Find domain of the function $y=frac{1}{sqrt{5+2lfloor -3xrfloor}}$
-1
I'm a starter in learning functions. Would you help me with this?
$$y=frac{1}{sqrt{5+2lfloor -3xrfloor}}$$
Tell me what inequalities i must solve?
calculus functions
edited Nov 25 at 20:21
lulu
39k24677
asked Nov 25 at 20:19
user602338
1567
|
show 3 more comments
-1
I'm a starter in learning functions. Would you help me with this?
$$y=frac{1}{sqrt{5+2lfloor -3xrfloor}}$$
Tell me what inequalities i must solve?
calculus functions
edited Nov 25 at 20:21
lulu
39k24677
asked Nov 25 at 20:19
user602338
1567
4
No problem. So, all you need is $5+2lfloor -3xrfloor>0$.
– lulu
Nov 25 at 20:23
Would you solve it in 3 or 2 lines of an instructing ANSWER please , bro?
– user602338
Nov 25 at 20:24
I'm not going to write out a full solution...but, honestly, it's almost there already. The inequality I wrote before is the same as $lfloor -3x rfloor >-2.5$ and since the floor is always an integer we must have $lfloor -3x rfloor ≥-2$
– lulu
Nov 25 at 20:26
Thanks. Bro. Would you rewrite the title! Sorry i'm a starter here to!
– user602338
Nov 25 at 20:28
I did edit the title (after you confirmed that my expression was what you had intended). Maybe you just need to refresh the screen.
– lulu
Nov 25 at 20:29
|
show 3 more comments
-1
-1
-1
I'm a starter in learning functions. Would you help me with this?
$$y=frac{1}{sqrt{5+2lfloor -3xrfloor}}$$
Tell me what inequalities i must solve?
calculus functions
edited Nov 25 at 20:21
lulu
39k24677
asked Nov 25 at 20:19
user602338
1567
I'm a starter in learning functions. Would you help me with this?
$$y=frac{1}{sqrt{5+2lfloor -3xrfloor}}$$
Tell me what inequalities i must solve?
calculus functions
calculus functions
edited Nov 25 at 20:21
lulu
39k24677
asked Nov 25 at 20:19
user602338
1567
edited Nov 25 at 20:21
lulu
39k24677
asked Nov 25 at 20:19
user602338
1567
edited Nov 25 at 20:21
lulu
39k24677
edited Nov 25 at 20:21
lulu
39k24677
edited Nov 25 at 20:21
lulu
39k24677
39k24677
asked Nov 25 at 20:19
user602338
1567
asked Nov 25 at 20:19
user602338
1567
asked Nov 25 at 20:19
user602338
1567
1567
4
No problem. So, all you need is $5+2lfloor -3xrfloor>0$.
– lulu
Nov 25 at 20:23
Would you solve it in 3 or 2 lines of an instructing ANSWER please , bro?
– user602338
Nov 25 at 20:24
I'm not going to write out a full solution...but, honestly, it's almost there already. The inequality I wrote before is the same as $lfloor -3x rfloor >-2.5$ and since the floor is always an integer we must have $lfloor -3x rfloor ≥-2$
– lulu
Nov 25 at 20:26
Thanks. Bro. Would you rewrite the title! Sorry i'm a starter here to!
– user602338
Nov 25 at 20:28
I did edit the title (after you confirmed that my expression was what you had intended). Maybe you just need to refresh the screen.
– lulu
Nov 25 at 20:29
|
show 3 more comments
4
No problem. So, all you need is $5+2lfloor -3xrfloor>0$.
– lulu
Nov 25 at 20:23
Would you solve it in 3 or 2 lines of an instructing ANSWER please , bro?
– user602338
Nov 25 at 20:24
I'm not going to write out a full solution...but, honestly, it's almost there already. The inequality I wrote before is the same as $lfloor -3x rfloor >-2.5$ and since the floor is always an integer we must have $lfloor -3x rfloor ≥-2$
– lulu
Nov 25 at 20:26
Thanks. Bro. Would you rewrite the title! Sorry i'm a starter here to!
– user602338
Nov 25 at 20:28
I did edit the title (after you confirmed that my expression was what you had intended). Maybe you just need to refresh the screen.
– lulu
Nov 25 at 20:29
4
4
No problem. So, all you need is $5+2lfloor -3xrfloor>0$.
– lulu
Nov 25 at 20:23
No problem. So, all you need is $5+2lfloor -3xrfloor>0$.
– lulu
Nov 25 at 20:23
Would you solve it in 3 or 2 lines of an instructing ANSWER please , bro?
– user602338
Nov 25 at 20:24
Would you solve it in 3 or 2 lines of an instructing ANSWER please , bro?
– user602338
Nov 25 at 20:24
I'm not going to write out a full solution...but, honestly, it's almost there already. The inequality I wrote before is the same as $lfloor -3x rfloor >-2.5$ and since the floor is always an integer we must have $lfloor -3x rfloor ≥-2$
– lulu
Nov 25 at 20:26
I'm not going to write out a full solution...but, honestly, it's almost there already. The inequality I wrote before is the same as $lfloor -3x rfloor >-2.5$ and since the floor is always an integer we must have $lfloor -3x rfloor ≥-2$
– lulu
Nov 25 at 20:26
Thanks. Bro. Would you rewrite the title! Sorry i'm a starter here to!
– user602338
Nov 25 at 20:28
Thanks. Bro. Would you rewrite the title! Sorry i'm a starter here to!
– user602338
Nov 25 at 20:28
I did edit the title (after you confirmed that my expression was what you had intended). Maybe you just need to refresh the screen.
– lulu
Nov 25 at 20:29
I did edit the title (after you confirmed that my expression was what you had intended). Maybe you just need to refresh the screen.
– lulu
Nov 25 at 20:29
|
show 3 more comments
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4
No problem. So, all you need is $5+2lfloor -3xrfloor>0$.
– lulu
Nov 25 at 20:23
Would you solve it in 3 or 2 lines of an instructing ANSWER please , bro?
– user602338
Nov 25 at 20:24
I'm not going to write out a full solution...but, honestly, it's almost there already. The inequality I wrote before is the same as $lfloor -3x rfloor >-2.5$ and since the floor is always an integer we must have $lfloor -3x rfloor ≥-2$
– lulu
Nov 25 at 20:26
Thanks. Bro. Would you rewrite the title! Sorry i'm a starter here to!
– user602338
Nov 25 at 20:28
I did edit the title (after you confirmed that my expression was what you had intended). Maybe you just need to refresh the screen.
– lulu
Nov 25 at 20:29