Weak derivative question
$begingroup$
I am confused of this example in Evans. Why is $|Du|$ calculated in this example?
pde weak-derivatives
$endgroup$
add a comment |
$begingroup$
I am confused of this example in Evans. Why is $|Du|$ calculated in this example?
pde weak-derivatives
$endgroup$
add a comment |
$begingroup$
I am confused of this example in Evans. Why is $|Du|$ calculated in this example?
pde weak-derivatives
$endgroup$
I am confused of this example in Evans. Why is $|Du|$ calculated in this example?
pde weak-derivatives
pde weak-derivatives
edited Dec 30 '18 at 3:25
dmtri
1,7402521
1,7402521
asked Dec 30 '18 at 2:14
math_novicemath_novice
367
367
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Because you need to show that $|Du|$ is in $L^p$.
$endgroup$
$begingroup$
Not to piggyback on this question, but why is the boundary in the second integral after performing integration by parts $partial B(0,epsilon)$ and not $partial(U - B(0, epsilon))$, is this because of the compact support that the test function has?
$endgroup$
– DaveNine
Dec 30 '18 at 7:15
$begingroup$
Because $phi$ has compact support in $U$ and vanishes on the boundary of $U$.
$endgroup$
– Julián Aguirre
Dec 30 '18 at 17:09
$begingroup$
Thank you for the answer! One more question: why do we want $lvert Durvert$ in $L^1$ when we calculate the integral of the boundary therm?
$endgroup$
– math_novice
Dec 30 '18 at 23:02
$begingroup$
In $L^p$, not in $L^1$. Is the definition of $W^{1,p}$.
$endgroup$
– Julián Aguirre
Dec 31 '18 at 4:03
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3056449%2fweak-derivative-question%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Because you need to show that $|Du|$ is in $L^p$.
$endgroup$
$begingroup$
Not to piggyback on this question, but why is the boundary in the second integral after performing integration by parts $partial B(0,epsilon)$ and not $partial(U - B(0, epsilon))$, is this because of the compact support that the test function has?
$endgroup$
– DaveNine
Dec 30 '18 at 7:15
$begingroup$
Because $phi$ has compact support in $U$ and vanishes on the boundary of $U$.
$endgroup$
– Julián Aguirre
Dec 30 '18 at 17:09
$begingroup$
Thank you for the answer! One more question: why do we want $lvert Durvert$ in $L^1$ when we calculate the integral of the boundary therm?
$endgroup$
– math_novice
Dec 30 '18 at 23:02
$begingroup$
In $L^p$, not in $L^1$. Is the definition of $W^{1,p}$.
$endgroup$
– Julián Aguirre
Dec 31 '18 at 4:03
add a comment |
$begingroup$
Because you need to show that $|Du|$ is in $L^p$.
$endgroup$
$begingroup$
Not to piggyback on this question, but why is the boundary in the second integral after performing integration by parts $partial B(0,epsilon)$ and not $partial(U - B(0, epsilon))$, is this because of the compact support that the test function has?
$endgroup$
– DaveNine
Dec 30 '18 at 7:15
$begingroup$
Because $phi$ has compact support in $U$ and vanishes on the boundary of $U$.
$endgroup$
– Julián Aguirre
Dec 30 '18 at 17:09
$begingroup$
Thank you for the answer! One more question: why do we want $lvert Durvert$ in $L^1$ when we calculate the integral of the boundary therm?
$endgroup$
– math_novice
Dec 30 '18 at 23:02
$begingroup$
In $L^p$, not in $L^1$. Is the definition of $W^{1,p}$.
$endgroup$
– Julián Aguirre
Dec 31 '18 at 4:03
add a comment |
$begingroup$
Because you need to show that $|Du|$ is in $L^p$.
$endgroup$
Because you need to show that $|Du|$ is in $L^p$.
answered Dec 30 '18 at 6:18
Julián AguirreJulián Aguirre
69.4k24197
69.4k24197
$begingroup$
Not to piggyback on this question, but why is the boundary in the second integral after performing integration by parts $partial B(0,epsilon)$ and not $partial(U - B(0, epsilon))$, is this because of the compact support that the test function has?
$endgroup$
– DaveNine
Dec 30 '18 at 7:15
$begingroup$
Because $phi$ has compact support in $U$ and vanishes on the boundary of $U$.
$endgroup$
– Julián Aguirre
Dec 30 '18 at 17:09
$begingroup$
Thank you for the answer! One more question: why do we want $lvert Durvert$ in $L^1$ when we calculate the integral of the boundary therm?
$endgroup$
– math_novice
Dec 30 '18 at 23:02
$begingroup$
In $L^p$, not in $L^1$. Is the definition of $W^{1,p}$.
$endgroup$
– Julián Aguirre
Dec 31 '18 at 4:03
add a comment |
$begingroup$
Not to piggyback on this question, but why is the boundary in the second integral after performing integration by parts $partial B(0,epsilon)$ and not $partial(U - B(0, epsilon))$, is this because of the compact support that the test function has?
$endgroup$
– DaveNine
Dec 30 '18 at 7:15
$begingroup$
Because $phi$ has compact support in $U$ and vanishes on the boundary of $U$.
$endgroup$
– Julián Aguirre
Dec 30 '18 at 17:09
$begingroup$
Thank you for the answer! One more question: why do we want $lvert Durvert$ in $L^1$ when we calculate the integral of the boundary therm?
$endgroup$
– math_novice
Dec 30 '18 at 23:02
$begingroup$
In $L^p$, not in $L^1$. Is the definition of $W^{1,p}$.
$endgroup$
– Julián Aguirre
Dec 31 '18 at 4:03
$begingroup$
Not to piggyback on this question, but why is the boundary in the second integral after performing integration by parts $partial B(0,epsilon)$ and not $partial(U - B(0, epsilon))$, is this because of the compact support that the test function has?
$endgroup$
– DaveNine
Dec 30 '18 at 7:15
$begingroup$
Not to piggyback on this question, but why is the boundary in the second integral after performing integration by parts $partial B(0,epsilon)$ and not $partial(U - B(0, epsilon))$, is this because of the compact support that the test function has?
$endgroup$
– DaveNine
Dec 30 '18 at 7:15
$begingroup$
Because $phi$ has compact support in $U$ and vanishes on the boundary of $U$.
$endgroup$
– Julián Aguirre
Dec 30 '18 at 17:09
$begingroup$
Because $phi$ has compact support in $U$ and vanishes on the boundary of $U$.
$endgroup$
– Julián Aguirre
Dec 30 '18 at 17:09
$begingroup$
Thank you for the answer! One more question: why do we want $lvert Durvert$ in $L^1$ when we calculate the integral of the boundary therm?
$endgroup$
– math_novice
Dec 30 '18 at 23:02
$begingroup$
Thank you for the answer! One more question: why do we want $lvert Durvert$ in $L^1$ when we calculate the integral of the boundary therm?
$endgroup$
– math_novice
Dec 30 '18 at 23:02
$begingroup$
In $L^p$, not in $L^1$. Is the definition of $W^{1,p}$.
$endgroup$
– Julián Aguirre
Dec 31 '18 at 4:03
$begingroup$
In $L^p$, not in $L^1$. Is the definition of $W^{1,p}$.
$endgroup$
– Julián Aguirre
Dec 31 '18 at 4:03
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3056449%2fweak-derivative-question%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown