Upper and lower bounds - nearest 5












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I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.










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  • $begingroup$
    Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:52










  • $begingroup$
    It might sound stupid to you but if i was doing i would round it to 138.5
    $endgroup$
    – jose carlos
    Oct 26 '17 at 21:58










  • $begingroup$
    Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:59










  • $begingroup$
    How is 137 a multiple of 5 then?
    $endgroup$
    – jose carlos
    Oct 26 '17 at 22:00










  • $begingroup$
    It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 22:01


















0












$begingroup$


I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:52










  • $begingroup$
    It might sound stupid to you but if i was doing i would round it to 138.5
    $endgroup$
    – jose carlos
    Oct 26 '17 at 21:58










  • $begingroup$
    Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:59










  • $begingroup$
    How is 137 a multiple of 5 then?
    $endgroup$
    – jose carlos
    Oct 26 '17 at 22:00










  • $begingroup$
    It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 22:01
















0












0








0





$begingroup$


I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.










share|cite|improve this question











$endgroup$




I am really confused about rounding number to the nearest 5, i was practicing bounds gcse questions and I had a question saying that 135 was rounded to nearest 5m, find the upper and lower bounds. I thought it was going to be 136.5 until my friend told me it was 137.5, I got really confused. Can someone explain how this works? Is there a way a value that nearest 5 is x or something like that? An clear explanation would be helpful.







elementary-number-theory upper-lower-bounds






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edited Oct 27 '17 at 1:07









Charles

24k452116




24k452116










asked Oct 26 '17 at 21:52









jose carlosjose carlos

611




611












  • $begingroup$
    Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:52










  • $begingroup$
    It might sound stupid to you but if i was doing i would round it to 138.5
    $endgroup$
    – jose carlos
    Oct 26 '17 at 21:58










  • $begingroup$
    Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:59










  • $begingroup$
    How is 137 a multiple of 5 then?
    $endgroup$
    – jose carlos
    Oct 26 '17 at 22:00










  • $begingroup$
    It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 22:01




















  • $begingroup$
    Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:52










  • $begingroup$
    It might sound stupid to you but if i was doing i would round it to 138.5
    $endgroup$
    – jose carlos
    Oct 26 '17 at 21:58










  • $begingroup$
    Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 21:59










  • $begingroup$
    How is 137 a multiple of 5 then?
    $endgroup$
    – jose carlos
    Oct 26 '17 at 22:00










  • $begingroup$
    It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
    $endgroup$
    – T. Bongers
    Oct 26 '17 at 22:01


















$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52




$begingroup$
Where would you like $137.0$ to round to, if you're aiming for the nearest multiple of $5$?
$endgroup$
– T. Bongers
Oct 26 '17 at 21:52












$begingroup$
It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58




$begingroup$
It might sound stupid to you but if i was doing i would round it to 138.5
$endgroup$
– jose carlos
Oct 26 '17 at 21:58












$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59




$begingroup$
Is $138.5$ a multiple of $5$? (It's not: Multiples of 5 look like 0, 5, 10, 15, ...)
$endgroup$
– T. Bongers
Oct 26 '17 at 21:59












$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00




$begingroup$
How is 137 a multiple of 5 then?
$endgroup$
– jose carlos
Oct 26 '17 at 22:00












$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01






$begingroup$
It's not, which is why you need to round it, either to 135 or 140. 135 is closer. The point of this is that 136.5 is not a cutoff for the things that round to 135.
$endgroup$
– T. Bongers
Oct 26 '17 at 22:01












2 Answers
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$begingroup$

The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.






share|cite|improve this answer









$endgroup$





















    0












    $begingroup$

    One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
    Eg. 135 rounded to the nearest 5
    Half 5 to get 2.5
    The upper bound is 135 + 2.5=137.5
    The lower bound is 135-2.5=132.5






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax.
      $endgroup$
      – dantopa
      Mar 12 at 16:50










    • $begingroup$
      A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
      $endgroup$
      – davidlowryduda
      Mar 14 at 20:24











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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

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    0












    $begingroup$

    The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.






        share|cite|improve this answer









        $endgroup$



        The cutoff is half way between two neighboring numbers you can round to. When rounding to the nearest $5$ you could round to $135$ or to $140$. The point half way between is $frac 12(135+140)=137.5$ Any number less than $137.5$ (and greater than $132.5$) should be rounded to $135$. This is general. The interval between cutoff points is the size of your increment of rounding, half above a target and half below.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jun 10 '18 at 13:57









        Ross MillikanRoss Millikan

        300k24200374




        300k24200374























            0












            $begingroup$

            One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
            Eg. 135 rounded to the nearest 5
            Half 5 to get 2.5
            The upper bound is 135 + 2.5=137.5
            The lower bound is 135-2.5=132.5






            share|cite|improve this answer









            $endgroup$













            • $begingroup$
              Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax.
              $endgroup$
              – dantopa
              Mar 12 at 16:50










            • $begingroup$
              A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
              $endgroup$
              – davidlowryduda
              Mar 14 at 20:24
















            0












            $begingroup$

            One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
            Eg. 135 rounded to the nearest 5
            Half 5 to get 2.5
            The upper bound is 135 + 2.5=137.5
            The lower bound is 135-2.5=132.5






            share|cite|improve this answer









            $endgroup$













            • $begingroup$
              Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax.
              $endgroup$
              – dantopa
              Mar 12 at 16:50










            • $begingroup$
              A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
              $endgroup$
              – davidlowryduda
              Mar 14 at 20:24














            0












            0








            0





            $begingroup$

            One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
            Eg. 135 rounded to the nearest 5
            Half 5 to get 2.5
            The upper bound is 135 + 2.5=137.5
            The lower bound is 135-2.5=132.5






            share|cite|improve this answer









            $endgroup$



            One trick I learnt when doing bounds is you can half the number it's been rounded to and use that to find the upper and lower bounds.
            Eg. 135 rounded to the nearest 5
            Half 5 to get 2.5
            The upper bound is 135 + 2.5=137.5
            The lower bound is 135-2.5=132.5







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Mar 12 at 16:09









            AnnaAnna

            1




            1












            • $begingroup$
              Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax.
              $endgroup$
              – dantopa
              Mar 12 at 16:50










            • $begingroup$
              A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
              $endgroup$
              – davidlowryduda
              Mar 14 at 20:24


















            • $begingroup$
              Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax.
              $endgroup$
              – dantopa
              Mar 12 at 16:50










            • $begingroup$
              A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
              $endgroup$
              – davidlowryduda
              Mar 14 at 20:24
















            $begingroup$
            Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax.
            $endgroup$
            – dantopa
            Mar 12 at 16:50




            $begingroup$
            Welcome to Mathematics Stack Exchange! A quick tour will enhance your experience. Here are helpful tips to write a good question and write a good answer. For equations, please use MathJax.
            $endgroup$
            – dantopa
            Mar 12 at 16:50












            $begingroup$
            A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
            $endgroup$
            – davidlowryduda
            Mar 14 at 20:24




            $begingroup$
            A correct answer is at the heart of this solution, but I think it's not very clear. The two (semi-automated) comments you received above this are from people reacting negatively to your answer in certain review queues. I think if you flesh out your answer, it might better address the question and attract a more positive reaction. Cheers.
            $endgroup$
            – davidlowryduda
            Mar 14 at 20:24


















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