlichti_phone:n
{
tl_set:Nx l_dlichti_phone_href_tl { #1 }
% remove all spaces
tl_replace_all:Nnn l_dlichti_phone_href_tl { ~ } { }
% save a copy
tl_set_eq:NN l_dlichti_phone_print_tl l_dlichti_phone_href_tl
% insert a thin space between any pair of digits
regex_replace_all:nnN
{ ([0-9][0-9]) } % two digits followed by another digit
{ 1c{,} } % the same with , in between
l_dlichti_phone_print_tl
% remove the trailing ,
regex_replace_once:nnN { c{,} Z } { } l_dlichti_phone_print_tl
dlichti_phone_href:VVV
c_colon_str
l_dlichti_phone_href_tl
l_dlichti_phone_print_tl
}
cs_new_protected:Nn dlichti_phone_href:nnn
{
href{tel#1#2}{#3}
}
cs_generate_variant:Nn dlichti_phone_href:nnn { VVV }
ExplSyntaxOff
begin{document}
phone{01 23 45 67 89}
phone{0123456789}
end{document}
add a comment |
You can't use StrSubstitute
in those places, because it doesn't produce the string after the substitution, but rather a fairly complicated set of instructions to produce that string.
A more complicated solution that avoids the need to input spaces between pairs of digits, so it will work even if you forget them.
documentclass{article}
usepackage{xparse}
usepackage{hyperref}
ExplSyntaxOn
NewDocumentCommand{phone}{m}
{
dlichti_phone:n { #1 }
}
tl_new:N l_dlichti_phone_href_tl
tl_new:N l_dlichti_phone_print_tl
cs_new_protected:Nn dlichti_phone:n
{
tl_set:Nx l_dlichti_phone_href_tl { #1 }
% remove all spaces
tl_replace_all:Nnn l_dlichti_phone_href_tl { ~ } { }
% save a copy
tl_set_eq:NN l_dlichti_phone_print_tl l_dlichti_phone_href_tl
% insert a thin space between any pair of digits
regex_replace_all:nnN
{ ([0-9][0-9]) } % two digits followed by another digit
{ 1c{,} } % the same with , in between
l_dlichti_phone_print_tl
% remove the trailing ,
regex_replace_once:nnN { c{,} Z } { } l_dlichti_phone_print_tl
dlichti_phone_href:VVV
c_colon_str
l_dlichti_phone_href_tl
l_dlichti_phone_print_tl
}
cs_new_protected:Nn dlichti_phone_href:nnn
{
href{tel#1#2}{#3}
}
cs_generate_variant:Nn dlichti_phone_href:nnn { VVV }
ExplSyntaxOff
begin{document}
phone{01 23 45 67 89}
phone{0123456789}
end{document}
add a comment |
You can't use StrSubstitute
in those places, because it doesn't produce the string after the substitution, but rather a fairly complicated set of instructions to produce that string.
A more complicated solution that avoids the need to input spaces between pairs of digits, so it will work even if you forget them.
documentclass{article}
usepackage{xparse}
usepackage{hyperref}
ExplSyntaxOn
NewDocumentCommand{phone}{m}
{
dlichti_phone:n { #1 }
}
tl_new:N l_dlichti_phone_href_tl
tl_new:N l_dlichti_phone_print_tl
cs_new_protected:Nn dlichti_phone:n
{
tl_set:Nx l_dlichti_phone_href_tl { #1 }
% remove all spaces
tl_replace_all:Nnn l_dlichti_phone_href_tl { ~ } { }
% save a copy
tl_set_eq:NN l_dlichti_phone_print_tl l_dlichti_phone_href_tl
% insert a thin space between any pair of digits
regex_replace_all:nnN
{ ([0-9][0-9]) } % two digits followed by another digit
{ 1c{,} } % the same with , in between
l_dlichti_phone_print_tl
% remove the trailing ,
regex_replace_once:nnN { c{,} Z } { } l_dlichti_phone_print_tl
dlichti_phone_href:VVV
c_colon_str
l_dlichti_phone_href_tl
l_dlichti_phone_print_tl
}
cs_new_protected:Nn dlichti_phone_href:nnn
{
href{tel#1#2}{#3}
}
cs_generate_variant:Nn dlichti_phone_href:nnn { VVV }
ExplSyntaxOff
begin{document}
phone{01 23 45 67 89}
phone{0123456789}
end{document}
You can't use StrSubstitute
in those places, because it doesn't produce the string after the substitution, but rather a fairly complicated set of instructions to produce that string.
A more complicated solution that avoids the need to input spaces between pairs of digits, so it will work even if you forget them.
documentclass{article}
usepackage{xparse}
usepackage{hyperref}
ExplSyntaxOn
NewDocumentCommand{phone}{m}
{
dlichti_phone:n { #1 }
}
tl_new:N l_dlichti_phone_href_tl
tl_new:N l_dlichti_phone_print_tl
cs_new_protected:Nn dlichti_phone:n
{
tl_set:Nx l_dlichti_phone_href_tl { #1 }
% remove all spaces
tl_replace_all:Nnn l_dlichti_phone_href_tl { ~ } { }
% save a copy
tl_set_eq:NN l_dlichti_phone_print_tl l_dlichti_phone_href_tl
% insert a thin space between any pair of digits
regex_replace_all:nnN
{ ([0-9][0-9]) } % two digits followed by another digit
{ 1c{,} } % the same with , in between
l_dlichti_phone_print_tl
% remove the trailing ,
regex_replace_once:nnN { c{,} Z } { } l_dlichti_phone_print_tl
dlichti_phone_href:VVV
c_colon_str
l_dlichti_phone_href_tl
l_dlichti_phone_print_tl
}
cs_new_protected:Nn dlichti_phone_href:nnn
{
href{tel#1#2}{#3}
}
cs_generate_variant:Nn dlichti_phone_href:nnn { VVV }
ExplSyntaxOff
begin{document}
phone{01 23 45 67 89}
phone{0123456789}
end{document}
edited Feb 26 at 22:56
answered Feb 26 at 22:32
egregegreg
730k8819293243
730k8819293243
add a comment |
add a comment |
The xstring
commands are not expandable so can't in general be used inline in other commands. You can use a simple expandable replacement here.
documentclass{minimal}
usepackage{hyperref}
makeatletter
defzza#1 {#1zza}
defzzb#1 {#1,zzb}
newcommandphone[1]{{def!##1{}def$##1##2{}href{tel:zza#1! }{zzb#1$ }}}
makeatother
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
add a comment |
The xstring
commands are not expandable so can't in general be used inline in other commands. You can use a simple expandable replacement here.
documentclass{minimal}
usepackage{hyperref}
makeatletter
defzza#1 {#1zza}
defzzb#1 {#1,zzb}
newcommandphone[1]{{def!##1{}def$##1##2{}href{tel:zza#1! }{zzb#1$ }}}
makeatother
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
add a comment |
The xstring
commands are not expandable so can't in general be used inline in other commands. You can use a simple expandable replacement here.
documentclass{minimal}
usepackage{hyperref}
makeatletter
defzza#1 {#1zza}
defzzb#1 {#1,zzb}
newcommandphone[1]{{def!##1{}def$##1##2{}href{tel:zza#1! }{zzb#1$ }}}
makeatother
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
The xstring
commands are not expandable so can't in general be used inline in other commands. You can use a simple expandable replacement here.
documentclass{minimal}
usepackage{hyperref}
makeatletter
defzza#1 {#1zza}
defzzb#1 {#1,zzb}
newcommandphone[1]{{def!##1{}def$##1##2{}href{tel:zza#1! }{zzb#1$ }}}
makeatother
begin{document}
href{tel:0123456789}{01,23,45,67,89}
phone{01 23 45 67 89}
end{document}
edited Feb 26 at 22:31
answered Feb 26 at 22:17
David CarlisleDavid Carlisle
497k4111441890
497k4111441890
add a comment |
add a comment |
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