Integral of squared Hypergeometric Function











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I am trying to integrate the following



$int_{0}^{1} {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



where $minBbb Z$ and $ninBbb Z$ with $m>0$, $ngeq 0$.



(Basically I want to normalise the function). I am getting this as a part of an effort to find some uniform large approximation for a certain associated Legendre polynomial (in case people are wondering whether it is homework).



I know that



$int_{0}^{1} (z(1-z))^m {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



is integrable, under the same conditions, and gives



$frac{n! Gamma (m+1)^2 Gamma (m+n+1) Gamma (2 m+2 n+1)}{2Gamma (m+n+1) Gamma (2 m+n+1) Gamma (2 m+2 n+2)}quad;{_2{F}_1}big(0, 1 + 2 m + 2 n, 2 m + 2 + 2 n, 1big)$.



The above is a table integral from I. S. Gradshteyn and I. M. Ryzhik 8th edition (doesn't appear in the 7th)



I welcome any hints or suggestions.










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  • I can help with the Mathjax integers. Which one do you want, $$m,nin Bbb Z$$ Or $$m,ninBbb N$$
    – clathratus
    Nov 15 at 18:09










  • @clathratus the first one, but isn't that just a normal $Z$ ?
    – ThunderBiggi
    Nov 15 at 21:17








  • 2




    You can see how someone else created a formula by right-clicking on it and selecting "Show Math As > TeX commands". In this case, you well see Bbb Z. the "Bbb" is just an abbreviation for "mathbb", and you will note that the { } are not needed if you are only applying the operation to a single character (though a space is needed to allow it to recognize where the operation name ends and the target begins). "Bbb Z" is the same as "mathbb{Z}".
    – Paul Sinclair
    Nov 16 at 0:24












  • As Paul said, $Bbb Z$ is made by "Bbb Z". Same thing with $Bbb N$: "Bbb N". hell, you could even do $Bbb H$
    – clathratus
    Nov 16 at 0:38










  • Thank you people!
    – ThunderBiggi
    Nov 16 at 9:25

















up vote
0
down vote

favorite












I am trying to integrate the following



$int_{0}^{1} {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



where $minBbb Z$ and $ninBbb Z$ with $m>0$, $ngeq 0$.



(Basically I want to normalise the function). I am getting this as a part of an effort to find some uniform large approximation for a certain associated Legendre polynomial (in case people are wondering whether it is homework).



I know that



$int_{0}^{1} (z(1-z))^m {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



is integrable, under the same conditions, and gives



$frac{n! Gamma (m+1)^2 Gamma (m+n+1) Gamma (2 m+2 n+1)}{2Gamma (m+n+1) Gamma (2 m+n+1) Gamma (2 m+2 n+2)}quad;{_2{F}_1}big(0, 1 + 2 m + 2 n, 2 m + 2 + 2 n, 1big)$.



The above is a table integral from I. S. Gradshteyn and I. M. Ryzhik 8th edition (doesn't appear in the 7th)



I welcome any hints or suggestions.










share|cite|improve this question
























  • I can help with the Mathjax integers. Which one do you want, $$m,nin Bbb Z$$ Or $$m,ninBbb N$$
    – clathratus
    Nov 15 at 18:09










  • @clathratus the first one, but isn't that just a normal $Z$ ?
    – ThunderBiggi
    Nov 15 at 21:17








  • 2




    You can see how someone else created a formula by right-clicking on it and selecting "Show Math As > TeX commands". In this case, you well see Bbb Z. the "Bbb" is just an abbreviation for "mathbb", and you will note that the { } are not needed if you are only applying the operation to a single character (though a space is needed to allow it to recognize where the operation name ends and the target begins). "Bbb Z" is the same as "mathbb{Z}".
    – Paul Sinclair
    Nov 16 at 0:24












  • As Paul said, $Bbb Z$ is made by "Bbb Z". Same thing with $Bbb N$: "Bbb N". hell, you could even do $Bbb H$
    – clathratus
    Nov 16 at 0:38










  • Thank you people!
    – ThunderBiggi
    Nov 16 at 9:25















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I am trying to integrate the following



$int_{0}^{1} {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



where $minBbb Z$ and $ninBbb Z$ with $m>0$, $ngeq 0$.



(Basically I want to normalise the function). I am getting this as a part of an effort to find some uniform large approximation for a certain associated Legendre polynomial (in case people are wondering whether it is homework).



I know that



$int_{0}^{1} (z(1-z))^m {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



is integrable, under the same conditions, and gives



$frac{n! Gamma (m+1)^2 Gamma (m+n+1) Gamma (2 m+2 n+1)}{2Gamma (m+n+1) Gamma (2 m+n+1) Gamma (2 m+2 n+2)}quad;{_2{F}_1}big(0, 1 + 2 m + 2 n, 2 m + 2 + 2 n, 1big)$.



The above is a table integral from I. S. Gradshteyn and I. M. Ryzhik 8th edition (doesn't appear in the 7th)



I welcome any hints or suggestions.










share|cite|improve this question















I am trying to integrate the following



$int_{0}^{1} {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



where $minBbb Z$ and $ninBbb Z$ with $m>0$, $ngeq 0$.



(Basically I want to normalise the function). I am getting this as a part of an effort to find some uniform large approximation for a certain associated Legendre polynomial (in case people are wondering whether it is homework).



I know that



$int_{0}^{1} (z(1-z))^m {_2{F}_1}big(-n,1+2m+n,1+m,1-zbig)^2 dz$,



is integrable, under the same conditions, and gives



$frac{n! Gamma (m+1)^2 Gamma (m+n+1) Gamma (2 m+2 n+1)}{2Gamma (m+n+1) Gamma (2 m+n+1) Gamma (2 m+2 n+2)}quad;{_2{F}_1}big(0, 1 + 2 m + 2 n, 2 m + 2 + 2 n, 1big)$.



The above is a table integral from I. S. Gradshteyn and I. M. Ryzhik 8th edition (doesn't appear in the 7th)



I welcome any hints or suggestions.







integration definite-integrals hypergeometric-function






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share|cite|improve this question













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edited Nov 16 at 9:24

























asked Nov 15 at 17:16









ThunderBiggi

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1356












  • I can help with the Mathjax integers. Which one do you want, $$m,nin Bbb Z$$ Or $$m,ninBbb N$$
    – clathratus
    Nov 15 at 18:09










  • @clathratus the first one, but isn't that just a normal $Z$ ?
    – ThunderBiggi
    Nov 15 at 21:17








  • 2




    You can see how someone else created a formula by right-clicking on it and selecting "Show Math As > TeX commands". In this case, you well see Bbb Z. the "Bbb" is just an abbreviation for "mathbb", and you will note that the { } are not needed if you are only applying the operation to a single character (though a space is needed to allow it to recognize where the operation name ends and the target begins). "Bbb Z" is the same as "mathbb{Z}".
    – Paul Sinclair
    Nov 16 at 0:24












  • As Paul said, $Bbb Z$ is made by "Bbb Z". Same thing with $Bbb N$: "Bbb N". hell, you could even do $Bbb H$
    – clathratus
    Nov 16 at 0:38










  • Thank you people!
    – ThunderBiggi
    Nov 16 at 9:25




















  • I can help with the Mathjax integers. Which one do you want, $$m,nin Bbb Z$$ Or $$m,ninBbb N$$
    – clathratus
    Nov 15 at 18:09










  • @clathratus the first one, but isn't that just a normal $Z$ ?
    – ThunderBiggi
    Nov 15 at 21:17








  • 2




    You can see how someone else created a formula by right-clicking on it and selecting "Show Math As > TeX commands". In this case, you well see Bbb Z. the "Bbb" is just an abbreviation for "mathbb", and you will note that the { } are not needed if you are only applying the operation to a single character (though a space is needed to allow it to recognize where the operation name ends and the target begins). "Bbb Z" is the same as "mathbb{Z}".
    – Paul Sinclair
    Nov 16 at 0:24












  • As Paul said, $Bbb Z$ is made by "Bbb Z". Same thing with $Bbb N$: "Bbb N". hell, you could even do $Bbb H$
    – clathratus
    Nov 16 at 0:38










  • Thank you people!
    – ThunderBiggi
    Nov 16 at 9:25


















I can help with the Mathjax integers. Which one do you want, $$m,nin Bbb Z$$ Or $$m,ninBbb N$$
– clathratus
Nov 15 at 18:09




I can help with the Mathjax integers. Which one do you want, $$m,nin Bbb Z$$ Or $$m,ninBbb N$$
– clathratus
Nov 15 at 18:09












@clathratus the first one, but isn't that just a normal $Z$ ?
– ThunderBiggi
Nov 15 at 21:17






@clathratus the first one, but isn't that just a normal $Z$ ?
– ThunderBiggi
Nov 15 at 21:17






2




2




You can see how someone else created a formula by right-clicking on it and selecting "Show Math As > TeX commands". In this case, you well see Bbb Z. the "Bbb" is just an abbreviation for "mathbb", and you will note that the { } are not needed if you are only applying the operation to a single character (though a space is needed to allow it to recognize where the operation name ends and the target begins). "Bbb Z" is the same as "mathbb{Z}".
– Paul Sinclair
Nov 16 at 0:24






You can see how someone else created a formula by right-clicking on it and selecting "Show Math As > TeX commands". In this case, you well see Bbb Z. the "Bbb" is just an abbreviation for "mathbb", and you will note that the { } are not needed if you are only applying the operation to a single character (though a space is needed to allow it to recognize where the operation name ends and the target begins). "Bbb Z" is the same as "mathbb{Z}".
– Paul Sinclair
Nov 16 at 0:24














As Paul said, $Bbb Z$ is made by "Bbb Z". Same thing with $Bbb N$: "Bbb N". hell, you could even do $Bbb H$
– clathratus
Nov 16 at 0:38




As Paul said, $Bbb Z$ is made by "Bbb Z". Same thing with $Bbb N$: "Bbb N". hell, you could even do $Bbb H$
– clathratus
Nov 16 at 0:38












Thank you people!
– ThunderBiggi
Nov 16 at 9:25






Thank you people!
– ThunderBiggi
Nov 16 at 9:25

















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