On $xy$ vs $ab$ where $2xy+x+y+1 = 2ab+a+b$












0














Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.



Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.



I was wondering what we can say about the relation between $x*y$ and $a*b$.
As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.



Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?










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    0














    Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.



    Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.



    I was wondering what we can say about the relation between $x*y$ and $a*b$.
    As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.



    Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?










    share|cite|improve this question

























      0












      0








      0







      Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.



      Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.



      I was wondering what we can say about the relation between $x*y$ and $a*b$.
      As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.



      Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?










      share|cite|improve this question













      Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.



      Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.



      I was wondering what we can say about the relation between $x*y$ and $a*b$.
      As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.



      Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?







      elementary-number-theory






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      asked Nov 25 at 20:07









      Tilsight

      135




      135






















          3 Answers
          3






          active

          oldest

          votes


















          0














          apparently not



           a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
          a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
          a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
          a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
          a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
          a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
          a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
          a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
          a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
          a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
          a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
          a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
          a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
          a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
          a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
          a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
          a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
          a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
          a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10





          share|cite|improve this answer





















          • Thank you, Will.
            – Tilsight
            Nov 25 at 20:41










          • Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
            – Tilsight
            Nov 25 at 20:43





















          0














          Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,



          so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.






          share|cite|improve this answer





























            0














            Not bounded at all.



            With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
            $$ x = frac{2(a-3)(a+1)}{5} $$



            With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
            $$ x = frac{2a^2 -2a-5}{5} $$



             a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
            a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
            a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
            a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
            a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
            a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
            a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
            a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
            a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
            a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
            a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
            a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
            a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
            a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
            a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
            a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
            a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
            a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
            a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
            a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
            a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642





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            • Thanks guys. Respect 😀
              – Tilsight
              Nov 25 at 20:57











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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            0














            apparently not



             a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
            a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
            a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
            a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
            a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
            a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
            a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
            a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
            a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
            a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
            a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
            a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
            a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
            a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
            a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
            a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
            a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
            a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
            a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10





            share|cite|improve this answer





















            • Thank you, Will.
              – Tilsight
              Nov 25 at 20:41










            • Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
              – Tilsight
              Nov 25 at 20:43


















            0














            apparently not



             a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
            a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
            a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
            a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
            a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
            a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
            a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
            a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
            a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
            a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
            a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
            a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
            a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
            a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
            a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
            a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
            a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
            a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
            a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10





            share|cite|improve this answer





















            • Thank you, Will.
              – Tilsight
              Nov 25 at 20:41










            • Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
              – Tilsight
              Nov 25 at 20:43
















            0












            0








            0






            apparently not



             a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
            a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
            a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
            a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
            a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
            a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
            a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
            a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
            a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
            a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
            a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
            a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
            a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
            a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
            a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
            a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
            a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
            a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
            a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10





            share|cite|improve this answer












            apparently not



             a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
            a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
            a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
            a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
            a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
            a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
            a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
            a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
            a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
            a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
            a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
            a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
            a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
            a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
            a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
            a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
            a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
            a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
            a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10






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            share|cite|improve this answer



            share|cite|improve this answer










            answered Nov 25 at 20:24









            Will Jagy

            101k599199




            101k599199












            • Thank you, Will.
              – Tilsight
              Nov 25 at 20:41










            • Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
              – Tilsight
              Nov 25 at 20:43




















            • Thank you, Will.
              – Tilsight
              Nov 25 at 20:41










            • Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
              – Tilsight
              Nov 25 at 20:43


















            Thank you, Will.
            – Tilsight
            Nov 25 at 20:41




            Thank you, Will.
            – Tilsight
            Nov 25 at 20:41












            Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
            – Tilsight
            Nov 25 at 20:43






            Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
            – Tilsight
            Nov 25 at 20:43













            0














            Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,



            so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.






            share|cite|improve this answer


























              0














              Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,



              so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.






              share|cite|improve this answer
























                0












                0








                0






                Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,



                so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.






                share|cite|improve this answer












                Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,



                so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 25 at 20:42









                Ahmad

                2,5241625




                2,5241625























                    0














                    Not bounded at all.



                    With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
                    $$ x = frac{2(a-3)(a+1)}{5} $$



                    With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
                    $$ x = frac{2a^2 -2a-5}{5} $$



                     a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
                    a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
                    a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
                    a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
                    a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
                    a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
                    a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
                    a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
                    a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
                    a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
                    a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
                    a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
                    a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
                    a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
                    a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
                    a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
                    a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
                    a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
                    a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
                    a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
                    a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642





                    share|cite|improve this answer





















                    • Thanks guys. Respect 😀
                      – Tilsight
                      Nov 25 at 20:57
















                    0














                    Not bounded at all.



                    With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
                    $$ x = frac{2(a-3)(a+1)}{5} $$



                    With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
                    $$ x = frac{2a^2 -2a-5}{5} $$



                     a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
                    a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
                    a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
                    a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
                    a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
                    a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
                    a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
                    a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
                    a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
                    a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
                    a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
                    a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
                    a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
                    a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
                    a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
                    a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
                    a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
                    a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
                    a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
                    a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
                    a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642





                    share|cite|improve this answer





















                    • Thanks guys. Respect 😀
                      – Tilsight
                      Nov 25 at 20:57














                    0












                    0








                    0






                    Not bounded at all.



                    With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
                    $$ x = frac{2(a-3)(a+1)}{5} $$



                    With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
                    $$ x = frac{2a^2 -2a-5}{5} $$



                     a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
                    a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
                    a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
                    a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
                    a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
                    a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
                    a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
                    a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
                    a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
                    a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
                    a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
                    a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
                    a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
                    a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
                    a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
                    a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
                    a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
                    a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
                    a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
                    a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
                    a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642





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                    Not bounded at all.



                    With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
                    $$ x = frac{2(a-3)(a+1)}{5} $$



                    With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
                    $$ x = frac{2a^2 -2a-5}{5} $$



                     a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
                    a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
                    a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
                    a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
                    a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
                    a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
                    a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
                    a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
                    a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
                    a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
                    a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
                    a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
                    a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
                    a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
                    a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
                    a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
                    a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
                    a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
                    a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
                    a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
                    a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642






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                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Nov 25 at 20:44









                    Will Jagy

                    101k599199




                    101k599199












                    • Thanks guys. Respect 😀
                      – Tilsight
                      Nov 25 at 20:57


















                    • Thanks guys. Respect 😀
                      – Tilsight
                      Nov 25 at 20:57
















                    Thanks guys. Respect 😀
                    – Tilsight
                    Nov 25 at 20:57




                    Thanks guys. Respect 😀
                    – Tilsight
                    Nov 25 at 20:57


















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