Error in Lang's definition of weak topology?












1












$begingroup$


On page 23-24 of his Real and Functional Analysis (3e) Serge Lang claims




Let $Y$ be a topological space and let $mathscr{F}$ be a family of
mappings $f colon X to Y$ of $X$ into $Y$. Let $mathscr{B}$ be the
family of all subsets of $X$ consisting of the sets $f^{-1}(W)$ where
$W$ is open in $Y$ and $f$ ranges over $mathscr{F}$. Then we leave to
the reader the verification of the following facts:




  1. $mathscr{B}$ is a base for a topology on $X$, i.e. satisfies
    conditions B2 and B2.


  2. ...





Here B1 and B2 are given on p. 23




B1. Every element of $X$ lies in some set in $mathscr{B}$.



B2. If $B$, $B'$ are in $mathscr{B}$ and $x in B cap B'$ then there exists some $B''$ in $mathscr{B}$ such that $x in B''$ and
$B'' subset B cap B'$.




It seems to me that the $mathscr{B}$ defined in the first quote from Lang need not satisfy the property B2 in the second quote.



For example, take $X=Re^2$ , $Y=Re$, $f(x_1,x_2) = x_1$, $g(x_1,x_2)=x_2$, $mathscr{F} = {f,g}$, $I=(0,1)$, $B=f^{-1}(I)$, $B'=g^{-1}(I)$.



Then $B cap B' = I times I$ but no subset of this set can be an inverse image under either $f$ or $g$ of any subset of $Re$.



Am I right in believing that this is an error in the book?










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$endgroup$








  • 1




    $begingroup$
    The base of the weak topology consists of all finite intersections of sets like $f^{-1}(W)$, as $f$ ranges in $mathcal{F}$ and $W$ over the open subsets of $Y$. It seems to me that Lang's $mathcal{B}$ is only a sub-base.
    $endgroup$
    – Siminore
    Aug 23 '13 at 17:11






  • 1




    $begingroup$
    Right, it's a mistake. ${ f^{-1}(W) : f in mathscr{F}, W subset Y text{ open}}$ is only a subbase.
    $endgroup$
    – Daniel Fischer
    Aug 23 '13 at 17:38
















1












$begingroup$


On page 23-24 of his Real and Functional Analysis (3e) Serge Lang claims




Let $Y$ be a topological space and let $mathscr{F}$ be a family of
mappings $f colon X to Y$ of $X$ into $Y$. Let $mathscr{B}$ be the
family of all subsets of $X$ consisting of the sets $f^{-1}(W)$ where
$W$ is open in $Y$ and $f$ ranges over $mathscr{F}$. Then we leave to
the reader the verification of the following facts:




  1. $mathscr{B}$ is a base for a topology on $X$, i.e. satisfies
    conditions B2 and B2.


  2. ...





Here B1 and B2 are given on p. 23




B1. Every element of $X$ lies in some set in $mathscr{B}$.



B2. If $B$, $B'$ are in $mathscr{B}$ and $x in B cap B'$ then there exists some $B''$ in $mathscr{B}$ such that $x in B''$ and
$B'' subset B cap B'$.




It seems to me that the $mathscr{B}$ defined in the first quote from Lang need not satisfy the property B2 in the second quote.



For example, take $X=Re^2$ , $Y=Re$, $f(x_1,x_2) = x_1$, $g(x_1,x_2)=x_2$, $mathscr{F} = {f,g}$, $I=(0,1)$, $B=f^{-1}(I)$, $B'=g^{-1}(I)$.



Then $B cap B' = I times I$ but no subset of this set can be an inverse image under either $f$ or $g$ of any subset of $Re$.



Am I right in believing that this is an error in the book?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    The base of the weak topology consists of all finite intersections of sets like $f^{-1}(W)$, as $f$ ranges in $mathcal{F}$ and $W$ over the open subsets of $Y$. It seems to me that Lang's $mathcal{B}$ is only a sub-base.
    $endgroup$
    – Siminore
    Aug 23 '13 at 17:11






  • 1




    $begingroup$
    Right, it's a mistake. ${ f^{-1}(W) : f in mathscr{F}, W subset Y text{ open}}$ is only a subbase.
    $endgroup$
    – Daniel Fischer
    Aug 23 '13 at 17:38














1












1








1





$begingroup$


On page 23-24 of his Real and Functional Analysis (3e) Serge Lang claims




Let $Y$ be a topological space and let $mathscr{F}$ be a family of
mappings $f colon X to Y$ of $X$ into $Y$. Let $mathscr{B}$ be the
family of all subsets of $X$ consisting of the sets $f^{-1}(W)$ where
$W$ is open in $Y$ and $f$ ranges over $mathscr{F}$. Then we leave to
the reader the verification of the following facts:




  1. $mathscr{B}$ is a base for a topology on $X$, i.e. satisfies
    conditions B2 and B2.


  2. ...





Here B1 and B2 are given on p. 23




B1. Every element of $X$ lies in some set in $mathscr{B}$.



B2. If $B$, $B'$ are in $mathscr{B}$ and $x in B cap B'$ then there exists some $B''$ in $mathscr{B}$ such that $x in B''$ and
$B'' subset B cap B'$.




It seems to me that the $mathscr{B}$ defined in the first quote from Lang need not satisfy the property B2 in the second quote.



For example, take $X=Re^2$ , $Y=Re$, $f(x_1,x_2) = x_1$, $g(x_1,x_2)=x_2$, $mathscr{F} = {f,g}$, $I=(0,1)$, $B=f^{-1}(I)$, $B'=g^{-1}(I)$.



Then $B cap B' = I times I$ but no subset of this set can be an inverse image under either $f$ or $g$ of any subset of $Re$.



Am I right in believing that this is an error in the book?










share|cite|improve this question









$endgroup$




On page 23-24 of his Real and Functional Analysis (3e) Serge Lang claims




Let $Y$ be a topological space and let $mathscr{F}$ be a family of
mappings $f colon X to Y$ of $X$ into $Y$. Let $mathscr{B}$ be the
family of all subsets of $X$ consisting of the sets $f^{-1}(W)$ where
$W$ is open in $Y$ and $f$ ranges over $mathscr{F}$. Then we leave to
the reader the verification of the following facts:




  1. $mathscr{B}$ is a base for a topology on $X$, i.e. satisfies
    conditions B2 and B2.


  2. ...





Here B1 and B2 are given on p. 23




B1. Every element of $X$ lies in some set in $mathscr{B}$.



B2. If $B$, $B'$ are in $mathscr{B}$ and $x in B cap B'$ then there exists some $B''$ in $mathscr{B}$ such that $x in B''$ and
$B'' subset B cap B'$.




It seems to me that the $mathscr{B}$ defined in the first quote from Lang need not satisfy the property B2 in the second quote.



For example, take $X=Re^2$ , $Y=Re$, $f(x_1,x_2) = x_1$, $g(x_1,x_2)=x_2$, $mathscr{F} = {f,g}$, $I=(0,1)$, $B=f^{-1}(I)$, $B'=g^{-1}(I)$.



Then $B cap B' = I times I$ but no subset of this set can be an inverse image under either $f$ or $g$ of any subset of $Re$.



Am I right in believing that this is an error in the book?







general-topology






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asked Aug 23 '13 at 16:46









Jyotirmoy BhattacharyaJyotirmoy Bhattacharya

3,14512240




3,14512240








  • 1




    $begingroup$
    The base of the weak topology consists of all finite intersections of sets like $f^{-1}(W)$, as $f$ ranges in $mathcal{F}$ and $W$ over the open subsets of $Y$. It seems to me that Lang's $mathcal{B}$ is only a sub-base.
    $endgroup$
    – Siminore
    Aug 23 '13 at 17:11






  • 1




    $begingroup$
    Right, it's a mistake. ${ f^{-1}(W) : f in mathscr{F}, W subset Y text{ open}}$ is only a subbase.
    $endgroup$
    – Daniel Fischer
    Aug 23 '13 at 17:38














  • 1




    $begingroup$
    The base of the weak topology consists of all finite intersections of sets like $f^{-1}(W)$, as $f$ ranges in $mathcal{F}$ and $W$ over the open subsets of $Y$. It seems to me that Lang's $mathcal{B}$ is only a sub-base.
    $endgroup$
    – Siminore
    Aug 23 '13 at 17:11






  • 1




    $begingroup$
    Right, it's a mistake. ${ f^{-1}(W) : f in mathscr{F}, W subset Y text{ open}}$ is only a subbase.
    $endgroup$
    – Daniel Fischer
    Aug 23 '13 at 17:38








1




1




$begingroup$
The base of the weak topology consists of all finite intersections of sets like $f^{-1}(W)$, as $f$ ranges in $mathcal{F}$ and $W$ over the open subsets of $Y$. It seems to me that Lang's $mathcal{B}$ is only a sub-base.
$endgroup$
– Siminore
Aug 23 '13 at 17:11




$begingroup$
The base of the weak topology consists of all finite intersections of sets like $f^{-1}(W)$, as $f$ ranges in $mathcal{F}$ and $W$ over the open subsets of $Y$. It seems to me that Lang's $mathcal{B}$ is only a sub-base.
$endgroup$
– Siminore
Aug 23 '13 at 17:11




1




1




$begingroup$
Right, it's a mistake. ${ f^{-1}(W) : f in mathscr{F}, W subset Y text{ open}}$ is only a subbase.
$endgroup$
– Daniel Fischer
Aug 23 '13 at 17:38




$begingroup$
Right, it's a mistake. ${ f^{-1}(W) : f in mathscr{F}, W subset Y text{ open}}$ is only a subbase.
$endgroup$
– Daniel Fischer
Aug 23 '13 at 17:38










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This community wiki solution is intended to clear the question from the unanswered queue.



The question has been answered in comments.



You are right, it is a mistake. Lang's $mathscr{B}$ is in general only a subbase.






share|cite|improve this answer











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    $begingroup$

    This community wiki solution is intended to clear the question from the unanswered queue.



    The question has been answered in comments.



    You are right, it is a mistake. Lang's $mathscr{B}$ is in general only a subbase.






    share|cite|improve this answer











    $endgroup$


















      1












      $begingroup$

      This community wiki solution is intended to clear the question from the unanswered queue.



      The question has been answered in comments.



      You are right, it is a mistake. Lang's $mathscr{B}$ is in general only a subbase.






      share|cite|improve this answer











      $endgroup$
















        1












        1








        1





        $begingroup$

        This community wiki solution is intended to clear the question from the unanswered queue.



        The question has been answered in comments.



        You are right, it is a mistake. Lang's $mathscr{B}$ is in general only a subbase.






        share|cite|improve this answer











        $endgroup$



        This community wiki solution is intended to clear the question from the unanswered queue.



        The question has been answered in comments.



        You are right, it is a mistake. Lang's $mathscr{B}$ is in general only a subbase.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Dec 23 '18 at 16:42


























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        2 revs, 2 users 89%
        Paul Frost































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