Trigonometric system of 3 equations with many solutions in radical form.
$begingroup$
Here is another (Ramanujan's type) trigonometric system of three equations.
Question:
"
If
$(sin{x}sin{y})^{1/4}+(cos{x} cos{y})^{1/4}=sqrt{1+sqrt{2}(sin{2x} sin {2y})^{1/4}} tag1$
$(sin{y}sin{z})^{1/4}+(cos{y} cos{z})^{1/4}=sqrt{1+sqrt{2}(sin{2y} sin {2z})^{1/4}} tag2$
then
$(sin{x} cos{z})^{1/4}+(cos{x} sin{z})^{1/4}=(8sin{2y})^{1/12}tag3$
One solution is:
$sin{2y}=sqrt{5}-2;$
$sin{2x}=(sqrt{5}-2)^3 (4+sqrt{15})^2;$
$sin{2z}=(sqrt{5}-2)^3 (4-sqrt{15})^2.$
systems-of-equations radicals
$endgroup$
|
show 2 more comments
$begingroup$
Here is another (Ramanujan's type) trigonometric system of three equations.
Question:
"
If
$(sin{x}sin{y})^{1/4}+(cos{x} cos{y})^{1/4}=sqrt{1+sqrt{2}(sin{2x} sin {2y})^{1/4}} tag1$
$(sin{y}sin{z})^{1/4}+(cos{y} cos{z})^{1/4}=sqrt{1+sqrt{2}(sin{2y} sin {2z})^{1/4}} tag2$
then
$(sin{x} cos{z})^{1/4}+(cos{x} sin{z})^{1/4}=(8sin{2y})^{1/12}tag3$
One solution is:
$sin{2y}=sqrt{5}-2;$
$sin{2x}=(sqrt{5}-2)^3 (4+sqrt{15})^2;$
$sin{2z}=(sqrt{5}-2)^3 (4-sqrt{15})^2.$
systems-of-equations radicals
$endgroup$
1
$begingroup$
What is the question ?
$endgroup$
– Claude Leibovici
Sep 22 '18 at 9:11
$begingroup$
To find almost another solution.
$endgroup$
– giuseppe mancò
Sep 22 '18 at 9:15
1
$begingroup$
An answer to MSE question 310026 "On Ramanujan's Question 359" by proposer is very related.
$endgroup$
– Somos
Sep 22 '18 at 11:18
1
$begingroup$
The last sentence of your answer to MSE question 310026 is "I calculated several solutions for $n=1,1/2,2,3,1/3,4,1/4,5,1/5,6,1/6,7,1/7,8,1/8,9,1/9,10,1/10,15,1/15$." Why don't you tell us more about these solutions?
$endgroup$
– Somos
Sep 22 '18 at 15:53
$begingroup$
From equation $(3)$ it appears that $sin x, sin y, sin z$ are elliptic moduli of first third and ninth degree. But equations $(1),(2)$ don't seem to be related to third degree modular equation. Are you sure there is no typo?
$endgroup$
– Paramanand Singh
Nov 5 '18 at 10:07
|
show 2 more comments
$begingroup$
Here is another (Ramanujan's type) trigonometric system of three equations.
Question:
"
If
$(sin{x}sin{y})^{1/4}+(cos{x} cos{y})^{1/4}=sqrt{1+sqrt{2}(sin{2x} sin {2y})^{1/4}} tag1$
$(sin{y}sin{z})^{1/4}+(cos{y} cos{z})^{1/4}=sqrt{1+sqrt{2}(sin{2y} sin {2z})^{1/4}} tag2$
then
$(sin{x} cos{z})^{1/4}+(cos{x} sin{z})^{1/4}=(8sin{2y})^{1/12}tag3$
One solution is:
$sin{2y}=sqrt{5}-2;$
$sin{2x}=(sqrt{5}-2)^3 (4+sqrt{15})^2;$
$sin{2z}=(sqrt{5}-2)^3 (4-sqrt{15})^2.$
systems-of-equations radicals
$endgroup$
Here is another (Ramanujan's type) trigonometric system of three equations.
Question:
"
If
$(sin{x}sin{y})^{1/4}+(cos{x} cos{y})^{1/4}=sqrt{1+sqrt{2}(sin{2x} sin {2y})^{1/4}} tag1$
$(sin{y}sin{z})^{1/4}+(cos{y} cos{z})^{1/4}=sqrt{1+sqrt{2}(sin{2y} sin {2z})^{1/4}} tag2$
then
$(sin{x} cos{z})^{1/4}+(cos{x} sin{z})^{1/4}=(8sin{2y})^{1/12}tag3$
One solution is:
$sin{2y}=sqrt{5}-2;$
$sin{2x}=(sqrt{5}-2)^3 (4+sqrt{15})^2;$
$sin{2z}=(sqrt{5}-2)^3 (4-sqrt{15})^2.$
systems-of-equations radicals
systems-of-equations radicals
edited Jan 9 at 10:15
giuseppe mancò
asked Sep 22 '18 at 9:05
giuseppe mancògiuseppe mancò
346210
346210
1
$begingroup$
What is the question ?
$endgroup$
– Claude Leibovici
Sep 22 '18 at 9:11
$begingroup$
To find almost another solution.
$endgroup$
– giuseppe mancò
Sep 22 '18 at 9:15
1
$begingroup$
An answer to MSE question 310026 "On Ramanujan's Question 359" by proposer is very related.
$endgroup$
– Somos
Sep 22 '18 at 11:18
1
$begingroup$
The last sentence of your answer to MSE question 310026 is "I calculated several solutions for $n=1,1/2,2,3,1/3,4,1/4,5,1/5,6,1/6,7,1/7,8,1/8,9,1/9,10,1/10,15,1/15$." Why don't you tell us more about these solutions?
$endgroup$
– Somos
Sep 22 '18 at 15:53
$begingroup$
From equation $(3)$ it appears that $sin x, sin y, sin z$ are elliptic moduli of first third and ninth degree. But equations $(1),(2)$ don't seem to be related to third degree modular equation. Are you sure there is no typo?
$endgroup$
– Paramanand Singh
Nov 5 '18 at 10:07
|
show 2 more comments
1
$begingroup$
What is the question ?
$endgroup$
– Claude Leibovici
Sep 22 '18 at 9:11
$begingroup$
To find almost another solution.
$endgroup$
– giuseppe mancò
Sep 22 '18 at 9:15
1
$begingroup$
An answer to MSE question 310026 "On Ramanujan's Question 359" by proposer is very related.
$endgroup$
– Somos
Sep 22 '18 at 11:18
1
$begingroup$
The last sentence of your answer to MSE question 310026 is "I calculated several solutions for $n=1,1/2,2,3,1/3,4,1/4,5,1/5,6,1/6,7,1/7,8,1/8,9,1/9,10,1/10,15,1/15$." Why don't you tell us more about these solutions?
$endgroup$
– Somos
Sep 22 '18 at 15:53
$begingroup$
From equation $(3)$ it appears that $sin x, sin y, sin z$ are elliptic moduli of first third and ninth degree. But equations $(1),(2)$ don't seem to be related to third degree modular equation. Are you sure there is no typo?
$endgroup$
– Paramanand Singh
Nov 5 '18 at 10:07
1
1
$begingroup$
What is the question ?
$endgroup$
– Claude Leibovici
Sep 22 '18 at 9:11
$begingroup$
What is the question ?
$endgroup$
– Claude Leibovici
Sep 22 '18 at 9:11
$begingroup$
To find almost another solution.
$endgroup$
– giuseppe mancò
Sep 22 '18 at 9:15
$begingroup$
To find almost another solution.
$endgroup$
– giuseppe mancò
Sep 22 '18 at 9:15
1
1
$begingroup$
An answer to MSE question 310026 "On Ramanujan's Question 359" by proposer is very related.
$endgroup$
– Somos
Sep 22 '18 at 11:18
$begingroup$
An answer to MSE question 310026 "On Ramanujan's Question 359" by proposer is very related.
$endgroup$
– Somos
Sep 22 '18 at 11:18
1
1
$begingroup$
The last sentence of your answer to MSE question 310026 is "I calculated several solutions for $n=1,1/2,2,3,1/3,4,1/4,5,1/5,6,1/6,7,1/7,8,1/8,9,1/9,10,1/10,15,1/15$." Why don't you tell us more about these solutions?
$endgroup$
– Somos
Sep 22 '18 at 15:53
$begingroup$
The last sentence of your answer to MSE question 310026 is "I calculated several solutions for $n=1,1/2,2,3,1/3,4,1/4,5,1/5,6,1/6,7,1/7,8,1/8,9,1/9,10,1/10,15,1/15$." Why don't you tell us more about these solutions?
$endgroup$
– Somos
Sep 22 '18 at 15:53
$begingroup$
From equation $(3)$ it appears that $sin x, sin y, sin z$ are elliptic moduli of first third and ninth degree. But equations $(1),(2)$ don't seem to be related to third degree modular equation. Are you sure there is no typo?
$endgroup$
– Paramanand Singh
Nov 5 '18 at 10:07
$begingroup$
From equation $(3)$ it appears that $sin x, sin y, sin z$ are elliptic moduli of first third and ninth degree. But equations $(1),(2)$ don't seem to be related to third degree modular equation. Are you sure there is no typo?
$endgroup$
– Paramanand Singh
Nov 5 '18 at 10:07
|
show 2 more comments
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1
$begingroup$
What is the question ?
$endgroup$
– Claude Leibovici
Sep 22 '18 at 9:11
$begingroup$
To find almost another solution.
$endgroup$
– giuseppe mancò
Sep 22 '18 at 9:15
1
$begingroup$
An answer to MSE question 310026 "On Ramanujan's Question 359" by proposer is very related.
$endgroup$
– Somos
Sep 22 '18 at 11:18
1
$begingroup$
The last sentence of your answer to MSE question 310026 is "I calculated several solutions for $n=1,1/2,2,3,1/3,4,1/4,5,1/5,6,1/6,7,1/7,8,1/8,9,1/9,10,1/10,15,1/15$." Why don't you tell us more about these solutions?
$endgroup$
– Somos
Sep 22 '18 at 15:53
$begingroup$
From equation $(3)$ it appears that $sin x, sin y, sin z$ are elliptic moduli of first third and ninth degree. But equations $(1),(2)$ don't seem to be related to third degree modular equation. Are you sure there is no typo?
$endgroup$
– Paramanand Singh
Nov 5 '18 at 10:07