What's the math formula that is used to calculate the monthly payment in this mortgage calculator?












7












$begingroup$


What's the math formula that is used to calculate the monthly payment in this mortgage calculator?



I would like to know this math formula so that I can plug in the following values



Mortgage Amount: $100,000  
Rate Type: Fixed
Interest Rate: 6%
Interest Term: 5 Years
Payment Frequency: Monthly
Amortization Rate: 5%


and calculate the monthly payment to $1,929.86 (as shown in the mortgage calculator).










share|cite|improve this question









$endgroup$

















    7












    $begingroup$


    What's the math formula that is used to calculate the monthly payment in this mortgage calculator?



    I would like to know this math formula so that I can plug in the following values



    Mortgage Amount: $100,000  
    Rate Type: Fixed
    Interest Rate: 6%
    Interest Term: 5 Years
    Payment Frequency: Monthly
    Amortization Rate: 5%


    and calculate the monthly payment to $1,929.86 (as shown in the mortgage calculator).










    share|cite|improve this question









    $endgroup$















      7












      7








      7


      5



      $begingroup$


      What's the math formula that is used to calculate the monthly payment in this mortgage calculator?



      I would like to know this math formula so that I can plug in the following values



      Mortgage Amount: $100,000  
      Rate Type: Fixed
      Interest Rate: 6%
      Interest Term: 5 Years
      Payment Frequency: Monthly
      Amortization Rate: 5%


      and calculate the monthly payment to $1,929.86 (as shown in the mortgage calculator).










      share|cite|improve this question









      $endgroup$




      What's the math formula that is used to calculate the monthly payment in this mortgage calculator?



      I would like to know this math formula so that I can plug in the following values



      Mortgage Amount: $100,000  
      Rate Type: Fixed
      Interest Rate: 6%
      Interest Term: 5 Years
      Payment Frequency: Monthly
      Amortization Rate: 5%


      and calculate the monthly payment to $1,929.86 (as shown in the mortgage calculator).







      finance






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      share|cite|improve this question











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      asked Feb 5 '14 at 1:18









      burnt1ceburnt1ce

      88115




      88115






















          2 Answers
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          $begingroup$

          The amortization table you cited states that “interest is compounded semi-annually for fixed interest rates.” (Note: This fact is not derived from finance theory; this is the bank's policy.) Therefore, the effective monthly interest factor is computed as $Requiv 1.03^{1/6}$, since $3$% is the semi-annual interest rate and there are six months in an interest period.



          The goal is to determine the fixed amount that needs to be paid each month in order to pay off the debt in 5 years, i.e., 60 months. Let $p$ denote this unknown number and $v_0$ the initial principal. The total debt by the end of the first month is: $$v_1=R v_0-p,$$ because the principal yields interest but $p$ is paid off. Similarly, $$v_2=Rv_1-p=R(Rv_0-p)-p=R^2 v_0-Rp-p.$$ By induction, it is not difficult to see that $$v_T=R^T v_0-psum_{t=0}^{T-1}R^t=R^T v_0-pfrac{R^T-1}{R-1}$$ after $T$ months.



          Now, if the debt is to be paid off in $T$ months, then $v_{T}=0$, so that solving for $p$ yields:
          begin{align*}
          0=R^T v_0-pfrac{R^T-1}{R-1},
          end{align*}
          or, after rearrangement: $$boxed{p=dfrac{R^T(R-1)}{R^T-1}v_0}$$
          If you plug in $T=60$, $v_0=100mathord, 000$, and $R=1.03^{1/6}$, then you get a monthly payment of $$1mathord,929mathord .86$.






          share|cite|improve this answer











          $endgroup$





















            3












            $begingroup$

            The formula is the amortization or Equated Monthly Payment formula (see also this link):



            $A = P cfrac{r (1+r)^n}{(1+r)^n - 1}$



            Without getting into the details of how it is derived, what you need to know is the following:





            • P is the principal amount borrowed


            • A is the periodic amortization payment


            • r is the periodic interest rate divided by 100 (nominal annual interest rate also divided by 12 in case of monthly installments), and


            • n is the total number of payments (for a 30-year loan with monthly payments n = 30 × 12 = 360)


            For your example,





            • P = 100,000


            • A is what we want to find


            • r = $cfrac{6}{100 cdot 12}$ = $cfrac{6}{1200}$ = 0.005, but as triple_sec pointed out, the amortization calculator you used says that "interest is compounded semi-annually for fixed interest rates and each payment period for variable interest rates," which means you use this calculation instead: r = ${0.03}^{1/6}$ = $cfrac{6}{1200} approx$ 0.049386


            • n = 5 years * 12 months/year = 60 months


            So, we get this:



            $A = 100000cdotcfrac{0.0049386cdot1.0049386^{60}}{1.0049386^{60}-1}$ = $1,929.86



            (You would get the same result if you put =PMT(1.03^(1/6)-1, 60, 100000) into a cell in Excel, because it does the same formula I quoted above.)



            Note: you say "Amortization rate" where I believe you meant "amortization term" (5 years); that matches the calculator and makes more sense in this context.






            share|cite|improve this answer











            $endgroup$













            • $begingroup$
              The excel formula PMT appears to have special case handling when r = 0 to prevent division by zero, in which case the calculations seems to be A = P / n
              $endgroup$
              – Scott Markwell
              Apr 4 '16 at 22:52











            Your Answer





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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

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            active

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            active

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            7





            +50







            $begingroup$

            The amortization table you cited states that “interest is compounded semi-annually for fixed interest rates.” (Note: This fact is not derived from finance theory; this is the bank's policy.) Therefore, the effective monthly interest factor is computed as $Requiv 1.03^{1/6}$, since $3$% is the semi-annual interest rate and there are six months in an interest period.



            The goal is to determine the fixed amount that needs to be paid each month in order to pay off the debt in 5 years, i.e., 60 months. Let $p$ denote this unknown number and $v_0$ the initial principal. The total debt by the end of the first month is: $$v_1=R v_0-p,$$ because the principal yields interest but $p$ is paid off. Similarly, $$v_2=Rv_1-p=R(Rv_0-p)-p=R^2 v_0-Rp-p.$$ By induction, it is not difficult to see that $$v_T=R^T v_0-psum_{t=0}^{T-1}R^t=R^T v_0-pfrac{R^T-1}{R-1}$$ after $T$ months.



            Now, if the debt is to be paid off in $T$ months, then $v_{T}=0$, so that solving for $p$ yields:
            begin{align*}
            0=R^T v_0-pfrac{R^T-1}{R-1},
            end{align*}
            or, after rearrangement: $$boxed{p=dfrac{R^T(R-1)}{R^T-1}v_0}$$
            If you plug in $T=60$, $v_0=100mathord, 000$, and $R=1.03^{1/6}$, then you get a monthly payment of $$1mathord,929mathord .86$.






            share|cite|improve this answer











            $endgroup$


















              7





              +50







              $begingroup$

              The amortization table you cited states that “interest is compounded semi-annually for fixed interest rates.” (Note: This fact is not derived from finance theory; this is the bank's policy.) Therefore, the effective monthly interest factor is computed as $Requiv 1.03^{1/6}$, since $3$% is the semi-annual interest rate and there are six months in an interest period.



              The goal is to determine the fixed amount that needs to be paid each month in order to pay off the debt in 5 years, i.e., 60 months. Let $p$ denote this unknown number and $v_0$ the initial principal. The total debt by the end of the first month is: $$v_1=R v_0-p,$$ because the principal yields interest but $p$ is paid off. Similarly, $$v_2=Rv_1-p=R(Rv_0-p)-p=R^2 v_0-Rp-p.$$ By induction, it is not difficult to see that $$v_T=R^T v_0-psum_{t=0}^{T-1}R^t=R^T v_0-pfrac{R^T-1}{R-1}$$ after $T$ months.



              Now, if the debt is to be paid off in $T$ months, then $v_{T}=0$, so that solving for $p$ yields:
              begin{align*}
              0=R^T v_0-pfrac{R^T-1}{R-1},
              end{align*}
              or, after rearrangement: $$boxed{p=dfrac{R^T(R-1)}{R^T-1}v_0}$$
              If you plug in $T=60$, $v_0=100mathord, 000$, and $R=1.03^{1/6}$, then you get a monthly payment of $$1mathord,929mathord .86$.






              share|cite|improve this answer











              $endgroup$
















                7





                +50







                7





                +50



                7




                +50



                $begingroup$

                The amortization table you cited states that “interest is compounded semi-annually for fixed interest rates.” (Note: This fact is not derived from finance theory; this is the bank's policy.) Therefore, the effective monthly interest factor is computed as $Requiv 1.03^{1/6}$, since $3$% is the semi-annual interest rate and there are six months in an interest period.



                The goal is to determine the fixed amount that needs to be paid each month in order to pay off the debt in 5 years, i.e., 60 months. Let $p$ denote this unknown number and $v_0$ the initial principal. The total debt by the end of the first month is: $$v_1=R v_0-p,$$ because the principal yields interest but $p$ is paid off. Similarly, $$v_2=Rv_1-p=R(Rv_0-p)-p=R^2 v_0-Rp-p.$$ By induction, it is not difficult to see that $$v_T=R^T v_0-psum_{t=0}^{T-1}R^t=R^T v_0-pfrac{R^T-1}{R-1}$$ after $T$ months.



                Now, if the debt is to be paid off in $T$ months, then $v_{T}=0$, so that solving for $p$ yields:
                begin{align*}
                0=R^T v_0-pfrac{R^T-1}{R-1},
                end{align*}
                or, after rearrangement: $$boxed{p=dfrac{R^T(R-1)}{R^T-1}v_0}$$
                If you plug in $T=60$, $v_0=100mathord, 000$, and $R=1.03^{1/6}$, then you get a monthly payment of $$1mathord,929mathord .86$.






                share|cite|improve this answer











                $endgroup$



                The amortization table you cited states that “interest is compounded semi-annually for fixed interest rates.” (Note: This fact is not derived from finance theory; this is the bank's policy.) Therefore, the effective monthly interest factor is computed as $Requiv 1.03^{1/6}$, since $3$% is the semi-annual interest rate and there are six months in an interest period.



                The goal is to determine the fixed amount that needs to be paid each month in order to pay off the debt in 5 years, i.e., 60 months. Let $p$ denote this unknown number and $v_0$ the initial principal. The total debt by the end of the first month is: $$v_1=R v_0-p,$$ because the principal yields interest but $p$ is paid off. Similarly, $$v_2=Rv_1-p=R(Rv_0-p)-p=R^2 v_0-Rp-p.$$ By induction, it is not difficult to see that $$v_T=R^T v_0-psum_{t=0}^{T-1}R^t=R^T v_0-pfrac{R^T-1}{R-1}$$ after $T$ months.



                Now, if the debt is to be paid off in $T$ months, then $v_{T}=0$, so that solving for $p$ yields:
                begin{align*}
                0=R^T v_0-pfrac{R^T-1}{R-1},
                end{align*}
                or, after rearrangement: $$boxed{p=dfrac{R^T(R-1)}{R^T-1}v_0}$$
                If you plug in $T=60$, $v_0=100mathord, 000$, and $R=1.03^{1/6}$, then you get a monthly payment of $$1mathord,929mathord .86$.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Feb 8 '14 at 11:47

























                answered Feb 8 '14 at 6:48









                triple_sectriple_sec

                15.8k21852




                15.8k21852























                    3












                    $begingroup$

                    The formula is the amortization or Equated Monthly Payment formula (see also this link):



                    $A = P cfrac{r (1+r)^n}{(1+r)^n - 1}$



                    Without getting into the details of how it is derived, what you need to know is the following:





                    • P is the principal amount borrowed


                    • A is the periodic amortization payment


                    • r is the periodic interest rate divided by 100 (nominal annual interest rate also divided by 12 in case of monthly installments), and


                    • n is the total number of payments (for a 30-year loan with monthly payments n = 30 × 12 = 360)


                    For your example,





                    • P = 100,000


                    • A is what we want to find


                    • r = $cfrac{6}{100 cdot 12}$ = $cfrac{6}{1200}$ = 0.005, but as triple_sec pointed out, the amortization calculator you used says that "interest is compounded semi-annually for fixed interest rates and each payment period for variable interest rates," which means you use this calculation instead: r = ${0.03}^{1/6}$ = $cfrac{6}{1200} approx$ 0.049386


                    • n = 5 years * 12 months/year = 60 months


                    So, we get this:



                    $A = 100000cdotcfrac{0.0049386cdot1.0049386^{60}}{1.0049386^{60}-1}$ = $1,929.86



                    (You would get the same result if you put =PMT(1.03^(1/6)-1, 60, 100000) into a cell in Excel, because it does the same formula I quoted above.)



                    Note: you say "Amortization rate" where I believe you meant "amortization term" (5 years); that matches the calculator and makes more sense in this context.






                    share|cite|improve this answer











                    $endgroup$













                    • $begingroup$
                      The excel formula PMT appears to have special case handling when r = 0 to prevent division by zero, in which case the calculations seems to be A = P / n
                      $endgroup$
                      – Scott Markwell
                      Apr 4 '16 at 22:52
















                    3












                    $begingroup$

                    The formula is the amortization or Equated Monthly Payment formula (see also this link):



                    $A = P cfrac{r (1+r)^n}{(1+r)^n - 1}$



                    Without getting into the details of how it is derived, what you need to know is the following:





                    • P is the principal amount borrowed


                    • A is the periodic amortization payment


                    • r is the periodic interest rate divided by 100 (nominal annual interest rate also divided by 12 in case of monthly installments), and


                    • n is the total number of payments (for a 30-year loan with monthly payments n = 30 × 12 = 360)


                    For your example,





                    • P = 100,000


                    • A is what we want to find


                    • r = $cfrac{6}{100 cdot 12}$ = $cfrac{6}{1200}$ = 0.005, but as triple_sec pointed out, the amortization calculator you used says that "interest is compounded semi-annually for fixed interest rates and each payment period for variable interest rates," which means you use this calculation instead: r = ${0.03}^{1/6}$ = $cfrac{6}{1200} approx$ 0.049386


                    • n = 5 years * 12 months/year = 60 months


                    So, we get this:



                    $A = 100000cdotcfrac{0.0049386cdot1.0049386^{60}}{1.0049386^{60}-1}$ = $1,929.86



                    (You would get the same result if you put =PMT(1.03^(1/6)-1, 60, 100000) into a cell in Excel, because it does the same formula I quoted above.)



                    Note: you say "Amortization rate" where I believe you meant "amortization term" (5 years); that matches the calculator and makes more sense in this context.






                    share|cite|improve this answer











                    $endgroup$













                    • $begingroup$
                      The excel formula PMT appears to have special case handling when r = 0 to prevent division by zero, in which case the calculations seems to be A = P / n
                      $endgroup$
                      – Scott Markwell
                      Apr 4 '16 at 22:52














                    3












                    3








                    3





                    $begingroup$

                    The formula is the amortization or Equated Monthly Payment formula (see also this link):



                    $A = P cfrac{r (1+r)^n}{(1+r)^n - 1}$



                    Without getting into the details of how it is derived, what you need to know is the following:





                    • P is the principal amount borrowed


                    • A is the periodic amortization payment


                    • r is the periodic interest rate divided by 100 (nominal annual interest rate also divided by 12 in case of monthly installments), and


                    • n is the total number of payments (for a 30-year loan with monthly payments n = 30 × 12 = 360)


                    For your example,





                    • P = 100,000


                    • A is what we want to find


                    • r = $cfrac{6}{100 cdot 12}$ = $cfrac{6}{1200}$ = 0.005, but as triple_sec pointed out, the amortization calculator you used says that "interest is compounded semi-annually for fixed interest rates and each payment period for variable interest rates," which means you use this calculation instead: r = ${0.03}^{1/6}$ = $cfrac{6}{1200} approx$ 0.049386


                    • n = 5 years * 12 months/year = 60 months


                    So, we get this:



                    $A = 100000cdotcfrac{0.0049386cdot1.0049386^{60}}{1.0049386^{60}-1}$ = $1,929.86



                    (You would get the same result if you put =PMT(1.03^(1/6)-1, 60, 100000) into a cell in Excel, because it does the same formula I quoted above.)



                    Note: you say "Amortization rate" where I believe you meant "amortization term" (5 years); that matches the calculator and makes more sense in this context.






                    share|cite|improve this answer











                    $endgroup$



                    The formula is the amortization or Equated Monthly Payment formula (see also this link):



                    $A = P cfrac{r (1+r)^n}{(1+r)^n - 1}$



                    Without getting into the details of how it is derived, what you need to know is the following:





                    • P is the principal amount borrowed


                    • A is the periodic amortization payment


                    • r is the periodic interest rate divided by 100 (nominal annual interest rate also divided by 12 in case of monthly installments), and


                    • n is the total number of payments (for a 30-year loan with monthly payments n = 30 × 12 = 360)


                    For your example,





                    • P = 100,000


                    • A is what we want to find


                    • r = $cfrac{6}{100 cdot 12}$ = $cfrac{6}{1200}$ = 0.005, but as triple_sec pointed out, the amortization calculator you used says that "interest is compounded semi-annually for fixed interest rates and each payment period for variable interest rates," which means you use this calculation instead: r = ${0.03}^{1/6}$ = $cfrac{6}{1200} approx$ 0.049386


                    • n = 5 years * 12 months/year = 60 months


                    So, we get this:



                    $A = 100000cdotcfrac{0.0049386cdot1.0049386^{60}}{1.0049386^{60}-1}$ = $1,929.86



                    (You would get the same result if you put =PMT(1.03^(1/6)-1, 60, 100000) into a cell in Excel, because it does the same formula I quoted above.)



                    Note: you say "Amortization rate" where I believe you meant "amortization term" (5 years); that matches the calculator and makes more sense in this context.







                    share|cite|improve this answer














                    share|cite|improve this answer



                    share|cite|improve this answer








                    edited Feb 8 '14 at 7:23

























                    answered Feb 8 '14 at 6:46









                    Ed CottrellEd Cottrell

                    156117




                    156117












                    • $begingroup$
                      The excel formula PMT appears to have special case handling when r = 0 to prevent division by zero, in which case the calculations seems to be A = P / n
                      $endgroup$
                      – Scott Markwell
                      Apr 4 '16 at 22:52


















                    • $begingroup$
                      The excel formula PMT appears to have special case handling when r = 0 to prevent division by zero, in which case the calculations seems to be A = P / n
                      $endgroup$
                      – Scott Markwell
                      Apr 4 '16 at 22:52
















                    $begingroup$
                    The excel formula PMT appears to have special case handling when r = 0 to prevent division by zero, in which case the calculations seems to be A = P / n
                    $endgroup$
                    – Scott Markwell
                    Apr 4 '16 at 22:52




                    $begingroup$
                    The excel formula PMT appears to have special case handling when r = 0 to prevent division by zero, in which case the calculations seems to be A = P / n
                    $endgroup$
                    – Scott Markwell
                    Apr 4 '16 at 22:52


















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