Question about the proof of the Recursiontheorem











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Please have a look at the proof, first of all I don't understand the parts of the proof where one is refering to the Definition of G.



In the inductionbase one Claims that $(1,x)$ is an element of G



In the inductionstep we define $x_{n+1}:= f_n(x_1,..,x_n)$ and claim that $(n+1,x_{n+1})$ is also an element G. Can please someone explain me why these two assertions are true due to the Definition of G?



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  • It's about the existential proof
    – RM777
    Nov 21 at 21:14










  • I would also like to no how the uniqueness is used of $(1,x_1),...,(n,x_n)$ in the inductionstep
    – RM777
    Nov 22 at 14:16

















up vote
0
down vote

favorite












Please have a look at the proof, first of all I don't understand the parts of the proof where one is refering to the Definition of G.



In the inductionbase one Claims that $(1,x)$ is an element of G



In the inductionstep we define $x_{n+1}:= f_n(x_1,..,x_n)$ and claim that $(n+1,x_{n+1})$ is also an element G. Can please someone explain me why these two assertions are true due to the Definition of G?



enter image description here



enter image description here



enter image description here



enter image description here










share|cite|improve this question






















  • It's about the existential proof
    – RM777
    Nov 21 at 21:14










  • I would also like to no how the uniqueness is used of $(1,x_1),...,(n,x_n)$ in the inductionstep
    – RM777
    Nov 22 at 14:16















up vote
0
down vote

favorite









up vote
0
down vote

favorite











Please have a look at the proof, first of all I don't understand the parts of the proof where one is refering to the Definition of G.



In the inductionbase one Claims that $(1,x)$ is an element of G



In the inductionstep we define $x_{n+1}:= f_n(x_1,..,x_n)$ and claim that $(n+1,x_{n+1})$ is also an element G. Can please someone explain me why these two assertions are true due to the Definition of G?



enter image description here



enter image description here



enter image description here



enter image description here










share|cite|improve this question













Please have a look at the proof, first of all I don't understand the parts of the proof where one is refering to the Definition of G.



In the inductionbase one Claims that $(1,x)$ is an element of G



In the inductionstep we define $x_{n+1}:= f_n(x_1,..,x_n)$ and claim that $(n+1,x_{n+1})$ is also an element G. Can please someone explain me why these two assertions are true due to the Definition of G?



enter image description here



enter image description here



enter image description here



enter image description here







algebra-precalculus induction






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share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 21 at 21:06









RM777

1528




1528












  • It's about the existential proof
    – RM777
    Nov 21 at 21:14










  • I would also like to no how the uniqueness is used of $(1,x_1),...,(n,x_n)$ in the inductionstep
    – RM777
    Nov 22 at 14:16




















  • It's about the existential proof
    – RM777
    Nov 21 at 21:14










  • I would also like to no how the uniqueness is used of $(1,x_1),...,(n,x_n)$ in the inductionstep
    – RM777
    Nov 22 at 14:16


















It's about the existential proof
– RM777
Nov 21 at 21:14




It's about the existential proof
– RM777
Nov 21 at 21:14












I would also like to no how the uniqueness is used of $(1,x_1),...,(n,x_n)$ in the inductionstep
– RM777
Nov 22 at 14:16






I would also like to no how the uniqueness is used of $(1,x_1),...,(n,x_n)$ in the inductionstep
– RM777
Nov 22 at 14:16

















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