Why do we need the expected value for calculating the variance in this task?











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I have a rectangle by sides $X$, $Y$ , $Z$. Where they also is independet stochastic variable with $E(X) =E(Y) =E(Z) =1cm$. $Var(X) = 0.5$ , $Var(Y) = Var(Z) = 0.75$. What is the variance for the box's volume?





I just don't get it. Why do we need $E(.)$ at all? When $Var(.)$ is already calculated? Why not just multiply all the $Var(.)$'s?










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    Because variance doesn't multiply: stats.stackexchange.com/a/52699
    – K B Dave
    Nov 16 at 13:31















up vote
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I have a rectangle by sides $X$, $Y$ , $Z$. Where they also is independet stochastic variable with $E(X) =E(Y) =E(Z) =1cm$. $Var(X) = 0.5$ , $Var(Y) = Var(Z) = 0.75$. What is the variance for the box's volume?





I just don't get it. Why do we need $E(.)$ at all? When $Var(.)$ is already calculated? Why not just multiply all the $Var(.)$'s?










share|cite|improve this question


















  • 1




    Because variance doesn't multiply: stats.stackexchange.com/a/52699
    – K B Dave
    Nov 16 at 13:31













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a rectangle by sides $X$, $Y$ , $Z$. Where they also is independet stochastic variable with $E(X) =E(Y) =E(Z) =1cm$. $Var(X) = 0.5$ , $Var(Y) = Var(Z) = 0.75$. What is the variance for the box's volume?





I just don't get it. Why do we need $E(.)$ at all? When $Var(.)$ is already calculated? Why not just multiply all the $Var(.)$'s?










share|cite|improve this question













I have a rectangle by sides $X$, $Y$ , $Z$. Where they also is independet stochastic variable with $E(X) =E(Y) =E(Z) =1cm$. $Var(X) = 0.5$ , $Var(Y) = Var(Z) = 0.75$. What is the variance for the box's volume?





I just don't get it. Why do we need $E(.)$ at all? When $Var(.)$ is already calculated? Why not just multiply all the $Var(.)$'s?







probability






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asked Nov 16 at 13:26









soetirl13

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114








  • 1




    Because variance doesn't multiply: stats.stackexchange.com/a/52699
    – K B Dave
    Nov 16 at 13:31














  • 1




    Because variance doesn't multiply: stats.stackexchange.com/a/52699
    – K B Dave
    Nov 16 at 13:31








1




1




Because variance doesn't multiply: stats.stackexchange.com/a/52699
– K B Dave
Nov 16 at 13:31




Because variance doesn't multiply: stats.stackexchange.com/a/52699
– K B Dave
Nov 16 at 13:31















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