How to show that $g=f^{-1}$ satisfies $g'' = 3(g^2(x))/2.$ While $f'(x) = (1+x^3)^{-1/2}$. (Suppose that f is...












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I have few ideas about this question. Like deriving $f'$ again and creating an equation with its inverse derivative etc. But I am not firmly about my solutions.



(I'll figure how to use typeset as soon as possible.)










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  • $begingroup$
    Nevermind I solved it.
    $endgroup$
    – HouseBT
    Dec 8 '18 at 12:20
















0












$begingroup$


I have few ideas about this question. Like deriving $f'$ again and creating an equation with its inverse derivative etc. But I am not firmly about my solutions.



(I'll figure how to use typeset as soon as possible.)










share|cite|improve this question











$endgroup$












  • $begingroup$
    Nevermind I solved it.
    $endgroup$
    – HouseBT
    Dec 8 '18 at 12:20














0












0








0





$begingroup$


I have few ideas about this question. Like deriving $f'$ again and creating an equation with its inverse derivative etc. But I am not firmly about my solutions.



(I'll figure how to use typeset as soon as possible.)










share|cite|improve this question











$endgroup$




I have few ideas about this question. Like deriving $f'$ again and creating an equation with its inverse derivative etc. But I am not firmly about my solutions.



(I'll figure how to use typeset as soon as possible.)







calculus algebra-precalculus






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 8 '18 at 12:09







HouseBT

















asked Dec 8 '18 at 11:50









HouseBTHouseBT

154




154












  • $begingroup$
    Nevermind I solved it.
    $endgroup$
    – HouseBT
    Dec 8 '18 at 12:20


















  • $begingroup$
    Nevermind I solved it.
    $endgroup$
    – HouseBT
    Dec 8 '18 at 12:20
















$begingroup$
Nevermind I solved it.
$endgroup$
– HouseBT
Dec 8 '18 at 12:20




$begingroup$
Nevermind I solved it.
$endgroup$
– HouseBT
Dec 8 '18 at 12:20










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