Using excel sheet as a function
I wonder how I can use an excel sheet as a function.
Let's say I have a complex calculation in Sheet1 with one parameter I would like to iterate over a range like [1 to 400] in a second sheet to create an x, f(x) table in Sheet2.
I'll be using Excel or Open Office.
How would I go about doing this?
Thanks.
Progress update
Attempted to do a test in the Sheet (General):
Public Function test() as Boolean
test = True
End Function
Then in a cell:
=test()
Resulting in #Name?
Also tried scouering online tutorials.
Partially solved:
- Visibility of the function is achieved by putting the code in a module.
- Insert -> module in VBA.
Progress:
Setting av value using
Worksheets("Sheet1").Range("A1").Value = 10
or
Worksheets("Sheet1").Cells(1,1).Value = 10
failes silently and doesn't execute the line under.
Progress:
The techniques work fine if I dumb down the code to a parameterless subroutine and assign it to a button.
Workaround
Implementation was really straight forward when implementing using a VBA macro launched from a button rather than using a function.
I iterated over a range of rows to get the inputs to the calculations.
microsoft-excel microsoft-excel-2003
|
show 2 more comments
I wonder how I can use an excel sheet as a function.
Let's say I have a complex calculation in Sheet1 with one parameter I would like to iterate over a range like [1 to 400] in a second sheet to create an x, f(x) table in Sheet2.
I'll be using Excel or Open Office.
How would I go about doing this?
Thanks.
Progress update
Attempted to do a test in the Sheet (General):
Public Function test() as Boolean
test = True
End Function
Then in a cell:
=test()
Resulting in #Name?
Also tried scouering online tutorials.
Partially solved:
- Visibility of the function is achieved by putting the code in a module.
- Insert -> module in VBA.
Progress:
Setting av value using
Worksheets("Sheet1").Range("A1").Value = 10
or
Worksheets("Sheet1").Cells(1,1).Value = 10
failes silently and doesn't execute the line under.
Progress:
The techniques work fine if I dumb down the code to a parameterless subroutine and assign it to a button.
Workaround
Implementation was really straight forward when implementing using a VBA macro launched from a button rather than using a function.
I iterated over a range of rows to get the inputs to the calculations.
microsoft-excel microsoft-excel-2003
1
RE the test function failing - have you enabled macros for the file in question? IIRC, with them disabled, custom functions will not operate.
– DMA57361
Sep 7 '10 at 13:04
Thanks, I think maybe it was a visibility issue. Moving the code to a module solved it. Now on to the hard part :)
– tovare
Sep 7 '10 at 13:06
1
Both those examples in your last update work for me (Excel 2003, what version are you using?). You can also useSheets("Sheet1")
and.Formula = 10
- both effectively the same when setting values (but Formula is quite different when retrieving). I doubt this will help though...
– DMA57361
Sep 7 '10 at 14:33
I tried two installations of Excel 2003. One had some VB-buttons disabled by the corporate admin, but I got around it. The second should be pretty unconstrained by coorporate snake oil, still didn't work though. I'll try some more tomorrow :-)
– tovare
Sep 7 '10 at 19:16
1
If the sheet is protected then you can't set the value. You either have to unprotect it, or user the USERINTERFACEONLY parameter when locking it.
– Lance Roberts
Sep 7 '10 at 20:28
|
show 2 more comments
I wonder how I can use an excel sheet as a function.
Let's say I have a complex calculation in Sheet1 with one parameter I would like to iterate over a range like [1 to 400] in a second sheet to create an x, f(x) table in Sheet2.
I'll be using Excel or Open Office.
How would I go about doing this?
Thanks.
Progress update
Attempted to do a test in the Sheet (General):
Public Function test() as Boolean
test = True
End Function
Then in a cell:
=test()
Resulting in #Name?
Also tried scouering online tutorials.
Partially solved:
- Visibility of the function is achieved by putting the code in a module.
- Insert -> module in VBA.
Progress:
Setting av value using
Worksheets("Sheet1").Range("A1").Value = 10
or
Worksheets("Sheet1").Cells(1,1).Value = 10
failes silently and doesn't execute the line under.
Progress:
The techniques work fine if I dumb down the code to a parameterless subroutine and assign it to a button.
Workaround
Implementation was really straight forward when implementing using a VBA macro launched from a button rather than using a function.
I iterated over a range of rows to get the inputs to the calculations.
microsoft-excel microsoft-excel-2003
I wonder how I can use an excel sheet as a function.
Let's say I have a complex calculation in Sheet1 with one parameter I would like to iterate over a range like [1 to 400] in a second sheet to create an x, f(x) table in Sheet2.
I'll be using Excel or Open Office.
How would I go about doing this?
Thanks.
Progress update
Attempted to do a test in the Sheet (General):
Public Function test() as Boolean
test = True
End Function
Then in a cell:
=test()
Resulting in #Name?
Also tried scouering online tutorials.
Partially solved:
- Visibility of the function is achieved by putting the code in a module.
- Insert -> module in VBA.
Progress:
Setting av value using
Worksheets("Sheet1").Range("A1").Value = 10
or
Worksheets("Sheet1").Cells(1,1).Value = 10
failes silently and doesn't execute the line under.
Progress:
The techniques work fine if I dumb down the code to a parameterless subroutine and assign it to a button.
Workaround
Implementation was really straight forward when implementing using a VBA macro launched from a button rather than using a function.
I iterated over a range of rows to get the inputs to the calculations.
microsoft-excel microsoft-excel-2003
microsoft-excel microsoft-excel-2003
edited Sep 8 '10 at 10:39
tovare
asked Sep 6 '10 at 19:58
tovaretovare
5281310
5281310
1
RE the test function failing - have you enabled macros for the file in question? IIRC, with them disabled, custom functions will not operate.
– DMA57361
Sep 7 '10 at 13:04
Thanks, I think maybe it was a visibility issue. Moving the code to a module solved it. Now on to the hard part :)
– tovare
Sep 7 '10 at 13:06
1
Both those examples in your last update work for me (Excel 2003, what version are you using?). You can also useSheets("Sheet1")
and.Formula = 10
- both effectively the same when setting values (but Formula is quite different when retrieving). I doubt this will help though...
– DMA57361
Sep 7 '10 at 14:33
I tried two installations of Excel 2003. One had some VB-buttons disabled by the corporate admin, but I got around it. The second should be pretty unconstrained by coorporate snake oil, still didn't work though. I'll try some more tomorrow :-)
– tovare
Sep 7 '10 at 19:16
1
If the sheet is protected then you can't set the value. You either have to unprotect it, or user the USERINTERFACEONLY parameter when locking it.
– Lance Roberts
Sep 7 '10 at 20:28
|
show 2 more comments
1
RE the test function failing - have you enabled macros for the file in question? IIRC, with them disabled, custom functions will not operate.
– DMA57361
Sep 7 '10 at 13:04
Thanks, I think maybe it was a visibility issue. Moving the code to a module solved it. Now on to the hard part :)
– tovare
Sep 7 '10 at 13:06
1
Both those examples in your last update work for me (Excel 2003, what version are you using?). You can also useSheets("Sheet1")
and.Formula = 10
- both effectively the same when setting values (but Formula is quite different when retrieving). I doubt this will help though...
– DMA57361
Sep 7 '10 at 14:33
I tried two installations of Excel 2003. One had some VB-buttons disabled by the corporate admin, but I got around it. The second should be pretty unconstrained by coorporate snake oil, still didn't work though. I'll try some more tomorrow :-)
– tovare
Sep 7 '10 at 19:16
1
If the sheet is protected then you can't set the value. You either have to unprotect it, or user the USERINTERFACEONLY parameter when locking it.
– Lance Roberts
Sep 7 '10 at 20:28
1
1
RE the test function failing - have you enabled macros for the file in question? IIRC, with them disabled, custom functions will not operate.
– DMA57361
Sep 7 '10 at 13:04
RE the test function failing - have you enabled macros for the file in question? IIRC, with them disabled, custom functions will not operate.
– DMA57361
Sep 7 '10 at 13:04
Thanks, I think maybe it was a visibility issue. Moving the code to a module solved it. Now on to the hard part :)
– tovare
Sep 7 '10 at 13:06
Thanks, I think maybe it was a visibility issue. Moving the code to a module solved it. Now on to the hard part :)
– tovare
Sep 7 '10 at 13:06
1
1
Both those examples in your last update work for me (Excel 2003, what version are you using?). You can also use
Sheets("Sheet1")
and .Formula = 10
- both effectively the same when setting values (but Formula is quite different when retrieving). I doubt this will help though...– DMA57361
Sep 7 '10 at 14:33
Both those examples in your last update work for me (Excel 2003, what version are you using?). You can also use
Sheets("Sheet1")
and .Formula = 10
- both effectively the same when setting values (but Formula is quite different when retrieving). I doubt this will help though...– DMA57361
Sep 7 '10 at 14:33
I tried two installations of Excel 2003. One had some VB-buttons disabled by the corporate admin, but I got around it. The second should be pretty unconstrained by coorporate snake oil, still didn't work though. I'll try some more tomorrow :-)
– tovare
Sep 7 '10 at 19:16
I tried two installations of Excel 2003. One had some VB-buttons disabled by the corporate admin, but I got around it. The second should be pretty unconstrained by coorporate snake oil, still didn't work though. I'll try some more tomorrow :-)
– tovare
Sep 7 '10 at 19:16
1
1
If the sheet is protected then you can't set the value. You either have to unprotect it, or user the USERINTERFACEONLY parameter when locking it.
– Lance Roberts
Sep 7 '10 at 20:28
If the sheet is protected then you can't set the value. You either have to unprotect it, or user the USERINTERFACEONLY parameter when locking it.
– Lance Roberts
Sep 7 '10 at 20:28
|
show 2 more comments
3 Answers
3
active
oldest
votes
The best way is to create the algorithm in Excel VBA. You can open up VBA and type this
Public Function Test1(x as Integer, y as Integer)
Test1 = x*y
End Function
You can call this function like any other function from the formula bar
In formula bar for A1
=Test1(2,4)
with a result of 8.
Change the algorithm in VBA to get the results you are looking for.
I'll try that, I just assumed it wouldn't work due to the amount of calculations that would need to be re-calculated in the first sheet every time.
– tovare
Sep 6 '10 at 20:22
add a comment |
I was looking for an answer to a similar question and found something like that:
public function GetWhatever(byval p1 as variant, byval p2 as variant) as variant
'Make sure you're in AutoCalculation mode, otherwise use me.calculate
me.range("A1").value = p1
me.range("A2").value = p2
GetWhatever = me.range("A3").value
end function
SO question: https://stackoverflow.com/a/3570907
add a comment |
One thing what I prefer is to create a DATA TABLE by varying the parameter and then LOOKUP for required value in the created data table.
A more proper way will be to write a code in Excel VBA and it can be called very easily, without much effort. However, if you already have the Excel sheet in your hand, you can easily go with former one by creating a DATA TABLE.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The best way is to create the algorithm in Excel VBA. You can open up VBA and type this
Public Function Test1(x as Integer, y as Integer)
Test1 = x*y
End Function
You can call this function like any other function from the formula bar
In formula bar for A1
=Test1(2,4)
with a result of 8.
Change the algorithm in VBA to get the results you are looking for.
I'll try that, I just assumed it wouldn't work due to the amount of calculations that would need to be re-calculated in the first sheet every time.
– tovare
Sep 6 '10 at 20:22
add a comment |
The best way is to create the algorithm in Excel VBA. You can open up VBA and type this
Public Function Test1(x as Integer, y as Integer)
Test1 = x*y
End Function
You can call this function like any other function from the formula bar
In formula bar for A1
=Test1(2,4)
with a result of 8.
Change the algorithm in VBA to get the results you are looking for.
I'll try that, I just assumed it wouldn't work due to the amount of calculations that would need to be re-calculated in the first sheet every time.
– tovare
Sep 6 '10 at 20:22
add a comment |
The best way is to create the algorithm in Excel VBA. You can open up VBA and type this
Public Function Test1(x as Integer, y as Integer)
Test1 = x*y
End Function
You can call this function like any other function from the formula bar
In formula bar for A1
=Test1(2,4)
with a result of 8.
Change the algorithm in VBA to get the results you are looking for.
The best way is to create the algorithm in Excel VBA. You can open up VBA and type this
Public Function Test1(x as Integer, y as Integer)
Test1 = x*y
End Function
You can call this function like any other function from the formula bar
In formula bar for A1
=Test1(2,4)
with a result of 8.
Change the algorithm in VBA to get the results you are looking for.
edited Sep 7 '10 at 13:24
DMA57361
16.9k66195
16.9k66195
answered Sep 6 '10 at 20:12
wbeard52wbeard52
2,74622238
2,74622238
I'll try that, I just assumed it wouldn't work due to the amount of calculations that would need to be re-calculated in the first sheet every time.
– tovare
Sep 6 '10 at 20:22
add a comment |
I'll try that, I just assumed it wouldn't work due to the amount of calculations that would need to be re-calculated in the first sheet every time.
– tovare
Sep 6 '10 at 20:22
I'll try that, I just assumed it wouldn't work due to the amount of calculations that would need to be re-calculated in the first sheet every time.
– tovare
Sep 6 '10 at 20:22
I'll try that, I just assumed it wouldn't work due to the amount of calculations that would need to be re-calculated in the first sheet every time.
– tovare
Sep 6 '10 at 20:22
add a comment |
I was looking for an answer to a similar question and found something like that:
public function GetWhatever(byval p1 as variant, byval p2 as variant) as variant
'Make sure you're in AutoCalculation mode, otherwise use me.calculate
me.range("A1").value = p1
me.range("A2").value = p2
GetWhatever = me.range("A3").value
end function
SO question: https://stackoverflow.com/a/3570907
add a comment |
I was looking for an answer to a similar question and found something like that:
public function GetWhatever(byval p1 as variant, byval p2 as variant) as variant
'Make sure you're in AutoCalculation mode, otherwise use me.calculate
me.range("A1").value = p1
me.range("A2").value = p2
GetWhatever = me.range("A3").value
end function
SO question: https://stackoverflow.com/a/3570907
add a comment |
I was looking for an answer to a similar question and found something like that:
public function GetWhatever(byval p1 as variant, byval p2 as variant) as variant
'Make sure you're in AutoCalculation mode, otherwise use me.calculate
me.range("A1").value = p1
me.range("A2").value = p2
GetWhatever = me.range("A3").value
end function
SO question: https://stackoverflow.com/a/3570907
I was looking for an answer to a similar question and found something like that:
public function GetWhatever(byval p1 as variant, byval p2 as variant) as variant
'Make sure you're in AutoCalculation mode, otherwise use me.calculate
me.range("A1").value = p1
me.range("A2").value = p2
GetWhatever = me.range("A3").value
end function
SO question: https://stackoverflow.com/a/3570907
edited May 23 '17 at 12:41
Community♦
1
1
answered Feb 5 '14 at 13:33
AsTeRAsTeR
11413
11413
add a comment |
add a comment |
One thing what I prefer is to create a DATA TABLE by varying the parameter and then LOOKUP for required value in the created data table.
A more proper way will be to write a code in Excel VBA and it can be called very easily, without much effort. However, if you already have the Excel sheet in your hand, you can easily go with former one by creating a DATA TABLE.
add a comment |
One thing what I prefer is to create a DATA TABLE by varying the parameter and then LOOKUP for required value in the created data table.
A more proper way will be to write a code in Excel VBA and it can be called very easily, without much effort. However, if you already have the Excel sheet in your hand, you can easily go with former one by creating a DATA TABLE.
add a comment |
One thing what I prefer is to create a DATA TABLE by varying the parameter and then LOOKUP for required value in the created data table.
A more proper way will be to write a code in Excel VBA and it can be called very easily, without much effort. However, if you already have the Excel sheet in your hand, you can easily go with former one by creating a DATA TABLE.
One thing what I prefer is to create a DATA TABLE by varying the parameter and then LOOKUP for required value in the created data table.
A more proper way will be to write a code in Excel VBA and it can be called very easily, without much effort. However, if you already have the Excel sheet in your hand, you can easily go with former one by creating a DATA TABLE.
answered Feb 20 at 4:35
Ankit TiwariAnkit Tiwari
1
1
add a comment |
add a comment |
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1
RE the test function failing - have you enabled macros for the file in question? IIRC, with them disabled, custom functions will not operate.
– DMA57361
Sep 7 '10 at 13:04
Thanks, I think maybe it was a visibility issue. Moving the code to a module solved it. Now on to the hard part :)
– tovare
Sep 7 '10 at 13:06
1
Both those examples in your last update work for me (Excel 2003, what version are you using?). You can also use
Sheets("Sheet1")
and.Formula = 10
- both effectively the same when setting values (but Formula is quite different when retrieving). I doubt this will help though...– DMA57361
Sep 7 '10 at 14:33
I tried two installations of Excel 2003. One had some VB-buttons disabled by the corporate admin, but I got around it. The second should be pretty unconstrained by coorporate snake oil, still didn't work though. I'll try some more tomorrow :-)
– tovare
Sep 7 '10 at 19:16
1
If the sheet is protected then you can't set the value. You either have to unprotect it, or user the USERINTERFACEONLY parameter when locking it.
– Lance Roberts
Sep 7 '10 at 20:28